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Support your answer.

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yeah this limit exists and its limit is 5/4

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Yeah this limit exits and its limit5/4.

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it exists and is 5/4

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THIS LIMIT EXIST AND IS 5/4

# data[].attributes.body
this limit exists and it is 5/4

# data[].attributes.body
this limit exists and it is 5/4

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yes this limit exist and is 5/4

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This limit exist and it's 5/4

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This limit exist an its limit is=5/4

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this limits exist and its 1.25

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This limit is exist is 5/4

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Belyse  my opinion is . This limit exists and is 5/4

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Belyse  my opinion is . This limit exists and is 5/4

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For my opinion the limit exists because its limit is 1.25

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for this I can see that it is exist becouse the lim of it is not un defined thas is my caliculation from my head

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In my opinion the limit exist which if 5/4

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it exist answer is 1.25

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It exist and its limit is 5/4

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Obviously it exists and it's 5/4

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yes this limit exists and its limit is 5/4

# data[].attributes.body
this limits exist and is 5/4

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this limit exist and is 5/4

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Direct substitution here we can not use it

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MY solution is 1.25 trough asking neighbors but direct substitution is IF

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this limit can exist because if x approaches both sides you get 5/4

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Yes it exist . and it is 5/4.

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THE LIMIT EXISTS . FIRST OF ALL DIRECT SUBSTITUTION CAN NOT BUT AFTER FACTORISING NUMERATOR AND SIMPLIFY THE LIMIT BECOME 5/4

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lim⁡x→2x2+x−6x2−4\lim_{x\to2}\frac{x^2+x-6}{x^2-4}x→2lim​x2−4x2+x−6​

Step 1: Factor

x2+x−6=(x+3)(x−2)x^2+x-6=(x+3)(x-2)x2+x−6=(x+3)(x−2) x2−4=(x−2)(x+2)x^2-4=(x-2)(x+2)x2−4=(x−2)(x+2)

Step 2: Cancel x−2x-2x−2

(x+3)(x−2)(x−2)(x+2)=x+3x+2\frac{(x+3)(x-2)}{(x-2)(x+2)}=\frac{x+3}{x+2}(x−2)(x+2)(x+3)(x−2)​=x+2x+3​

Step 3: Substitute x=2x=2x=2

2+32+2=54\frac{2+3}{2+2}=\frac{5}{4}2+22+3​=45​

✅ Answer:

54\boxed{\frac{5}{4}}45​​

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simply this limits does not exist if you substitute directly but if you ask neighbour it can be exist about 5/4

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for my idea this limit is exist because it is 1/5

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Actually when you calculate you can see that this limit it exist and is 5/4

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IT EXIST AND IT'S 5/4

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the limt exist and itis 4/5

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limit exist if you evaluate

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Yes, this limit exists and is 5/4.

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Its exist the answer is 5/4.

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this limits exist and is 5/4 PR EUGENE

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It exist

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THIS LIMITS EXISTS AFTER SIMPLIFY AND IT IS 1.25

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this limit exits and is 5/4

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thefuction exist becouse F(x)=5/4

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The limit exists and is equal to

54five-fourths

𝟓/𝟒

.

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yeah this limit exist and its limit is 5/4 ,simply it's 1.25 . my friends be vigilant to what you are play with .these practices may come in exams soon! elie

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It exist it is5/4