# data[].attributes.body
a
i 16$
ii 20$
iii 23$
iiii 18.50$
iiiii 24.95$
b: cost of the book=$x+10
c$y=$x+10

# data[].attributes.body
e) 32.5% = 32.5/100
= 32.5 x 10/100 x 10
= 325/1000
= 65/200
= 13/40
325/1000 = 0.325

# data[].attributes.body
c) 1 3/4 = 1 + 3/4
= 100% + (3/4 x 100)%
= 100% + 75%
= 175%

# data[].attributes.body
2) a/ 40 x 3/4 = 30 (kg)
Lilah is 30kg
b/ Abdul = 20kg
20 x 3/4 = 15 (kg)
Lilah is 15kg
Abdul = 60kg
60 x 3/4 = 45 (kg)
Lilah is 45kg
c/ y = 3/4x

# data[].attributes.body
3) a/ ii = 10 + 10 = $20
iii = 10 + 13 = $23
iv = 10 + 8.50 = $18.50
v = 10 + 14.95 = $24.95
b/ Diary cost is $x, then the cost of the book is $(x + 10)
c/ y = x + 10 ($)

# data[].attributes.body
a/ = 10 + 10 = 20$
= 10 + 13 = 23$
= 10 + 8.50 = 18.50$
= 10 + 14.95 = 24.95$

# data[].attributes.body
2= 10 + 10 = $20
3= 10 + 13 = $23
4= 10 + 8.50 = $18.50
5 = 10 + 14.95 = $24.95

# data[].attributes.body
a) 3/4 x 40 = 30
b) Adul : 70
Lilah : 3/4
Answer :  3/4 x 70 = 52.5
C) Y= 3/4 X

# data[].attributes.body
a 30kg
b 1.abdul:100kg
lillah:75kg
2.abdul:80kg
lilah:60kg
c Y=3/4 X

# data[].attributes.body
225%

# data[].attributes.body
125%

# data[].attributes.body
170%

# data[].attributes.body
3.6%=3.6/100
= 3.6x10/100 x 10
=36/1000
= 9/250
9/250=0.036

# data[].attributes.body
0.625
62.5/100

# data[].attributes.body
I 1.5 = 1.5/100
= 1.5 x 10 / 100x10
= 15/1000
= 3/200
= 15/1000
= 0.015
II
1 3/10 = 1 + 3/10
= 100% + ( 3/10 X 100 )%
= 100%+30%
130%
III
a lilah = 30kg
b 80kg adul
lilah 3/4
100 adul
3/4