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The point in a titration process where there is enough base or acid to neutralize the solution that's inside the flask.

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You must figure out the moles to be able to divide it by the volume. At this point you will also be getting the volume (acid or base) and adding it to a flask.

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So after a couple of problem solving, your answer will be 0.0211 M. In other words, 0.0211 M is the concentration of the substance NaOH (Sodium hydroxide).

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Now, you want to get the answer from the previous step which is 0.00465 and divide it with 220 HCl but you want to make sure it is in liters instead of mL. So you divide by .220 L and you will get 0.0211 M.

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You want to multiply 0.155 M with 0.0300 L(which is also known as 30.0 mL) and then you get 0.00465

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There is a sample of 30.0 mL of HCl with 0.155 M being titrated with 220 NaOH. What would the concentration of NaOH be?

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There is a sample of 30.0 mL of HCl with 0.155 M being titrated with 220 NaOH. What would the concentration of NaOH be?

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After the process, it begins to reach the endpoint where there is a physical change like the color of the solution changes. Anything that is excess like the acid or base will determine the pH of the substance.

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by Brandon Suris