# data[].attributes.headline
Item : Pepperoni ADC : 2 packs Ordering date:  Sept 24 Delivery Date : Sept 30 Next Delivery Date : Oct 4 Qty in coming delivery : 10 packs SOH: 15 packs Buffer days : 2 days

# data[].attributes.subject
Item : Pepperoni ADC : 2 packs Ordering date:  Sept 24 Delivery Date : Sept 30 Next Delivery Date : Oct 4 Qty in coming delivery : 10 packs SOH: 15 packs Buffer days : 2 days

# data[].attributes.headline
Item :Mozzarella ADC : 10 kg Ordering date:  Sept 17 Delivery Date : Sept 23 Next Delivery Date : Sept 27 Qty in coming delivery : 40 kg SOH: 20 kg Buffer days : 2 days

# data[].attributes.subject
Item :Mozzarella ADC : 10 kg Ordering date:  Sept 17 Delivery Date : Sept 23 Next Delivery Date : Sept 27 Qty in coming delivery : 40 kg SOH: 20 kg Buffer days : 2 days

# data[].attributes.headline
Item :Chicken Wings   ADC : 7kg Ordering date:  Sept 18 Delivery Date : Sept 24  Next Delivery Date : Sept 29Qty in coming delivery : 45 kgSOH: 15 kg Buffer days : 2 days  

# data[].attributes.subject
Item :Chicken Wings   ADC : 7kg Ordering date:  Sept 18 Delivery Date : Sept 24  Next Delivery Date : Sept 29Qty in coming delivery : 45 kgSOH: 15 kg Buffer days : 2 days  

# data[].attributes.body
FC = Adc = 2 x OC = 11

FC = 22

+

Buffer = 4

-

ID = 10

-

SOH = 15

STO = 1pk

# data[].attributes.body
ADC 2 x ODC 10 = 20

BUFF 2 days x ADC 2 = 4

Forecasted 20 + Buffer 4 -Incoming 10pcks. - SOH 15 pcks.= 1 pck.

# data[].attributes.body
Adc 2

Oc 11 days X 2 buffers = 26

Incoming 10

Stock on hand 15

Answer: 1

# data[].attributes.body
ADC x ORDERING CYLE (11days)

2x11= 22

FC + Buffer (2 days)

22+4= 26

Soh: 15 packs

Incoming del: 10 packs

Fc + Buffer - Soh - incoming del

22+4-15-10 = 1 pack

STO: 1 Pack

# data[].attributes.body
FC = Adc = 2 x OC = 110

FC = 110

+

Buffer = 20

-

ID = 40

-

SOH = 20

STO = 70kg / 20 = 3.5 =4 case

# data[].attributes.body
ADC 10kg x ODC 11 = 110

BUFF 2 days x ADC 10 = 20

Forecasted 110kg. + Buffer 20kg. -INCOMING 40kg. - SOH 20kg= 70 kg

Mozzarella ordering 20kg/Case

70kg/20kg = 3.5 Case

Order: 4 CASE

# data[].attributes.body
ADC 10

OC 11days

2x 11= 22+ 4= 26- 25 = 1

10 INCOMING DEL

15 BUFFER

= 25

# data[].attributes.headline
adc 10kg, incoming 40kg, soh 20kg, 2days buffer , OC 11                 10adc*11OC = 110 kg                         10adc*2days buffer=20kg                   110kg+20-20soh-40incoming=70kg                               70kg/20kg per case 3.5 then placed order as 4case 

# data[].attributes.subject
adc 10kg, incoming 40kg, soh 20kg, 2days buffer , OC 11                 10adc*11OC = 110 kg                         10adc*2days buffer=20kg                   110kg+20-20soh-40incoming=70kg                               70kg/20kg per case 3.5 then placed order as 4case 

# data[].attributes.body
Adc x OC (11days)

10x11= 110

Adc x buffer (2 days)

10x2= 20

FC+Buffer - Soh - incoming del = STO

110+20-40-20= 70kg

70/20kg =3.5kg

STO: 4 case

# data[].attributes.body
11days cycle

(22)

+4buffer

(26)

-24soh

ans.1

# data[].attributes.body
ADC - 2

OC - 11 days

2x11 = 22 = 26

Incoming = 10

SOH = 15

10+15=25

1 kilo

# data[].attributes.body
ADC : 2/ORDERING CYCLE : 11/BUFFER : 2DAYS (4)/INCOMING DELIVERY : 10/SOH : 15

2*11 = 22

22 + 4 = 26 - 10 - 15 = 1pack STO

# data[].attributes.body
FC = Adc = 7 x OC = 12

FC = 84

+

Buffer = 14

-

ID = 45

SOH = 15

STO = 38kg / 15kg = 2.53 = 3 case

# data[].attributes.body
Ordering cycle 11 plus 20 days

Equals 130

40 + 20 = 60

130 - 60 = 70kg

20÷70 =3.5

Equivalent to 4.

Answer: 4

# data[].attributes.body
Given:

ADC = 2packs

Buffer = 2days

SOH = 15packs

Incoming Del = 10packs

Ordering Cycle = 11days

FORMULA

STO = ADC + Buffer - SOH - IDel

= 2 (11) + 2(2) - 15 - 10

= 22 + 4 - 15 - 10

= 26 - 15 - 10

= 11 - 10

= 1pack of Pep

# data[].attributes.body
ADC 7kg. x ODC 12 = 84kg.

BUFF 2 days x ADC 7kg. = 14kg.

Forecasted 84kg. + Buffer 14kg. -INCOMING 45kg. - SOH 15kh.= 38kg.

CW Ordering 15kg/Case

38kg/15kg = 2.5 case

Order: 3 Case

# data[].attributes.body
110 - 40- 20 = 50

50 + 20 = 70/7kg

# data[].attributes.headline
Adc 7kg, incoming 45kg,soh 15kg,2 days buffer ,OC12                     Adc7*OC12=84                                Adc7*2days buffer= 14                        84+14-45incoming-15soh=38           38/15kg per case round of to 3case

# data[].attributes.subject
Adc 7kg, incoming 45kg,soh 15kg,2 days buffer ,OC12                     Adc7*OC12=84                                Adc7*2days buffer= 14                        84+14-45incoming-15soh=38           38/15kg per case round of to 3case

# data[].attributes.body
*11 days cyllcle(110)

110+ 20buffer(130)

130-90soh

ans.70

# data[].attributes.body
Adc x Oc (12 days)

7x12 = 84

Adc x buffer (2days)

7x2= 14

Fc+ Buffer-soh- incoming del = STO

84+14-45-15= 38kg

38/15=2.53

STO: 3 case/pack

# data[].attributes.body
ADC - 10

OC - 11

10x11 = 110

SOH - 20

Incoming - 40

130-20-40 = 70kg

70kg/4 packs

# data[].attributes.body
7*12= 84

84 - 45 - 15 = 24

24 + 14 = 38 / 5kg

# data[].attributes.body
Oc 12+2 = 14

7x 14 =98

45+15

Soh 60

98-60 = 38

# data[].attributes.body
ADC - 7

OC - 12 days

7x12 = 84

7x2 = 14

84+14-45-15 = 38

38/15 = 2.5

3 case

# data[].attributes.body
ADC =10

OC= 11

10× 11= 110 + 20 buffer =130

130 -60=70kg 3.5cs

# data[].attributes.body
ADC=10

OC =12 days

98 kg

60kg SOH

=38kg

# data[].attributes.body
Given:

ADC = 10kg

Buffer = 2days

SOH = 20kg

Incoming Del = 40kg

Ordering Cycle = 11days

FORMULA

STO = ADC + Buffer - SOH - IDel

= 10 (11) + 2(10) - 20 - 40

= 110 + 20 - 20 - 40

= 130 - 20 - 40

= 110 - 40

= 70kg or 4packs