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1)      Set up one test tube containing 2mm of water and three test tubes containing 2mm of hydrogen peroxide.

2)      Place a sample of liver in the first test tube containing water as the solute (tube 1.) This is the control. No reaction should occur.

3)      Place a sample of liver in the first test tube containing hydrogen peroxide (tube 2.) There should be a reaction that creates bubbles and foam.

4)      Place a red hot splint splint above the second test tube containing hydrogen peroxide (tube 3) and no liver sample.) Nothing should happen because H2O2 is non-flammable.

5)      Replicate the test tube from step 3, (hydrogen peroxide + liver sample). After it foams, place a red hot splint above the test tube. The flame should spark in the presence of pure oxygen. (This proves a reaction has occurred and pure oxygen is present.)

6)      Using the final test tube, place a liver sample in 2mm of water. Boil it over a Bunsen burner. Once you have done this add 2mm of hydrogen peroxide to the test tube. No large reaction should occur (you may see a few bubbles, but nothing grand.)

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Catalase, an enzyme found in the liver, is said to be responsible for breaking down H2O2 into O2 and H2O. What reactions occurs when catalase is introduced to H2O2? What happens when introduced to water? What happens when it is denatured?

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5 test tubes

4 liver samples

Hydrogen Peroxide

Water

Wooden Splints

Bunsen Burner

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Catalase will react to H2O2 and create H2O and O2. Catalase when denatured (boiled) will not have the same reaction.

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Examine the effect that catalase has as an enzyme.

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From the findings from the experiment, summarized in the chart above, my hypotheses have been proven correct. The enzyme catalase acts as a catalyst in chemical reactions (like all enzymes) and aided in the reaction of liver and H2O2.

From the results of test tube 2, a reaction between the enzyme catalase and H2O2 occurred, leaving the products oxygen (O2) and water (H2O).

From the results of test tube 4, it further proved that the products of the reaction became H2O and O2 when the red hot splint was placed above the product. The splint creating the flame marked the presence of pure oxygen because O2 is flammable. (This is also why the splint did not flame over tube 3  because H2O2 is non-flammable.)

In trail of tube 5, it showed that catalase is no longer active after having been denatured. (No reaction occurred when H2O2 was introduced after the liver sample had been boiled.)