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1AgNO ₃  +1 NaBr  --->  1NaNO ₃  +  1AgBr
2KI  +  1Pb(NO ₃)₂  ---> 1PbI ₂  +  2KNO 3
2Al(OH)₃  +  3H ₂ SO ₄--->1Al ₂(SO ₄)₃  + 6H ₂ O
1CaCl 2  +  1Na ₂ SO ₄  ---> 1CaSO ₄  + 2NaCl
1MgCl ₂  +  2NH ₄ OH  --->1Mg(OH)₂  +  2NH ₄ Cl
these chemical equations  are all double replacement,  because if you look at the last question MgCl both switched places in the final products all the equations switch both the elements around to make a new product in the final product.

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3H ₂ CO ₃ +  2Al  --->  3H 2  + 1Al ₂(CO ₃)3
2Al  + 1Fe ₂ O ₃  ---> 2Fe  +  1Al ₂ O 3
1Ca  +  2HCl  ---> 1CaCl ₂  +  1H 2
1Cl ₂  + 1KI  --->  1KCl  +  1I 2
1C ₆ H ₁₂  +  9O 2  --->6CO ₂  +  6H ₂ O
these are all single replacement, because if you look at the last chemical equation you can see that hydrogen switches places

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1MgCO 3--->  1MgO  + 1CO 2
2NO ₂ --->  2O ₂  + 1N ₂

1Ba(OH)₂  --->1BaO  +  1H ₂ O
2KClO ₃  --->  2KCl  +  3O 2
2HgO  --->  2Hg  + 1O 2
these chemical equations all go into decomposition because, all equations start out as one compound then separate into two compounds (elements) this is similar to synthesis but in reverse.

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1P ₄  +  3O ₂  -->   2P ₂ O 3
2NH ₃  +  1H ₂ SO ₄  --> 1(NH ₄)₂ SO 4
1SO ₂  +  1H ₂ O  --->  1H ₂ SO 3
1Li ₂ O  +  1CO ₂  --->  1Li ₂ CO 3
2C ₅ H ₅  +  1Fe  --->  1Fe(C ₅ H ₅)2
A + B -> AB (synthesis)
All of these chemical equations belong in the synthesis category because all of these equations have started out separated and the end result was one product.

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1C ₂ H ₄  +  3O ₂-->  2CO ₂  +  2H ₂ O
2CH ₃ OH  +  3O 2  --->  2CO ₂  +  4H ₂ O
1C ₂ H ₅ OH  +  3O 2  --->  2CO ₂  +  3H ₂ O
1Cu ₂ SO ₄  +  1Zn  -->  2Cu  + 1ZnSO 4
1C ₅ H ₈  +  7O 2  --->  5CO ₂  +  4H ₂ O
As the lists states, we are interested in combustion reactions for two opposite reasons. Sometimes we want to speed it up and sometimes slow it down.
Hydrocarbon + oxygen -> CO ₂ + H ₂ O
(combustion/oxidation)