# data[].attributes.body
1)Heat is transferred in three ways, convection. conduction, or radiation. Work is transferred from a system through anything but heat.
2) Work=(Pressure)(Change in volume)
3)They are all related by displacement's need to change volume which creates pressure when volume gets smaller which creates work.
4) V=(2m^2)(,25m)
V=.5m^3
W=(7.5x10^5Pa)(.5m^3)
W=3.75x10^5J
5) E=q+w
115J=q+12J
q=103J
6)E=q/w
50/70
5/7

# data[].attributes.body
1) Heat is transferred through convection, radiation, or conduction. Work transfers from a system through heat.
2) Work= pressure * change in volume
3) They are related because displacement is needed to change volume which creates more or less when volume increases or decreases.
4) V=(2m^2)(0.25m)
V=.50m^3
W=(7.5x10^5 Pa)(0.50m^3)
W=3.75x10^5 J
5)E = q+w
115J = q +12J
q = 103J
6) E = q/w
50/70

# data[].attributes.body
1.) Heat is transferred through convection, conduction, or radiation. Work transfers from a system by any other means but heat.
2.) Work = Pressure * Change in Volume.
3.) They all related by displacement's need to change volume which then creates pressure when volume gets smaller which creates work.
4.) V = (2m^2)(0.25m)
0.5 M^3
(7.5*10^5)(0.5)
W= 3.75 * 10^5
5.) E = Q+W
115J = Q + 12J
Q = 103J
6.) E = Q/W
50/70
5/7

# data[].attributes.body
1. The three ways, convection, conduction, and radiation, are the ways heat is transferred from a system.
2. W=P*change in V
3. The change in displacement changes the volume and can increase pressure, resulting in different levels of work.
4.  7.5*10^5*.5m^3=3.75*10^5
5.Change of E=q+w
115=q+12
q=103j
6. 5/7=71.4%

# data[].attributes.body
1) Heat is transferred in three ways, convection, conduction, or radiation. It transfers from a object with a higher thermal energy to an object with a lower thermal energy.
2) Work=(Pressure)(Change in volume)
3) The work done by a gas is equal to the negative external pressure times the change in velocity.  The displaced pressure then is showed by the change in volume.
4) V=(2m^2)(0.25m)
V=.50m^3
W=(7.5x10^5 Pa)(0.50m^3)
W=3.75x10^5 J
5)E = q+w
115J = q +12J
q = 103J
6) E = q/w
50/70
5/7

# data[].attributes.body
1.  Heat is transferred through convention, radiation, or conduction. Work is transferred from a system through anything but for heat.
2.  W = L2 (Integral) L1 (P*A) dL
3. The work of gas is pressure multiplied by delta volume. The volume is then displaced by pressure.
4. W=7.5*10^5 * 0.25 (integral)0(2)= 375000 Pa*m
5. chg U= Q-W
chg U= internal energy
Q=heat added to system
W=work done by system
6. W/Q=Efficiency
50/30=5/3 efficiency

# data[].attributes.body
1.) Heat is transferred through convection, conduction, or radiation. Work transfers from a system by any other means but heat.
2.) Work = pressure * change in volume.
3.) They all relate because displacement is needed to change volume which then creates pressure when volume gets smaller which creates work.
4.) V = (2m^2)(.25m)
.5 M^3
(7.5*10^5)(.5)
W= 3.75 * 10^5
5.) E = q+w
115J = q +12J
q = 103J
6.) E = q/w
50/70
5/7

# data[].attributes.body
1.Heat is transferred from a system when coming in contact with an object that has lower thermal energy(heat). This is done through conduction. Work is transferred from a system through any form of energy that is not heat.
2)(  W=P*ΔV ) Where P is the pressure and  ΔV is the change in volume.
3.  Displacement is the form of work done on the object.  The change in volume relates to the displaced pressure.  The volume is displaced by the pressure.
4. Change in V = (2m^2)*(.25m) = .5m^3
W= (7.5*10^5Pa)(.5m^3)= 3.75*10^5 J
5. ΔU = Q-W
U= internal energy = 115J
Q= heat = ?
W=work = 12J
115J = Q- 12J
Q= 127J
6.  Efficiency = W/Q
50J/30J = 5/3 = 167% efficiency

# data[].attributes.body
1. Heat transfers from a system through thermal energy and the differences in temperature. Work is the transfer of energy through any means other than heat.
2. W=P*∆V
P=Pressure
∆V= Change in volume
3. Pressure and volume are how the gas changes. This causes displacement on objects, such as a piston. In a piston, when pressure and volume increase, the piston moves, and thus work is done. If there is no change in volume, there can be no displacement.
4. ∆V=(2m^2)(0.25m)
∆V=.50m^3
W=(7.5x10^5 Pa)(0.50m^3)
W=3.75x10^5 J
5. ∆E=q+w
115J=q+12J
q=103J
6. Efficiency=Q/W
Efficiency=50J/70J
Efficiency=5/7 or 71.4%

# data[].attributes.body
1. Energy eschanged between thermodynamic interaction is reffered to as heat;while work, is a transfer of energy by any process except heat. Heat cannot be completely convereted to heat, but work can be converted to heat. *Can increase low internal energy to high internal energy by heating it. Energy system can change due to work, while energy transfer is due to heat.
2. W= L2(integral)L1(P*A)*dL
A-Area, P-Pressure,V-Volume
3. Work done by a gas is equal to the negative external pressure multiplied by the change in velocity. Change in volume (Vf-Vi), in turn reflects the the displaced pressure.
4.W=(7.5*10^5)*(.25m(integral)0(2)dL=375000Pa+m
5.(triangle-change of)U=Q-W
u-internal energy
q-heat added to the system
w-work done by system
115J+12J=127J
6.50/30=1.666 efficiency
(W/Q-efficiency forumla)

# data[].attributes.body
1. It is transferred through convention, radiation, or conduction. Work is transferred by anything except heat.
2. W=L2(Integral)L1(P*A)*dL
A=area
P=pressure
V=volume
3. Work of gas is pressure multiplied by change in volume. Volume then is displaced by pressure.
4. (7.5*10^5)(.25m(integral)0(2)dl)
W=375000 Pa*m
5. 12J+115J=127J
6. 50/30 = 5/3 efficiency

# data[].attributes.body
1.) When an object with high thermal energy comes into contact with an object with lower thermal energy, heat is transfer by conduction. Work is transferred through heat.
2.) W = L2 (Integral) L1 (P*A) dL
3.)Volume is then displaced by pressure .Pressure is multiplied by delta volume.
4.) W = (7.5 x 10^5)[0.25(integral)0 (2) dL]
= 375000 Pa*m
5.) delta U=Q - W
Q = deltaU + Q
=115J + 12J = 127J
6.) W / Q = efficiency
50 / 30 = 5 / 3

# data[].attributes.body
1. Heat is transferred through convention, radiation, or conduction. Work is transferred by anything except heat, between a system and its surroundings.
2. W=L2(Integral)L1(P*A)dL
A=area
P=pressure
V=volume
3. Work of gas is the result of the pressure multiplied by change in volume. Volume is displaced by pressure.
4. (7.5*10^5)[0.25(Integral)0(2) dL]=W=375000 Pa*m
5. deltaU=Q-W
Q=deltaU+Q=115J + 12J=127J
6. W/Q=efficiency
50/30=5/3

# data[].attributes.body
1. Heat can be transferred by convention, radiation, or conduction.
Work is transferred through any type of energy besides heat. Furthermore, work is transferred between a system and its surroundings.
2.W=L2(Integral)L1(P * A) * dL
where A is area, P is pressure, and V is volume.
3. Work of gas is when pressure is multiplied by delta volume. Volume is then displaced by pressure.
4.
(7.5 * 10^5)
((.25m(integral)0 (2)dL))= W
W= 375000 Pa* m
5.chgU=Q-W
12J+115J=127J
6.W/Q=Efficiency
50/30=5/3
5/3 efficiency

# data[].attributes.body
1. Heat is the transfer of energy, usually changing from hot to cold. Work is the transfer of any type of energy other than heat.
2. W=L2(integral)L1(P*A)dL
3.
4. W=7.5*10^5 * 0.25 (integral)0(2)= 375000 Pa*m
5. chgU= Q-W
Q =115 J+12 J=127 J
6. W/Q=Efficiency
50/30=5/3 efficiency

# data[].attributes.body
As a result of the pressure being increased in the closed area the volume becomes displaced.

4)2m^2 .25m
7.5x10^5 Pa
W=(7.5x10^5)(.25m(integral)0(2)dL)=375000Pa*m

5)12J+115J=127J transferred as heat

6) W/Q=Efficiency
50J/30J=5/3 or
1.67

# data[].attributes.body
1) Heat is transferred by conduction, convention, and or radiation. Heat transfers by conduction occurs when an object with high thermal energy comes into contact with an object with low thermal energy.
2) W=L2(integral)L1(P*A)dL
A: Area
W: P(chg V)
P: Pressure
V: Volume
3) The work of gas is pressure multiplied by a change in volume. Volume is displaced when pressure is activated.
4) W= (7.5 x 10^5) (.25(integral)0(2)dL)= 375000 Pa*m
5) chg U= Q-W
chg U= internal energy
Q=heat added to system
W=work done by system
Q=115 J+12 J=127 J
6) W/Q=Efficiency
50/30=5/3 efficiency

# data[].attributes.body
1)Heat is transferred by conduction from high thermal energy to low thermal energy aka thermal interaction. Work is transferred by any other system than heat but can be converted to heat. This includes mechanical, electrical, and gravitational work.

2)W=L2(integral)L1(P*A)*dL
A=Area
P=pressure
V=volume
d=diameter

3)Pressure is multiplied by a change in volume

# data[].attributes.body
1)Heat transfer from hot to cold and is transferred by conduction. Work is the transfer of energy and heat.
2)W=L2*L1 (P*A)dL
A=area, D=diameter
3)When pressure is changed, the volume either increases or decreases. With that the value of displacement changes.
4)W=7.5*10^5 * 0.25 (intergral)0(2)= 375000 Pa*m
6)W/Q=effiency
50/30=5/3

# data[].attributes.body
1) Heat transfers by a change of temperature and only exists as it crosses the system boundary. Heat ALWAYS transfers from hot to cold.

Work is an energy interaction between the system and its surroundings. Positive Work: work transferred out. Negative Work: work transferred in.

2) W = L2(integral)L1 (P*A)dL
A = area; L = length
W = P(chg V)
P = pressure
V = volume

3) The Work of Gas is pressure multiplied by a change in volume. Pressure displaces volume when activated. That's why we have a final and initial volume.

4) W = (7.5 x 10^5)[0.25(integral)0 (2) dL] =
375000 Pa*m

5) chg  U = Q-W
chg U = internal energy
Q = heat added to system
W = work done by system
Q = 115 J + 12 J = 127 J

6) W/Q = Efficiency
50/ 30 = 5/3 efficiency.