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Find the midpoint:
(-7,14) (15,9)
-7+15/2 = 8/2= 4
14+9/2= 23/2= 11.5
Answer: (4,11.5)

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A new concept we learned this module, was separating one triangle into three. There would be a small, medium, and large triangle. We would be given some sides on each triangle, and using proportions we would have to find the remaining unknown sides. All three triangles would be similar, thus making the use of proportions an easy way to find the side lengths

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https://www.youtube.com/watch?v=O74LFU4VmlE
In this video, he uses the acronym SohCahToa and explains how to label a right triangle. He also goes through a sample problem and solves. At the end, he also covers some concepts that we have not yet covered in class, but it is a basic video.

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the one across from a given angle

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next to a given angle

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the longest side of a right triangle, opposite the right angle

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Trigonometry are just ratios of similar triangles. They can help you solve missing info in right triangles. You need either: side+angle to get a side
side+side to get and angle

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Sin= opposite/hypotenuse
cos=adjacent/hypotenuse
Tan=opposite/adjacent

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(x1+x2/2, y1+y2/2)
It's purpose is to determine the middle between two sets of points

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A point in the middle

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Look for:
-Supplementary (180)
-Complementary (90)
Corresponding (congruent)
-Alt Int angles (congruent)
-Same side int. (180)
-Vertical (congruent)
-180 in a triangle
-360 in a quadrilateral

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-Using Proportional Sides (similar figures)
-Pythagorean Theorem (a^2+b^2=c^2)

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If the scale factor was 3 then you would copy the length 2 times instead of one for a scale of 2.

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1. Draw a line from the center point to point A and extend the line
2. Measure the line of the center point and A and cope the length so that it will be congruent to AA'
3. Repeat for points B and C