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This is how I did it

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Thanks to everyone's contributions! :)
The board is now closed.

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Electricity will always flow through the place that uses less volts

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This happens as the electrons flow through the wire with less resistance.
(I used the simulator as I di not bring my electrical components home.)

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The bulb stopped glowing as electricity flowed through the wire in the middle, instead of the wire below. There is no source of energy for the bulb.

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Be careful of redundant wires! The wire added is the diagonal one. This wire is unnecessary, and even creates a short circuit.

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Electrons will always take the path with less resistance. As the bulb has resistance, the electrons will choose the wire with nothing, thus no electricity flows through the bulb, and it will not light up.

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The bulb does not light up as there is an extra wire with no components except the wire and little resistance. It would flow through that path and cause a short circuit, while electricity will not flow through the path with the bulb.

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I added the additional wire between the battery and the bulb. The extra wire directed the current through itself and away from the bulb. Current travels through the path of least resistance and the path with the additional wire only has less resistance than the original path with the bulb.

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The extra added wire in the circuit basically creates a new, shorter circuit. The electricity will flow through this new circuit instead of the one containing the lightbulb and will cause a short circuit, resulting in the lightbulb staying off.

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1. The bulb lights up

2. 1 battery was disconnected

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Emmanuel Goh An Swee                      5 Gen (5-2)

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Emmanuel Goh An Swee                      5 Gen (5-2)

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The basics are that lightbulbs "give off" resistance which electricity does not like. As a result, electricity tries its best to bypass it, which it does by using the extra wire.

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The diagonal wire is the wire that is added. It creates a short circuit and therefore although the bulb's circuit is not touched (It is still there). This is what Mrs Ng taught us in class.

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Above is the solution if one wants to make the bulb shine less brightly, or even not light up.

As electrons flow through the path with the least resistance, the circuit above will become a short circuit as there is no object to convert the electrons to light or heat energy.

Thus, electrons will not flow to the path with the bulb and as a result, the bulb will not light up as there are no electrons to be converted to light energy.

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In this setup, the bulb will not light up.

This is because electricity always flows through the path with the least resistance.

In the circuit with the bulb, there is more resistance, so the electric current does not flow through that path, and thus the bulb does not light up. (I tested it)

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I added the wire to make a short circuit so that instead of the electrons flowing through the wire with the light bulb, they will instead flow through the extra wire as there is less resistance and electricity follows the path of least resistance.

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The electricity from the two batteries is supposed to go to the light bulb, but because of the extra wire, which has NO components in it, letting it have less resistance, the electricity would flow through that wire and not the lightbulb.

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Because there is less resistance in the wire in the middle, more electricity flows through it and less electricity flows through the bottom most wire, thus the light bulb is dimmer.

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A gentle reminder :)

Do include:

1. Your full name & teaching group
2. Photograph of your solution
3. Short explanation of the phenomenon

Happy typing!