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1. 8+41
2. -6+12i
4i and -41

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For the multiplication problem, when you distribute you get 12i + 6i^2. i^2 = -1 so 12i + 6(-1) = -6 + 12i

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Cesar
1. 8+41
2. -6+12i
3. 4i & -41

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1. 8+41
2. -6+12i
3. 4i and -4i

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For Question 2, when you distribute you get: 12i + 6i^2. i^2 = -1 so = 12i + 6(-1) = -6 + 12i

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Write each of the following in the form a + bi

1. (2 + 5i) - (-6 + i)
2. (2i)(6 + 3i) -- Hint: Use Distributive Property

Solve the equation.

3. x2 + 16 = 0