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a)I have learnt that there are two groups in the  4 operations. The first group consists of 'addition' and 'subtraction',while the second group consists of 'multiplication' and 'division' .We should always start from the left to the right,unless the is a mixture of group 1 and group 2 .If there is the (body guards),we must give way to the body guards and start doing with the body guards first,then,followed by group 2 and last,group 1.

b)4+3-(2-1)+49
=4+3-1+49
=7-1+49
=6+49
=55

Ans:55

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a)I have learnt that there are two groups of order of operations.Group 1 is addition and subtraction,Group 2 is multiplication and division.We must give 'priority' to group 2 and always start from left to right.There are also brackets(a.k.a bodyguards).We need to do the question in the brackets first then group 2 and 1.

b)(5x3)-10+50
=15-10+50
=5+50
=55

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a) I have learntthat they are two groups in order of operations.group 1 consist of addition and subtraction while group 2 consist of multiplication and division.We must start from left to right if there is only one group in the equation.If there is group 1 and 2 both, then we need to start with group 2.I also learnt how to use brakets.We need to start with the brackets, followed by group 2 and 1.

b)(5+4)x2-8
=9x2-8
=18-8
=10

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b)10×13-2÷2+1
=130-2÷2+1
=130-1+1
=129+1
=130

The Answer Is 130

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a)I have learnt that there are two groups, group 1 and group 2. Group 1 has Addition and Subtraction while group 2 has Multiplication and Division .You must always start from left to right unless there is group 2 and you must do it first.If there are brackets, you should do the ones in the bracket followed by group 2 and group 1.

b) 34 x 4 +(45-27) =
34 x 4 + 18
= 136 + 18
= 154

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I have learnt that there are 2 groups. There is Addition and Subtraction in Group 1 and Multiplication and division in group 2.Always start from the left to right if only group 1 or 2 is shown ( Meaning if one group is shown the other cannot appear).If both groups appear group 2 will take priority and you must always start with group two then proceeding to group 1. If there are brackets then the brackets will be the one to start with.Then following by group 2 and then group 1.

Example.
(9+7)/2x9-1
=16/2x9-1
=8x9-1
=72-1
=71 <---A

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a)We have learnt that there two groups.Group 1 is addition & subtraction and group two is multiplication & division.If there is grp 2 , we have to do it first,but if there is ' bodyguard' (or brackets), then we have to do that sum first.

5 x 6 - (26 + 6)÷4
=5 x 6 - 32 ÷ 4
=30 - 32 ÷ 4
=30 - 8
=22

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a)I have learnt that  in the order of operations, there are two groups- grp 1 and 2. group 1 consists of subtraction and addition.group 2 consists of multiplication and division. If there is  group 1 and 2 only,  you have to do group 2 first then only group 1.there are also "bodyguards" AKA brackets. If there are all three groups (grp 1, 2 and the bodyguards), you have to do the number statement inside the brackets first then you do grp 1 and then grp 2.

b)10 - 3 + 8 x (6 ÷ 3) =
=10 - 3 + 8 x 18
=10 - 3 + 144
=7 + 144
=151

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a) I've learnt order of operations . In order of operations I have learnt that there are two groups . In group one there is plus and minus and in group two, there is multiply and divide.
b) (5+2)+6+7x6
=7+6+7x6
=13+42
=55

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a)I've learn't that there are two groups in order of operations.Group 1 consists of plus and minus.Group 2 consists of multiply and divide.If the number sentence consists of only group 1 or group 2, we should always solve the question from left to right.But if the question consists of groups 1 and 2, then do the operations of group 2 first,then you do the rest from left to right.But if the    sum has brackets involved in it, then we have to do the operations whether their from group 1 or group 2
b)389+(5000/50)+619x4-64
=389+100+619x4-64
=389+100+2476-64
=489+2476-64
=2965-64
=2901

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a)I have learnt how to do order of operations.There are two groups of operations. Group 1 consists of + and -. Group 2 consists of x and /. If there is only one group, then do from left to right. If there is a mixture of groups, then do the operations of group two first, then do the rest from left to right. Most important, if there are brackets, then do the operations in brackets.
b)(9568+22)/10x7-63
=9590/10x7-63
=959x7-63
=6713-63
=6650

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a)I have learnt that in there are two groups.Group 1 has plus and minus while group 2 has multiply and divide.If the number sentence only consist of only group 1 or group 2, we should always do the sum from the left to the right.But if the sum consists of groups 1 and 2, group 2 will always take priority. Means that we should always do group 2 first.If the sum involves the  bodyguards ( the brackets ) the things between the brackets should take priority.

b)( 96+26 ) x 3 ÷ 2
=122 x 3 ÷ 2
=366 ÷ 2
=183

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a)I have learnt that there are two groups in the order of the operations.group 1 consists of + and -.Group 2 consists of x and / we should always work the problem from left to right in either groups.  If the problem has both group one and group two, we should work on the multiplication and division(group 2) first. When there are numbers in brackets which are also known as bodyguards we will have to solve them first whether they are from group 1 or group 2.

b)(1+1)x1/1
=2

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a) I have learnt that in Order Of Operations, there is Group 1, which consists of addition and subtraction or plus and minus. Group 2, on the other hand, consists of multiplication and division or times and divide. When one group has all its equations in one sentence (like 9+12-6), we go from left to right.The same rule applies to Group 2, left to right. But in a case which we have both groups in one sentence (3+6x9-33) , we start with Group 2 first as Group 2 'supposedly has more power than Group 1'. But we have another symbol called the brackets or 'bodyguards', which holds more power. So we do (in order) brackets, Group 2 then Group 1.

b) 60 - (3 x 5) / 3
= 60 - 15 / 3
= 60 - 5
= 55

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A) I have learnt that in "Order Of Operations", there are TWO groups. Group 1 involves Addition and Subtraction whereas Group 2 involves Multiplication and Division. When there is a sum involving Group 1 (Example: 6+4-2), We have to work out the sum with the 'Left to Right' technique. The same goes for a sum involving Group 2 (Example: 8x2/4). However, If a sum involves both Group 1 and Group 2 (Example: 6+4x3), Group 2 will always be solved first as It takes priority. And when there are Brackets in a sum which is also known as 'Bodyguards' (Example: (8+7)-5x2), the sum in the Brackets will be solved First. I have now clearly explained on what I have learnt on "Order Of Operations"!!! >_<

B) 22x4+(77-54)
= 22x4+23
=88+23
=111

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a)I have learnt that there are two groups.
Group 1: + and -
Group 2:* and /
If you are using only one group you should work from left to right. But if you use a mix then you always need to start with group 2 from left to right. But most importantly if you have brackets than brackets should go first.

b) (215+200)/5
= 415/5
=8

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I have learnt that there are two groups and the bodyguards which it is the brackets.Group 1 is addition and subtraction,Group 2 is important that always start with any symbol like muitiplication or division and the most important part of orders of operations is  the brackets.Always start with the brackets first.After that you go to group 2.Then you go to group 1

EXAMPLE

(9x3)+24-17
=27+24-17
=51-17
=34

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a) I have learnt that there are 2 groups  of order of operations.The first group and the second group.The first group consists of plus and minus, whereas he second group consists of times and divide.Group two is more superior than group one and thus, in any number sentence that consists of order of operations, times and divide (grp 2) will go first.whenever in a statement of order of operations, if there is only one group, the golden rule is to go from left to right.We have also learnt of body guards, brackets.( ). Whenever bodyguards are used,the numeral statement with bodyguards will go first.
but some people would ask;
" what if group 1and group 2 have bodyguards"...... Those with that Q , it is simple. We go back to the rule that grp 2 is more greater than grp one. So , grp 2 with () will go first.

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I have learnt that there are Two  groups in "Order of Operations". The first group is addition and subtraction. Thesecond group is  multiplication and division. We should always use the technique "Left to Right" to solve a question. If we go from right to left, we might not get the correct answer & might lose the marks in the exam.If a question involves BOTH group 1 & 2, we should still use the same technique to solve the question. If there are the two groups in a question, we have to do the multiplication or division first, (whichever comes first), rather than the addition and subtraction. This is because Group 2 has more priority than Group 1.Unless there are brackets, nothing else should be different. Brackets are also known as "Bodyguards"  as they "protect" the numbers inside. They have a small equation inside them. If a question involves them, we should work them out first rather than the other two groups. So,  would rather calculate the the sum in the brackets first, then continue to finish the question. After that, I have to FIRST calculate the sum of the Group 2. If Group 1 is not in the question , then do Group 2 & the equation in the brackets.(if there are any). If Group 2 is not in the question, then just repeat the steps and, you are done!!!I have explained the "Order of Operations" and what I have learnt.=)

b)(10-7)+3x4=
=3+3x4
=3+12
=15

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a) From the lessons, I have learnt that in Order Of Operations, there are TWO groups. Group 1 is addition and subtraction, whereas Group 2 is division and multiplication. If a sum involving Order Of Operations contains Group 1, solve the question using the "Left-to-Right" technique. The same goes for a sum involving Group 2. If a question includes Group 1 AND Group 2, Group 2 ALWAYS goes first, before Group 1, as it is of higher priority. So far, everything is simple. HOWEVER, this is changed if the sum includes brackets! Referring to these brackets as "bodyguards",  they cover a small sum (Example: 2+3), and that sum goes FIRST. I have now successfully explained the technique of Order Of Operations: what I have learnt.

b) 38x5-(23+15)
=  190-58
=

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a) I have learnt that  there are 2 groups, Group 1 ( addition and subtraction ) and Group 2 ( multiplication and division ) , and brackets. If the sum has only Group 1 OR Group 2, then we work from left to right. If the sum has both Group 1 and 2, then we solve Group 2 first, followed by Group 1. If the sum includes brackets, then the equation in brackets has to be solved first.
b) 19 - (4+3) x 2
=19 - 7 x 2
= 19 - 14
= 5

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a) I have learnt  two groups in order of operations: Group one that consists of addition and subtraction while Group two consists of multiplication and division and Group two always comes first
b) 5+9x8
=5+72
=77

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a)I have learnt that there are 2 groups of the order of operations. The first group contains addition and subtraction and the second group contains multiplication and division. The first group is called Group 1 and the second group is called Group 2. If the equation contains only Group 1 then we work the equation from left to right and if the equation  contains only Group 2 then we also work the equation from left to right but if the equation contains Group 1 and Group 2 we work the Group 2 first as Group 2 is more important. If we add brackets then we solve the brackets first because brackets are the bodyguards and the bodyguards are even more important than Group 2.

b)   (11 + 9) - 2 x 5  + 20
= 20 - 2 x 5 + 20
= 20 - 10 + 20
= 10 + 20
= 30

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a) I have learnt that there are 2 groups of order of operations. The first group contains +/- and the second group contains x/division. When there is only group 2 or only group 1 in a equation, we must work from left to right. But when there is Group 1 and Group 2 in a equation, we must solve the one in Group 2 first then come back to Group one. Unless... there is brackets. Then, you have to do the number sentence in the brackets first and then  do either Group 2 or Group 1.

b)In this equation we must do the one in brackets first, followed by Group 2 .
(36+14)*2x5+(1+1)                   1)Do the
=50*2x5+(1+1) brackets first.
=50*2x5+2 2)Followed by Group 2
=50*10+2 3)Do the one in Group 2
=5+2 4) Add the numbers
=7 5) ANSWER

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a)What I learnt is there are 2 groups.Group1 contains of addition and subtraction.Group2 contains of multipication and division.There is also 'bodygaurds'.Group2 always go first unless group1 have bodygaurds.
b) (10-2) x2+3
=8x2+3
=16+3
=19

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a) I learnt that there is two groups.Group 1 contains plus and minus and Group 2 contains multiplication and division.
Usually, Group 2 goes first.
But when there is brackets.The one with brackets goes first.
b)3+(8-2)x5
=3+6x5
=3+30
=33

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A)I learnt that there are 2 groups,A and B.The A is (plus and minus)and group B is (times and divide)'The bodyguard''are brackets.If the statement is only times and minus,then left to right.If only times and minus,right to left.If there is brackets,we should start with it.
B)5+(7-2)x 5
=5+5 x5
=5+25
=30

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A)I have learnt that there are two groups and the "Bodyguards" in order of the operations. The first Group is Addition and Subtraction while the secong group is division and multiplication. The "Bodyguards" are brackets.
If only plus and minus, we should start from left to right. If group 2 is there, then they should always go first. But if the brackets are involved, we should start with the brackets even though the sum has group one.
If we want to add brackets in our equation, we should add if if we want to do a specific part first.
B)(54+25)x (76-12)
=79 x (76 - 12)
=79 x 64
=5056

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A)I have learnt bracket go first, then group 2, and then group 1
b) (2-3+4)*9=27

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A) I learnt that there are two groups and brackets.  The first contains addition and subtraction and the second, multiplication and division. In an equation contains of only one group, I can only do it left to right. if there is an equation that contains both groups, always do the simpler equations that have group two in the eqaution then followed by doing the remaining question left to right. If there is an equation that has brackets, always do the brackets first, even if the sum is group one. Then if the equation does not have both of the groups, do it left to right. And if the sum does, start with group 2.
B) 2 x (8+4) - 6
=2 x 12 - 6
=24 - 6
= 18

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a)I learnt hat there are 2 groups and brackets. Group 1 contains addition and subtraction. Group 2 contains multiplication and division and last are the brackets ((-)) If i have a sum containing all Groups and brackets I would first calculate the brackets than group 2 than group 1-Example in b)

b)34+(4-2)x2
=34+2x2
=34+4
=38

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A)I learnt from the lessons that there are 2 groups.They are group 1 and group 2. Group 1 contains addition(+) and subtraction(-).Group 2 contains multiplication(x) and division .In a number equation involving signs from Groups 1 and 2,the signs counted in group 2 will get top priority at all times.However,there is another Mathematics tool that are called brackets.We also like to refer to them as 'bodyguards'.If any part of an equation is covered in brackets,that part of the equation must be solved first before you can move on to solve the rest of the equation.
B)(34-3)+(5x3)x4
=31+15x4
=31+60
=91

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A) I have learnt that there are two groups, Group 1 which consists of plus and minus, and Group 2 which consists of multiplication and division. There are also two brackets and they are called "Bodyguards". Usually if there is both Group 1 and Group 2 together in a sum, Group 2 will be solved first. But with the "Bodyguards", Group 1 will go first.

B) 21+(5-2)x6
=21+3x6
=25x6
=150

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a) I have learnt that there are two groups,add and subtract in the first and divide and times in the second.Two brackets are referred to as the ''bodyguards'' as they tell you which sum you must do first if there are any in the number statement.

b)33-(4x5)+5
=33-20+5
=33-25
=8

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A) I have learnt that there are 2 groups and brackets.  Group 1 contains + and - while group 2 contains ÷ and × .  Two of the brackets are bodyguards. We must do them first in a number statement.                                   B) 6(5+3) 10                                                                             = 6-2+10                                                                                  =4+10                                                                                      =14

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a)

b)