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Picture of a cylinder at rest at the top of a ramp.

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Picture of a cylinder at rest at the top of a ramp.

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I used a tomato can from the grocery store and used the mass that was on the label already which was 170g = 0.17kg

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In order to find velocity of the cylinder rolling down, I combined the Big ugly equation and Rotational Kinetic Energy.

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Using a ruler I measured the height (8.1 cm) from bottom to top where the can was at rest.

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Using a ruler I measured the length (3.6 cm) of the side of the can from top to bottom.

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I used a ruler to measure out of the radius of the can and got 2.7 cm.

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Showing free body diagram for a solid cylinder down an inclined plane

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While solving in the beginning I substituted equations such as the Newtons 2nd Law for rotation in order to come up with the equation for radial acceleration. Also I used the forces in the diagram and solved each x-direction and y-direction for the sum of the forces which for radial is  ΣF=mar or acm .

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Since I knew that the cylinder was at rest to begin with, it's safe to assume that any initial velocity here is 0 m/s, with that I used the radial acceleration equation since I've solved for it already and rearranged it to solve for final angular velocity.

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After solving for final angular velocity (ω f = 6.47 rad/s) , I used the 1st angular kinematics equation to solve for time, with my known variables  ω i ,  ω f , α .

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After solving for the time, I used the variables I had and used the 3rd angular kinematics equation to solve for the angular displacement (θ= 0.5 rad).

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While solving for the initial velocity I used my energy skills and used the Big Ugly equation to solve for it.

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Comment on Final Velocity Calculation (Fixed)

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Comment on Final Velocity Calculation (Fixed)

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This is Such a GREAT start. If you use Big Ugly instead of conservation of energy for that calculation, you'll get 40 more points!

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You can also use this for Using Big Ugly (I decided to count it for you because it's so obvious - but usually I want people to label it).

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There are so many calculations you can do with this - just take a look at all the rotational stuff plus the momentum energy stuff and find random things to calculate (I see rotational inertia, rotational KE, KE trans, angular speed...so many!)

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Radial Acceleration Calculation Comments (Fixed)

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Radial Acceleration Calculation Comments (Fixed)

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You use that static friction is equal to mu*normal but that's not the case. See the Physics Ninja video for extra help with this. It might have cancelled in the end but you still need to be able to solve this without making that possibly incorrect assumption :)

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This was so close! But the units were wrong. Fix the units on angle and you've got the points for the next draft.

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Make sure you show where the equation come from that friction equals Ia/r stuff. Add that in the beginning and it'll count!

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oops!  about radial acceleration (Fixed)

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oops!  about radial acceleration (Fixed)

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Oops! I just noticed that you're using radial acceleration in the angular kinematics "alpha" slot. That's not going to work. Oh man! I'm bummed because that affects your theta and other stuff below it...

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I used tangent to find the horizontal part of the ramp, since I knew the angle and the height of the ramp already.

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I used the equation Work done by torque equals torque times the angular displacement in order to solve for the work.

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I didn't expect anybody to sweep the angular motion/rotation unit but you sure did!!!!

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Buoyant Force Calculation and Buoyant force equation with F=0

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Buoyant Force Calculation and Buoyant force equation with F=0

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~6 pts +30 pts

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Since I knew 3 variables already the final velocity, horizontal displacement, and acceleration I used the kinematics 1d equation 2 to solve for initial velocity.

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I combined the big ugly equation and the thermodynamics equation to solve for the final temperature of the ice cube when it comes to rest, and earlier to solve for the work of the friction I used that for my Q since I knew that 50% of the energy dissipated by friction is absorbed. I also solved for final temperature by using the Q= mcT equation from the thermodynamics skills unit.

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Bonus Combo ~25 pts                   Kinematics and Big Ugly solving for same thing 2 different ways.

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Bonus Combo ~25 pts                   Kinematics and Big Ugly solving for same thing 2 different ways.

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In the above photos I solved for initial velocity using the Big ugly equation and also using kinemtics equation and I got the same answer for both.

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In this scenario there is the object floating in the water that is applying a force onto the ground which is the gravity force and the ground is also applying a force back onto the object which is keeping it up and floating the buoyant force.

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In this scenario there is a ice cube that is applying force onto the ground with the force of gravity and the ground is applying force back onto the object with the normal force this shows Newton's 3rd Law that for every action there is an equal and opposite reaction.

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In this scenario there is the cylindrical object that is at rest and acting on the ground due to the force of gravity (which is at an angle due to the ramp and gives the force of gravity mass times gravity constant multiplied by cosine theta) , and the ground is acting upon the object as well giving the normal force therefore creating an equal and opposite reaction proving newton's 3rd law.