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You are provided two different solutions but their identities have been mixed up.

One of the solution contains copper(II) ions.

The other solution contains aluminium ions.

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You are provided two different solutions but their identities have been mixed up.

One of the solution contains iron(II) ions.

The other solution contains iron(III) ions.

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You are provided two different solutions but their identities have been mixed up.

One of the solution contains calcium ions.

The other solution contains zinc ions.

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You are provided two different solutions but their identities have been mixed up.

One of the solution contains zinc ions.

The other solution contains lead(II) ions.

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You are provided two different solutions but their identities have been mixed up.

One of the solution contains ammonium ions.

The other solution contains calcium ions.

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Add aqueous sodium hydroxide for both solutions. The solution that forms light blue precipitate contains copper(II) ions and the solution that forms white precipitate contains aluminium ions.

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Add aqueous sodium hydroxide to both solutions. The solution with iron(II) ions will form a dirty-green precipitate. The solution with iron(III) ions will form a reddish-brown precipitate.

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Add NaOH(aq) to both of the solution, the solution that forms blue precipitate contains copper (II) ions, and the other solution contains aluminium ions

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Add a few drops of NaOH to both solutions. The solution that forms a light-blue precipitate has copper(II) ions while the solution that forms white precipitate has aluminium ions.

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Upon adding aqueous sodium hydroxide, iron(ll) ions forms a dirty green ppt and iron(lll) ions forms a reddish-brown ppt

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Add aqueous sodium hydroxide to both solutions. The solution containing iron(II) ions will form a dirty-green precipitate. The solution containing iron(III) ions will form a reddish-brown precipitate.

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Add NaOH to both solutions.
The solution containing copper ions will produce light blue precipitate.
The solution containing aluminium ions will produce white precipitate.

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Calcium and Zinc have the same result in NaOH where they would form white precipitate, however zinc’s precipitate is soluble in excess NaOH while calcium’s precipitate is insoluble in excess NaOH

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Add aqueous sodium hydroxide to both solutions. The solution with iron(III) will have a reddish brown precipitate, and the solution with iron(II) will have a dirty green precipitate.

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Add excess aqueous sodium hydroxide to both calcium and zinc solutions. The solution with calcium ions will form a white precipitate that is insoluble in excess NaOH. The solution with zinc ions will form a white precipitate that is soluble in excess NaOH.

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Add aq Sodium hydroxide. Reaction with copper (II) ions will turn into a blue precipitate and reaction with aluminium ions will turn into a white precipitate

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Add NaOH in excess to both solutions. The calcium solution will be insoluble in excess  while the zinc solution will be soluble in excess.

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Add NaOH to both solutions.
A dirty green ppt. forms in the solution containing Fe(II) ions without adding excess.
A reddish brown ppt. forms in the solution containing Fe(III) ions without adding excess.

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Add aqueous sodium hydroxide for both solutions. The solution that forms dirty green precipitate contains iron(II) ions and the solution that forms reddish brown precipitate contains iron(III) ions.

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add aqueous ammonia into both solutions. The solution containing aluminium ions will form white ppt upon adding aqueous ammonia while the solution containing copper (II) ions will form light blue ppt upon adding aqueous ammonia.

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Add aqueous sodium hydroxide to both solutions. The solution with iron(II) to form a dirty green precipitate. The solution with iron(III) will form a reddish brown precipitate.

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Add a few drops of aq NaOH to both solutions. The solution with a dirty green precipitate contains Fe2+ ions and the solution with a reddish brown precipitate contains Fe3+ ions

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add aqueous sodium hydroxide, the copper (ii) ions will react to form a light blue precipitate, while the aluminium ions will react to form a white precipitate

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Add excess aq NaOH to both solution, the one that is soluble in excess aq NaOH is zinc, and the other solution that is insoluble in excess aq NaOH is calcium

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Add excess aq NaOH to the solutions. The solution with calcium ions will have white ppt which is insoluble in excess aq NaOH while solution with zinc ions will have white ppt soluble in excess aq NaOH, giving a colourless solution.

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add excess NaOH into a solution. A white precipitate would be formed for calcium and it is insoluble in excess NaOH. while a white precipitate would be formed for zinc and it is soluble in excess aq NaOH to give a colourless solution

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Add aqueous ammonia to both solutions to in excess. White precipitate will form in both solutions. Precipitate that is soluble in excess is the solution containing zinc ions. Solution with insoluble precipitate in excess is lead(II)

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Add aqueous sodium hydroxide to both solutions. The solution with aluminum ions forms white precipitate and the solution with copper (II) ions form light blue precipitate.

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Add aqueous ammonia for both solutions. The solution that has no viable reaction or does not have any precipitate/colourless contains calcium ions and the solution that forms white precipitate contains zinc ions.

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add aqueous sodium hydroxide, the iron (II) ions will react to form a dirty green precipitate, while the iron (III) ions will react to form a reddish brown precipitate

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Add excess aq ammonia. Zinc ions will be soluble and leave a colour less solution. Aluminium ions are insoluble and will leave a white precipitate

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Both do not react with aqueous ammonia, so react with NaOH and the solution that releases pungent gas that turns moist red litmus paper blue is the solution with ammonia ions while the solution that forms insoluble white precipitate contains the calcium ions

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Add aqueous ammonia to both solutions.
The solution containing zinc ions will produce white precipitate that is soluble in excess aqueous ammonia.
The solution containing lead ions will produce white precipitate that is insoluble in excess aqueous ammonia.

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Add sodium hydroxide to both solutions. The solution with ammonium ion, will have no precipitate. The solution with calcium ion will have a white precipitate.

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Add aqueous ammonia to both solutions, the solution that is soluble in excess NH3(aq) is zinc ions. The other solution that is insoluble in excess NH3(aq) is lead 2 ion

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Add aqueous sodium hydroxide. The solution with calcium will form white precipitate while the solution with ammonia ions will not form precipitate.

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Add a few drops of aq NaOH into both solutions. The solution with no precipitate formed contains NH4+ ions and the solution with white precipitate formed contains Ca2+ ions.

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Add NaOH into both solutions.
In the solution containing calcium, a white precipitate will form that is insoluble in excess aq. NaOH.
No precipitate forms in the solution containing NH3. When this solution is heated, colourless and pungent ammonia gas is given off, this gas turns moist red litmus paper blue.

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Add NH3(aq) to both solution, the solution that forms white precipitation is calcium, the other solution will have no reaction is ammonia

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add aqueous ammonia (not in excess) , the calcium ions will not react thus no precipitate will be formed, the zinc ions will react to form a white precipitate

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Add aq. NaOH to both solutions. The solution that contains blue precipitate contains copper(II) ions while the solution that contains white precipitate contains aluminium ions.

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Add aq. NH3 to both solutions, white precipitate is formed in both solutions. Add aq. NH3 in excess to both solutions, the solution where white precipitate dissolves in excess aq. NH3 to form colourless solution contains zinc ions while the solution containing precipitate that remains insoluble contains lead(II) ions.

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add excess NaOH into both solutions. A white ppt would be formed for ca2+ and it is insoluble in excess Solvent while a white ppt would be formed for zn2+ and it is soluble in excess solvent to give a colourless solution.

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Add aqueous ammonia into both solutions. Both will form white precipitate. However, upon adding excess aqueous ammonia, white precipitate in solution containing lead (II) ions remains insoluble while white precipitate in solution containing zinc ions is soluble and would form a colour less solution.

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Add aqueous sodium hydroxide to both solution. The solution that forms a dirty green precipitate contains iron(ll) ions. The solution that forms reddish brown precipitate contains iron(lll) ions.

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Add aqueous sodium hydroxide to both solutions. Calcium ions form a white ppt that is insoluble in excess NaOH, while Ammonium ions does not form any ppt. When the solution is heated, ammonia gas is given off and turns moist red litmus paper blue.

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Add aqueous sodium hydroxide. The solution with copper(II ions will form a light blue precipitate. The solution with aluminium ions forms a white precipitate

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Adding aqueous sodium hydroxide to both solutions will form a white precipitate. However, when an. NaOH is added in excess, white precipitate in the solution containing zinc ions will give a colourless solution while white precipitate in the solution containing calcium ions remains insoluble.

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add sodium sulfate to the solution, the calcium will react to form a precipitate as it is insoluble in sulfates

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Add excess aq. ammonia to both solutions. The solution that is colourless has zinc ions while the solution that has white precipitate formed has lead(II) ions.

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Add excess aqueous ammonia for both solutions. The solution that turns colourless contains zinc ions when in excess and the solution that forms white precipitate when in excess contains lead(II) ions.

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add aqueous ammonia in excess, the lead (II) ions will react and form a white precipitate that is insoluble, while the zinc ions form white precipitate that is soluble

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Add aqueous sodium hydroxide for both solutions. The solution that forms white precipitate contains calcium ions and the solution that is colourless contains ammonium ions.