# data[].attributes.body
29/6=4r5

so then

# data[].attributes.body
29/6=4 r 5

# data[].attributes.body
29/6 =4r

# data[].attributes.body
29/6=4 groups with remainder of 5

# data[].attributes.body
6x9= 24 6x9 is the closes we can get to 29 that not higher than 29

# data[].attributes.body
29/6=4r 5

# data[].attributes.body
29/6=4 r 5
so if 6 x 4=24 then 5 left =29.
You can use the remaining by rounding the answer up.

# data[].attributes.body
29/6=p for photos and there will be 5 left over which he can divide into 6s

# data[].attributes.body
29 / 6 = 4 r 5

# data[].attributes.body
6X4=24
and 24 is the closest you can get to becuase 6X5 is 30 so you already passed 29.now sense i worked backwords now i know what to do. 24/6=4r5 and now i can add another page for the other left over 5

# data[].attributes.body
29/6=4r5

# data[].attributes.body
29-24=5 and 6*4=24 so 29/6=4 r 5.

# data[].attributes.body
Esteban has 29 photographs. He can only fit 6 photos on each page of his photo album. How many pages must he use to hold all 29 photos?

1. Write an equation
2. Solve the problem and show all work.
3. Explain your answer using complete sentences
4. Upload a picture of your slate/work.