# data[].attributes.headline
muhammad syamim bin omar farook AE150086

# data[].attributes.subject
muhammad syamim bin omar farook AE150086

# data[].attributes.body
1
A=1
B=10+5j
C=0
D=1

2
Vs = ( 155.596 + 200.5j ) v

# data[].attributes.body
question 1
A=1
B=10+5j
C=0
D=1

question 2
Vs = ( 155.596 + 200.5j ) v

# data[].attributes.body
Question 1:
* Short Line
1. A=1
2.B=10 + 5J
3. C=0
4. D=1

Question 2:
Vs =(155.596 +j200.5j) v

# data[].attributes.body
QUESTION 1

1.     A=1

2.     B=10 + 5j

3.     C=0

4.     D=1

QUESTION 2
Vs = (155.596 + j
200.476) V

# data[].attributes.body
1) A=1 B=10+5j C=0 D =1
2) Vs =(155.6+200.5j) V

# data[].attributes.body
DE150052

# data[].attributes.body
Q1
A=1, B=10+j5, C=0, D=2

Q2
Vs(LL)= (216.09+j45593.12)kV

# data[].attributes.body
DE150061
1) A=D=1
B= 10 +j5
C= 0
2) 156.6 + j200.5

# data[].attributes.body
Q1. A=1
B=10+j5
C=0
D=1
Q2. Vs(LL) = (206.35 + j1372.52)kV
= 1387.94kV < 81.45

# data[].attributes.body
Q1. For short line,
A =1; B=10+ j5; C=0; D=1
Q2. Vs(LL) = (206.35+j1372.5) kV

# data[].attributes.body
Q1) A=1, B=10+j5, C=0, D=1
Q2) Vs = (155.6 + j200.5)V

# data[].attributes.body
Q1
A =1
B = 10 +5j
C = 0
D = 1

Q2
Vs = 155.5959 + j200.4759

# data[].attributes.body
Q1. For ABCD constant at shortline trans, ACD is same which is
A = 1
C =0
D=1
B= Z = 10+5j

Q2
Vs= 155.5959 + 200.4759j

# data[].attributes.body
Q1 A=1
B=10+5j
C=0
D=1
Q2
Vs= (155.596+200.476j)V

# data[].attributes.body
Question 1.A=1
B=10+5j
C=0
D=1
Question 2.
Vs= (155.596+200.476j)V

# data[].attributes.body
Q1 A=1
B=10+5j
C=0
D=1
Q2
Vs= (155.596+200.476j)

# data[].attributes.body
1) A=1 B=10+5j C=0 D=1
2)Vs= (155.596+200.476j)

# data[].attributes.body
Allan Yong
Ce150123

# data[].attributes.body
QUESTION 1:
A= 1
B=10+5j
C=0
D=1

QUESTION 2:
Vs(LN)= (155.596 + j200.476) V
Vs (LL)= (269.523+ j347.217) V

# data[].attributes.body
AE150012

Question 2:
Vs(L-L)=155.6+j200.48)V

Question 1:
A=1, B=10+j5, C=0, D=1

# data[].attributes.body
QUESTION 1

1.     A=1

2.     B=10 + 5j

3.     C=0

4.     D=1

QUESTION 2
Vs = (155.596 + j
200.476) V

# data[].attributes.body
Dr,for the chapter 5 tutorial,if we do it in group , we have to submit only 1 copy each group ist? And the group members we should follow our project group as well ?

# data[].attributes.body
Q1.
A = 1
B = 10+5j
C = 0
D =1

Q2.
Vs(L-L) = (155.6 + 200.48j)V

# data[].attributes.headline
MOHAMAD NAZRUL IKMAL BIN JAMALUDDIN CE150113

# data[].attributes.subject
MOHAMAD NAZRUL IKMAL BIN JAMALUDDIN CE150113

# data[].attributes.body
1. A=1
B=(10+5j)
C=0
D=1

2. Vs(L-L) = (155.6 + 200.5j) V

# data[].attributes.headline
WAN ABDUL LATIF BIN WAN KHAIDIR CE150149

# data[].attributes.subject
WAN ABDUL LATIF BIN WAN KHAIDIR CE150149

# data[].attributes.body
ANS:
1. A=1 ,B=(10+j5) ,C=0 ,D=1
2. Vs(L-L)=( 155.5959 + 200.4759j )V

# data[].attributes.body
Question 1.

A.     1

B.     10+5j

C.     0

D.     1

Question 2.

VS = (155.595 + j200.476) V

# data[].attributes.headline
NUR IZNI FATIN BT ABDUL RAHMAN (AE150192)

# data[].attributes.subject
NUR IZNI FATIN BT ABDUL RAHMAN (AE150192)

# data[].attributes.body
Answer: Question 1
A=1
B=10+5j
C=0
D=1

Question 2
Vs(L-L)= (155.6+200.5j)V

# data[].attributes.headline
Thank you for the answers.. For those who have not post the answer yet, I'll give you time until 5 pm. :) 

# data[].attributes.subject
Thank you for the answers.. For those who have not post the answer yet, I'll give you time until 5 pm. :) 

# data[].attributes.body
(CE150087)

# data[].attributes.body
Please study chapter 5 which I've uploaded in blendspace. There are videos as well coming to be uploaded by this evening. Internet is so slow makes them so long to appear in blendspace.

Here is your tutorial for Chapter 5. You can do them in groups and submit to me next week in class.

# data[].attributes.body
MUHAMMAD AZAM BIN JAMALUDDIN

(CE150218)

ANSWER

QUESTION 1

1.     A=1

2.     B=10 + 5j

3.     C=0

4.     D=1

QUESTION 2

Vs = (155.596 + j
200.476) V

# data[].attributes.body
Muhammad Firdauz Bin Adam CE150193

Question 1.

A.     1

B.     10+5j

C.     0

D.     1

Question 2.

VS = (155.595 + j200.476) V

# data[].attributes.headline
NOOR HIDAYATUL AINI BT MOHD DAHARI (CE150140

# data[].attributes.subject
NOOR HIDAYATUL AINI BT MOHD DAHARI (CE150140

# data[].attributes.body
Question 1:
A:1, B=Z:10+j5, C:0, D:1

Question 2:
Vs=(155.596+j200.476)V
@253.77<52.18V

# data[].attributes.body
1)  A= 1 , B=Z=10+j5 , C=0,  D=1
2)  Vs=(155.5959+j200.4759)V

# data[].attributes.body
1. A=1
B=10+5j
C=0
D=1

2. Vs= ( 155.6 + 200.5j ) V

# data[].attributes.body
QUESTION 1
A=1
B=10+5j
C=0
D=1
QUESTION 2
Vs=(155.596+j200.476)V

# data[].attributes.body
1. A=1,B=10+j5, C=0,D=1
2. Vs=155.6+j200.5  V

# data[].attributes.body
Q1
A=1
B=10+j5
C=0
D=1

Q2
Vs=(155.5959+j200.476)V

# data[].attributes.body
Question 1:
A=1
B=10+j5
C=0
D=1

Question 2:
Vs= (155.5959+j200.48)V

# data[].attributes.body
1. A=1, B=10+j5, C=0, D=1
2. Vs=(155.5959+j200.4759)V

# data[].attributes.body
Ans 1 :
A = 1
B = 10+5j
C = 0
D = 1

Ans 2 :
Vs = (155.596 + j200.476) V

# data[].attributes.body
1.A=1 , B=10+j5 , C=0 , D=1
2.Vs=(155.5959+j200.4759)V

# data[].attributes.body
AE150178
1. A=1  B=10+j5  C=0 D=1
2. Vs=(155.596+j200.476)v

# data[].attributes.headline
NUR AMIRA ELYANIE BINTI SARMAN (AE150163)

# data[].attributes.subject
NUR AMIRA ELYANIE BINTI SARMAN (AE150163)

# data[].attributes.body
1. A= 1
B=10+j5
C= 0
D =1

2. Vs = ( 155.60 + j200.48) V

# data[].attributes.body
ANSWER :
Q1. A=1, B=10+j5, C=0, D=1
Q2. Vs(L-L)=(155.5959+j200.4759)V

# data[].attributes.body
1. A=1
B=10+j5
C=0
D=1

2. Vs = (155.5959 + j200.4759 ) V

# data[].attributes.body
Answer:
Q1) A=1, B=(10+j5), C=0, D=1

Q2) Vs= (155.60+j200.48)V

# data[].attributes.body
Answer :-
Q1)
A=1
B=(10+5j)
C=0
D=1

Q2)
Vs=(155.5959+j200.48)V

# data[].attributes.body
1)A = 1,
B = 10+5j ,
C = 0 ,
D = 1

2) Vs = (155.596 + 200.476j) V

# data[].attributes.body
Q1. A=1 , B=10+5j , C=0 , D=1
Q2. Vs=(155.6+200.5j)V

# data[].attributes.body
1. A=1 B=(10+5j) C=0 D=1
2. Vs = (155.5959 + 200.4759j ) V

# data[].attributes.headline
Nurhazwani Nabilah Binti Abdul Halim (CE150023

# data[].attributes.subject
Nurhazwani Nabilah Binti Abdul Halim (CE150023

# data[].attributes.body
Answer :
Q1) A=1
B =10 + j5
C = 0
D = 1

Q2) VS = 155.6 + j200.5

# data[].attributes.body
Answer :-
Q1)
A=1
B=(10+5j)
C=0
D=1

Q2)
Vs=(155.5959+j200.48)V

# data[].attributes.headline
NUR AIN BAIZURA BINTI BAHARUDIN (CE150127)

# data[].attributes.subject
NUR AIN BAIZURA BINTI BAHARUDIN (CE150127)

# data[].attributes.body
ANSWER :
1. A = 1, B = 10+5j , C = 0 , D = 1

2. Vs = (155.596 + j200.476) V

# data[].attributes.headline
NURUL ALIA FATIN BINTI REDZOAN (CE150103)

# data[].attributes.subject
NURUL ALIA FATIN BINTI REDZOAN (CE150103)

# data[].attributes.body
ANSWER:
Q1)
A = 1
B = 10+5j
C = 0
D = 1

Q2) Vs = ( 155.6 + 200.5j ) V

# data[].attributes.headline
NurAinul Izzati Bt Mohd Hafizin (AE150198)

# data[].attributes.subject
NurAinul Izzati Bt Mohd Hafizin (AE150198)

# data[].attributes.body
Ans :
Q1)
A=1
B=10+j5
C=0
D=1
Q2)
Vs=(155.6+j200.44)V

# data[].attributes.body
Answer :
Q1) A = 1 ,
B = (10+j5),
C = 0 ,
D = 1

Q2) Vs= (155.596 + j200.476)V

# data[].attributes.body
ANS: 1) A=1
B=(10+5j)
C=0
D=1

# data[].attributes.body
1) A=1
B=10+5j
C=0
D=1
2) Vs= ( 155.6 + 200.5j ) V

# data[].attributes.body
1. A=1 B=(10+5j) C=0 D=1
2. Vs = (155.5959 + 200.4759j ) V

# data[].attributes.headline
MUHAMMAD AMAR HAZWAN BIN HISHAM (DE150024

# data[].attributes.subject
MUHAMMAD AMAR HAZWAN BIN HISHAM (DE150024

# data[].attributes.body
Answer question 1. A=1, B=10+J5, C=0, D= 1
Answer question 2. VS9(ln) 155.596+200.476j

# data[].attributes.body
1. A= 1
B = 10+j5
C =0
D= 1

2. Vs= 155.6+ j200.5

# data[].attributes.body
ANS: 1) A = 1
B = (10+j5)
C= 0
D = 1
2) Vs =(155.6 + j200.5) V

# data[].attributes.body
ANSWER
Q1)
A = 1
B = 10+5j
C = 0
D = 1

Q2) Vs = ( 155.6 + 200.5j ) V

# data[].attributes.body
ANS: 1) A=1
B=(10+5j)
C=0
D=1
2)Vs(LN)= ( 155.5959 +
200.4759j ) V

# data[].attributes.body
who's in ? you can discuss with friends but please post the answer by each name

# data[].attributes.body
Dear All, for this week's lesson, please try to find the solution of the following questions. Your posted answer will be recorded as your attendance.

1. Calculate the ABCD constant for transmission line model that is 50 km long and operates at 50 Hz. Series resistance and inductance of the transmission line is 0.2 W/km and 0.3183 mH/km.

2. A 220 kV, 200 MVA and 50 Hz, three-phase transmission line is 150 km long completely transposed transmission line has the following positive-sequence impedance and admittance:

r = 0.11 Ω/km

x = 0.90 Ω/km

y = 5.0 ´ 10-6 S/km

Given the voltage at the receiving end of the transmission line is 200 kV, calculate the sending end line to line voltage if the transmission line is supplying rated apparent power at unity power factor.

# data[].attributes.body
Answer: 1) A = 1, B = (10+5j), C = 0, D = 1

2) Vs(LL) = (155.5959 + 200.4759j) V