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MVT is when a function is both continuous and differentiable over a closed interval. Pretty cool huh?

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The mean value theorem is a function that is continuous and differentiable over a closed interval

f'(c)=(f(b)-f(a))/(b-a)

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MVT is a function that is continuous and differentiable on a closed interval

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In a function interval that is continuous and differentiable, there is at least one point where the slope of the tangent is the same as the slope at the start and end of the interval.

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In mathematics, the mean value theorem states, roughly, that for a given planar arc between two endpoints, there is at least one point at which the tangent to the arc is parallel to the secant through its endpoints.

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When a function is differentiable and continuous on a closed interval

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function that is continuous and differentiable on a closed interval

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A function is continuous and differentiable on a closed interval

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If a function is continuous and closed on an interval, there is a point at which it's tangent line is equal to the overall slope.

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A function that is both continuous and differentiable on a closed interval

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if a function is differentiable at the point c on the interval (a,b). the derivate of c equals the y value of b minus the y value of a divided by b minus a

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If a function is continuous and differentiable on an interval, then the instantaneous rate of change is equal to the slope of the interval at a point, c

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A closed interval of a function that is continuous and differentiable.

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a function is continuous and differentiable on a closed interval

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In mathematics, the mean value theorem states, roughly, that for a given planar arc between two endpoints, there is at least one point at which the tangent to the arc is parallel to the secant through its endpoints.

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Function that is continuous and differentiable within an interval

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A theorem that is applicable to any function that is both continuous and differentiable  in an interval, that gives you an average value of that function.

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a theorem that makes a function continuous on a closed interval [a,b]. yeehaw

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there is a value between a and b where the slope at c is equal to the average.

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The function is continuous and differentiable on a closed interval

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The mean value theorem states that if a function is continuous and differentiable on a closed interval, there is a secant line that exists

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The mean value theorem states that if a function is continuous and differentiable on a closed interval, it means something on an open interval to.
Maybe f'(c) =[ f(b)-f(a)[/[b-a]

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The mean value theorem is when a function is differentiable and continuous on a closed function

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a function is continuous and differentiable on a closed interval

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function is differentiable and continuous on a closed interval

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I typed something and it didn't submit so I'm not typing it again

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A function is differentiable and continuous on a closed interval

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continuous and differentiable on an interval

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interval [a,b], there must exist a point c where the tangent at f(c) is equal to the slope of the interval.

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For a closed interval, there exists a point where the tangent line is equivalent to the slope of two points.

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a function is continuous and differentiable on a closed interval

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a function is continuous and differentiable on a closed interval

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the mean value states that a function is continuous and differentiable on a closed interval

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a function is continuous and differentiable on a closed interval

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A function is continuous and differentiable on an interval

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continuous and differentiable on a closed interval

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The mean value theorem states that a function is differentiable and continuous on a closed interval

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For any two endpoints there is a secant line to a function between those two points

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in a closed interval, a function is continuous and differentiable

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a function is continuous and differentiable on a closed interval

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The MVT says that a function is continuous and differentiable on a closed interval

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For any function that is differentiable and continuous on the interval [a,b] has at least one point c where the line tangent to c is parallel to the secant line ab.

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MVT = a continuous function on a closed interval, and the tangent = slope of interval at some point

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A function is continuous and differentiable on closed interval

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idk

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a function that is continuous and differentiable on a closed interval

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The mean value theorem shows that there must be a point where the tangent is equal to the slope of the continuous interval.

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there must be a point within an interval when a function is differentiable and continuous

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MVT is when a function is continuous and differentiable on the interval.

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continuous and differentiable