# data[].attributes.body
1. (2+5i)-(-6+i)
8+4i

2. 2i(-6+3i)=-12i+6i^2
-12i+6i^=-12i-6
-6-12i

3. x=4i, -4i

# data[].attributes.body
x^2 + 16 =0
x ^2 = 0-16
x^2=-16
x^2= -16
x^2 = +- 16 -1
x+ =+- 4 -i
(4i , -4i)

# data[].attributes.body
(2i)(6+3i)
(2i+x3i)(6)
(6i,6)

This is a multiplication problem. Use distributive property to get 12i + 6i^2. Then substitute -1 for i^2. 12i + 6(-1) = -6 + 12i

# data[].attributes.body
1.   (2+5i)-(-6+i)
( 2-6)(i-5i)
(4,-4i)

# data[].attributes.body
x^2 + 16 = 0
x^2         = 0-16
x^2        = -16
square root on both sides
x      = +-4     -1
x       = +4i
-4i

# data[].attributes.body
2. (2i) (6+3i)
12i + 6i
18i

When you multiply 2i and 6i you get 12i^2. i^2 = -1. 12i + 6i^2 = 12i + 6(-1) = -6 + 12i

# data[].attributes.body
1. (2+5i) - ( -6+i)
(2+5i) + (6 -i)
(2+6) + ( 5i-i)
8 + 4i

# data[].attributes.body
Write each of the following in the form a + bi

1. (2 + 5i) - (-6 + i)
2. (2i)(6 + 3i) -- Hint: Use Distributive Property

Solve the equation.

3. x2 + 16 = 0