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When you divide a kite in half you get 2 congruent triangles

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You can divide the kite and then get the two congruent triangles!

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When you divide a kite you get to congruent triangles

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If you divide a kite on the bisector diagonal, you get 2 congruent triangles.

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Divide the kite in half and it will make 2 triangles.

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Half of a kite is a triangle so the formula for a kite is related to the formula for a triangle.

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A kite can be divided into triangles, and from there, you find the area of them.

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When you divide up a trapezoid then its made up of triangles. Then you can just find the area of the triangle and add it up.

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all you have to do is multiple half of the inside and you get the whole thing

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When you divide a kite into two it becomes triangles so you find the area for each

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It is just 2 triangles so the fomulas are very sismular

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you can normally take two parts of a kite, triangles and flip[ them makes rectangle.

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To get the area of the kite, you take the length of one diagonal, and multiply it by HALF of the length of the second diagonal, this giving you the area. This is done by making 2 sets of equivalent triangles, and shift 2 triangles to make a rectangle.

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You divide the kite into two different sections then find the area by multiplying the width and height. There are two triangles in a kite.

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when you divide a kite into different sections so then you can find the area for both while two triangles make a kite

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Divide it in 2 and you find the area of the triangles in the trapezoid

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First you have to divide the sections into 2 then combine the pieces. Which basically just makes it 1/2W*H

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When you divide a kite into sections it makes triangles so you find the area of both

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When you divide a kite into sections it makes triangles so you kind find the area of both

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two triangles make one kite so we can find the area of both

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We can find the area for both and two triangles make a kite

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Two triangles make into one kite and you can just find the area of both

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there is two triangles in one kite and we can find the area of both