# data[].attributes.body
Zn+2HCl ---> ZnCl²+H²

Zn=Zn
H - 2e-=H²
Cl - 2e-=Cl²

this is a oxidation reaction as hydrogen is being removed from chlorine

OA= HCl
RA= Zn

# data[].attributes.body
S - 4e- ----> S4+
O +2e- ----> O2-
20 + 4e- ----> (O2) -4
Oxygen is getting reduced
Sulphur is getting Oxidised
Reducing Agent - Sulphur
Oxidising Agent - Oxygen
Hence, this is a Redox

# data[].attributes.body
Zn+HCl-->ZnCl2+H2

Ionic equation: Zn0+H+1 Cl-1--> Zn² Cl-1+H² ⁰
Zn is getting reduced as it is gaining  a Chlorine.
HCl is getting oxidized as it is losing Hydrogen

# data[].attributes.body
2 NH ₃  + 3 Cl ₂ -------> N ₂ + 6 HCl

6 Cl ⁰ + 6 e⁻ --------> 6 Cl⁻¹
(reduction)

2 N⁻³ - 6 e⁻ -------->  2 N ⁰
(oxidization)

# data[].attributes.body
2 NH ₃ + 3 Cl ₂ → N ₂ + 6 HCl

This is an oxidation-reduction reaction:

6 Cl ⁰ + 6 e⁻ → 6 Cl⁻¹ reduction

2 N⁻³ - 6 e⁻ → 2 N ⁰ - oxidiation

# data[].attributes.body
2 NH ₃ (g) + 3 Cl ₂ (g) → N ₂ (g) + 6 HCl (g)

This is an oxidation-reduction (redox) reaction:

6 Cl ⁰ + 6 e⁻ → 6 Cl⁻¹ (reduction)

2 N⁻³ - 6 e⁻ → 2 N ⁰ (oxidation)

# data[].attributes.body
Zn + 2 O -2  + C-2 O-2 ---> Zn + 0 + C+ 4  O2

ZnO is getting reduced
CO is getting oxidised
CO is reducing agent
ZnO is oxidising agent

# data[].attributes.body
S0 + 2O⁰ -----> S⁺⁴  2O⁻²

Half Reactions:
S⁰ - 4e⁻ -----> S⁺⁴
O0 + 2e⁻ ------> O⁻²
2O⁰ + 4e⁻ ------> 2O⁻²

Sulphur is getting oxidised while, oxygen is getting reduced hence,
OA = O₂      RA = S

Thus, this reaction is redox.

# data[].attributes.body
Cu2+SO42-      +    Zn    ----> Zn2+SO42-      +     Cu

Zn(s)+CuSO4(aq)→ZnSO4(aq)+Cu(s)

oxidation: ZnSO4(aq)

reduction: Cu(s)

# data[].attributes.body
Zn+2 O-2 + CO ---> Zn+CO2

Zn is getting reduced from Zn+2 to Zn0, which means 2 electrons are added to it.

C is getting oxidized from C-2 to C+4, which means we remove 6 electrons from it.

# data[].attributes.body
CuSO4 + Zn ----> ZnSO4 + Cu

Cu^+2 (SO4)^-2 + Zn^0 ----> Zn^+2 (SO4)^-2 + Cu^0

Half reaction:

Cu^+2 +2e- ----> Cu^0 (GER - Reduction)
Zn^0 - 2e- ------> Zn^+2 ( LEO - Oxidation)

Oxidizing agent : CuSO4
Reducing Agent: Zn

# data[].attributes.body
-(Cu)+2 (So4)-2   +   (Zn)0 ------> (Zn)+2 (SO4)-2 + (Cu)0

-Cu+2 +2e- -----> Cu0 [Reduction]
-Zn0 -2e- ------> Zn+2 [Oxidation]

Oxidizing Agent: CuSO4
Reducing Agent: Zn

# data[].attributes.body
Step 1: Balanced equation
Step 2: It is redox as
Cu0 - 2e = Cu2+(Oxidation)
Cu2+ 2e = Cu(Reduction)
Zn0 - 2e = Zn2+(Oxidation)
Zn2+ + 2e= Zn(Reduction)

OA ---> CuSO4
RA ---> Zn

# data[].attributes.body
Given Equation:
ZnO + CO --> Zn + CO2

Ionic Equation:
Zn⁺² O⁻² + C⁺² O⁻² --> Zn⁰ + C⁺⁴ O-2

Half Reactions
Zn+2 + 2e⁻ --> Zn0  (RA - gain of electrons)
C+2 - 2e- --> C+4      (OA - loss of electrons)

Oxidising agent --> ZnO
Reducing agent --> CO

Since oxidation and reduction is taking place simultaneously, the given equation is a redox reaction.

# data[].attributes.body
S⁰ - 4e⁻ ---> S⁴⁺ (oxidation half-reaction)
O + 2e⁻ ---> O²⁻ (reduction half-reaction)
2O⁰ + 4e- ---> 2O²⁻
S⁰ + O²⁻ ---> S⁴⁺ 2O²⁻

# data[].attributes.body
Sulphur is getting oxidised as there is an addition of oxygen atoms and oxygen is getting reduced as there is an addition of electronegative ion.
Oxidising agent is O2(Oxygen) and Reducing agent is S(Sulphur)

# data[].attributes.body
ZnO is losing oxygen hence it is being reduced. CO is being oxidized by accepting oxygen to form CO2.

Half reactions
Zn-2+ 2e--->Zn0
C-2+ 2e---->C+4

the oxidizing agent is ZnO and the reducing agent is CO

THE FOLLOWING CAN BE CALLED A REDOX REACTION AS SiIMULTANEOUSLY BOTH OXIDATION AND REDUCTION IS TAKING PLACE.
Hence, justified.

# data[].attributes.body
S0 + O₂ ⁰-->S4 + O₂ 2-
Sulphur is being oxidized by oxygen. (LEO)
Oxygen is being reduced.  (GEO)
S0 - 4e- --> S4 (GEO)
O0 +2e- --> O₂ ²⁻(LEO)
Reducing agent: Sulphur
Oxidizing agent: Oxygen