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If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

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Substitute the expression that is equal to the isolated variable into the other equation after isolating one of the two variable.

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One way to find the roots to a system of a linear equation would be to look at a graph. When graphed, linear equations appear as straight lines. In order to find the *root(s)* of a linear equation, you would have to look at where the lines intersect.

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If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

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Isolate one of the two variables in one of the equations, Substitute the expression that is equal to the isolated variable from Step 1 into the other equation, Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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A Linear Equation is an equation of a line. A System of those two equations can be solved (find where they intersect), either: Using Algebra.

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If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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One way to find the roots to a system of a linear equation would be to look at a graph. When graphed, linear equations appear as straight lines. In order to find the *root(s)* of a linear equation, you would have to look at where the lines intersect.

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If the discriminant is negative, this means that the line when graphed will *never* touch the x-axis, causing a complex root.

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With the way that these types of equations are graphed, there is *no way* they’ll hit the x-axis more than twice, meaning they will *never* have more than two roots

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According to Google,

1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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One way to find the roots to a system of a linear equation would be to look at a graph. When graphed, linear equations appear as straight lines. In order to find the *root(s)* of a linear equation, you would have to look at where the lines intersect.

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if the discriminant is negative, then the quadratic equation has complex roots.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

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Substitute the expression that is equal to the isolated variable into the other equation after isolating one of the two variable.

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You would find the roots of a system of linear equations is by making a graph and see where the line crosses the x-axis and then substitute the expression for the y-axis.

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Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0  is the expression 𝑏 − 4 𝑎 𝑐  . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

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Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0  is the expression 𝑏 − 4 𝑎 𝑐  . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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if the discriminant is negative, then the quadratic equation has complex roots.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

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1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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There are no intersection points I think you spell it I forgot. So you can not because every quadratic equation cannot have more than 2 roots. Hector B

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if the discriminant is negative, then the quadratic equation has complex roots!

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If the discriminant is negative then we know that the quadratic equation will have complex roots .

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if the discriminant is negative, then the quadratic equation has complex roots.

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You would find the roots of a system of linear equations is by making a graph and see where the line crosses the x-axis and then substitute the expression for the y-axis.

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if the discriminant is negative, then the quadratic equation has complex roots

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Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0  is the expression 𝑏 − 4 𝑎 𝑐  . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0  is the expression 𝑏 − 4 𝑎 𝑐  . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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The discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0 is the expression 𝑏 − 4 𝑎 𝑐  and If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0  is the expression 𝑏 − 4 𝑎 𝑐  . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0  is the expression 𝑏 − 4 𝑎 𝑐  . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

# data[].attributes.body
A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

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Substitute the expression that is equal to the isolated variable into the other equation after isolating one of the two variable.

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You would find the roots of a system of linear equations is by making a graph and see where the line crosses the x-axis and then substitute the expression for the y-axis.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

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You would find the roots of a system of linear equations is by making a graph and see where the line crosses the x-axis and then substitute the expression for the y-axis.

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a quadratic-linear system cannot have more than two solutions because every quadratic equation cannot have more than 2 roots.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions

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herefore, our assumption that a quadratic equation has three distinct real roots is wrong. Hence, every quadratic equation cannot have more than 2 roots.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect up to two times.

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A quadratic-linear system cannot have more than two solutions because every quadratic equation cannot have more than 2 roots!

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α and γ are distinct. Thus, a(α - γ) = 0 cannot be true. Therefore, our assumption that a quadratic equation has three distinct real roots is wrong. Hence, every quadratic equation cannot have more than 2 roots.

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A quadratic-linear system cannot have more than two solutions because every quadratic equation cannot have more than 2 roots!

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One may find the roots of a system of linear equations by solving one linear equation for y in terms of x, where the line will cross the x -axis.

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A quadratic linear system cannot have more than two solutions because no other values of x satisfies the equation except a and b.

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A quadratic-linear system cannot have more than two solutions because every quadratic equation cannot have more than 2 roots. Hector B

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α and γ are distinct. Thus, a(α - γ) = 0 cannot be true. Therefore, our assumption that a quadratic equation has three distinct real roots is wrong.

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A quadratic-linear system cannot have more than two solutions because a line can only intersect zero, one, or two times; hence a linear and quadratic system can have zero, one, or two solutions.

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our assumption that a quadratic equation has three distinct real roots is wrong.

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α and γ are distinct. Thus, a(α - γ) = 0 cannot be true. Therefore, our assumption that a quadratic equation has three distinct real roots is wrong. Hence, every quadratic equation cannot have more than 2 roots.

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1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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How I would find the solutions of a quadratic linear system is by substituting the expression that is equal to the isolated variable from the two variables. Hector B

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1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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by isolating one of the two variables in one of the equations

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Isolate one of the two variables in one of the equations, Substitute the expression that is equal to the isolated variable from Step 1 into the other equation, Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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To solve, set the two quadratics equal to each other and then combine like terms.

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Substitute the expression that is equal to the isolated variable from Step 1 into the other equation.

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Substitute the expression that is equal to the isolated variable into the other equation after isolating one of the two variable.

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Isolate one of the two variables in one of the equations.

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1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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1. Isolate one of the two variables in one of the equations. ...

2. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...

3. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

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you will find the roots of a system in linear equation is making a graph and you will find a line that crossed the x axis

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by using the elimination or substitution method

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To find the solutions of a quadratic linear system I would isolate one of the two variables then substate and etc .

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To find the roots of a system of linear equations I would solve one linear equation for y in terms of x where the line crosses the x -axis,

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You would find the roots of a system of linear equations is by making a graph and see where the line crosses the x-axis and then substitute the expression for the y-axis.

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Making a graph and see where the line crosses the x axis

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You would find the roots of a system of linear equations is by making a graph and see where the line crosses the x-axis and then substitute the expression for the y-axis.

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where the line crosses the x-axis

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How you would find the roots of a system of linear equations is by making a graph and see where the line crosses the x-axis and then substitute the expression for the y-axis. Hector B

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A Linear Equation is an equation of a line. A System of those two equations can be solved (find where they intersect), either: Using Algebra.

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solve one linear equation for y in terms of x where the line crosses the x -axis,

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Make a graph and look for the points where both line cross.

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where the line crosses the x -axis,

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First, solve one linear equation for y in terms of x . Then substitute that expression for y in the other linear equation