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Katlyn Linsey 9G1

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given: AB=AC {angles opposite to equal sides are equal}
<A+<B+<C=180
90+<B+<C=180
90+<B+<C=180
2<B=90
=<B=45
therefore, <B=<C = 45

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angle b = 180-90 = 90 [angle sum ppty]
90 by 2 =45
angle c = angle b =45

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GIVEN:In triangle ABC;AB=AC,<A=90 degree
TO FIND:<B &<C
SOLUTION:
SINCE AB=AC
<B=<C
<A+<B+<C=180 degree(angle sum property)
<A+2<B=180 degree
2<B=180-90=90 degree
2<B=90
<B=90/2=45 degree

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Given - Triangle ABC is right angled.
AB=AC
A=90 degrees
To Find - angle b and angle c
Proof
since AB=AC, angle B = angle C
angle A + angle B + angle C = 180
angle a + 2 angle b = 180
90 + 2 angle b = 180
2 angle b = 180-90 =90
angle b = 90/2 = 45
hence angle b = c = 45 degree

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Given: ABC is a right angle triangle, AB=AC. A=90⁰
To find: angle B and angle C
Proof: as AB=AC, Angle B= angle C
With angle sum property, Angle A+ angle B+ angle C=180⁰
90⁰+angle b + angle c=180⁰
Angle B+ Angle C= 90⁰
2×angle b= 90⁰
Angle B= 45⁰
Angle C= 45⁰
Angle A= 90⁰

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Given :
In a Right angled triangle ABC,
A is 90°
AB=AC

To find : <B and <C
Proof : in triangle ABC
AB =AC
<B =<C as opposite angles are equal.

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Given: ABC is a right angle triangle
angle A=90 degrees
AB=AC
To find: angle B & angle C

Solution:
Since AB=AC;
angle B=angle C----->1
<A+<B+<C=180 degrees
<B+<B+<A=180
2<B=180-<A
2<B=180-90
<B=90/2
<B=45 degrees
<B=<C
<C=45 degrees

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In triangle ABC,
AB=AC ;  <A= 90 degrees
To Find : <B and <C
In triangle ABC, since,
AB=AC ,  <B = <C (opp. angles on opp. sides)
Also, <A + <B + <C = 180 degrees.
then, <A + 2<B = 180
90 + 2<B = 180
2<B = 90
<B = 90 / 2 = 45 degrees

therefore, <B = <C = 45 degrees

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given: ABC is a right angled triangle
A=90 degree
AC=AB
to prove:  find B and angle C
proof: In triangleABC,
since AB=AC
angle B is also equal to                        angle C
so, A+B+C=180
as given a is 90.. 90+B+C=180
B=180-90
C is also 90 as angleB=angleC
therefore <B=90
<C=90

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Given - ABC is a right triangle
angle A = 90
AC = AB
To find - Angle B and Angle C
Solution - Since AB = AC,
Angle B = Angle C
Therefore,
Angle A + Angle B + Angle C = 180
90 + Angle B + Angle B = 180
2.Angle B = 180 - 90 = 90
Angle B = 90/2 = 45
Therefore
Angle B = Angle C = 45 degrees

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given - in triangle ABC ( right angle triangle)A = 90
AC= BC
AB = AC
to find = angle B and angle C
SOL-
AB = AC
THEREFORE ANGLE B = ANGLE C
angle A = 90 DEGREEE
ANGLE B = C
THEREFORE = angle A + angle B + angle c = 180 DEGREEE ( ANGLE SUM PROPERTY )
ANGLE B  = 180-90 = 90
angle B = 90/2 = 45
therefore angle B = angle C = 45 dergees .

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GIVEN:
ABC is a right angled triangle
angle A = 90 degree
AB=AC

TO FIND
Angle B and Angle C

SOLUTION
As AB=AC, Angle B=Angle C
Using Angle sum property,
Angle A + angle B  + Angle C=180
90 +angle B + angle B=180
90+ 2 angle B=180
2 Angle B= 90
Angle B=90/2
=45
Therefore angle B=45
angle C=B=45

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Given - <A=90degrees ; AB=AC
To Find - <B,<C
Solution - AB=AC (Given)
<B=<C
<A+<B+<C = 180degrees
90+2<B = 180
2<B=90degrees
<B=<C=45degrees

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given: ABC is a right angled triangle ;A = 90 ,
AB=AC
to find - angle B and C
proof ab=ac given
angle A = 90
angle b=c
angle A + angle B+ angle C =180(angle sum property)
Angle B =90/2=45
b=c c=45 degrees

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Given - ABC is a right angled triangle
angle A = 90
AB = CA
To find - angle B and C
Proof : AB = AC ( given )
Angle A = 90
Angle A + Angle B + Angle C = 180
90 + B + C =180
90 + 2x = 180
2x = 180 - 90
2x = 90
x = 90/2
= 45
therefore B and C are 45 degrees

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Given: ABC is a right angle triangle.
<A is 90 degrees.
AC=AB
To find: <B , <C
SOLUTION:
AB = AC. Therefore, <B = <C.
<A=90 degree.
<B= <C= x
<A + <B + <C = 180 degrees. [ angle sum property of triangle]
= 90 + x + x = 180
90+2x=180
2x= 180-90=90
x= 90/2= 45 degrees
Therefore, <B= 45 degrees. <C= 45 degrees

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Given-
IN TRIANGLE ABC,
ANGLE A = 90 DEGREES
AB=AC

TO FIND = ANGLE B and ANGLE C

PROOF-
AB=AC (given)
So, ANGLE B = ANGLE C
ANGLE A + ANGLE B + ANGLE C = 180 degrees
90 degrees + ANGLE B +ANGLE B = 180
2 angle B = 180-90 = 90 degrees
ANGLE B = 90/2 = 45 degrees
Thus,
ANGLE B = ANGLE C = 45 degrees

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angle C and angle B are equal.
therefore angle a+b+c=180
90+2y=180 (a=b)
2y+180
y=180/2
y=90
a=b=90

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GIVEN:  ABC is a right angled triangle ; LA=90 ; AB=AC
TO FIND: LB and LC
SOLUTION: since AB=AC,
LB=LC ----(1)
LB+LC+LA = 180
LB+LB=180-LA ( from 1 )
2LB=180-90
LB=90/2
LB=45
ALSO, LC =45
THEREFORE LB=45 & LC =45.

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Proof: In triangle ABC
angle A= 90
angle B = angle C ( AB=AC)
lets take angle B= angle C= x
angle B + angle A + angle C = 180 ( angle sum ppty)
ANGLE A + 2X = 180
90 + 2X= 180
2X= 180-90
X= 90/2
X=45
THEREFORE ANGLE B= ANGLE C= 45