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a)42=2x3x7
66=2x3x11
78=2x3x13
2x3=6
b)9=3^2
16=2^4
18=2x3^2
2^4x3^2=144

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a)Midnight->-6
8am----->-6+8=2
6pm----->-2                     Ans: a)-2 degrees
b)overall increase

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1764=2^2x3^2x7^2
LCM of 1764 and p=8820=2^2x3^2x5x7^2
HCF of 1764 and p=36=2^2x3^2

We can conclude that p=2^2x3^2x5=180
Ans:180

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a)-sqrt 10816=-sqrt 2^6x13^2
=-sqrt (2^3x13)(2^3x13)
=-2^3x13
=-104(ans)

b)3cuberoot 13824=3cuberoot 2^9x3^3
=3cuberoot (2^3x3)(2^3x3)(2^3x3)
=2^3x3
=24(ans)

# data[].attributes.body
a)5760=2^7x3^2x5^1
2^x-->2^7
5^y-->5^1
X=7
Y=1

b)5346=2x3^5x11
Make the index notation divisible by 3-------->2^3x3^6x11^3
2^3x3^6x11^3=7762392
7762392/5346=1452
K=1452

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a) -2 & 3
-1 & 4
1 & 6

b)1 & 2
-1 & -2

c)1+4+5=10
1+3+6=10
2+3+5=10
-1+5+6=10

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(i)Northbound-->15mins
Eastbound---->25mins
Westbound--->55mins

15--->3x5
25--->5^2
55--->5x11
LCM---->5^2x3x11=825
825mins---->13h 45mins
13h 45mins after 0530--->1915
Ans:1915

(ii)825/15=55
825/25=33
825/55=15

ANS: Northbound=55
Eastbound=33
Westbound=15

# data[].attributes.body
a)520----->2^3x5x13
1600---->2^6x5^2

LCM---->2^6x5^2x13=20800

b)HCF of 520 and 1600-->2^3x5=40

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Posted on 26 Feb

# data[].attributes.body
Posted on 26Feb

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Posted on 26Feb

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Please ignore the 'question 1' and working above the question 2

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00:00 -6°C
08:00   2°C
18:00 -2°C
i)2°C
ii)4°C,increase.

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36=2^2x3^2
8820=2^2x3^2x5x7^2
1764=2^2x3^2x7^2
So p = 2^2x3^2x5=180
Ans:180

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i)-√10816
=-√2^6x13^2
=-(2^3x13)
=-104
Ans:-104
ii)3√13824
=2^9X3^3
=2^3X3
=24
Ans:24

# data[].attributes.body
a)5760/3^2=640
640=2^7x5
Ans:x=7,y=1
b)2^2x3x5^2=1452
Ans:1452

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Avatar of %{name}

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a) 5760=2^7x3^2x5^1
X=7
Y=1
b) 5346k/3
=(2x3^2x11)([2]x3^2x[11])([2]x3x[3]x[11])
2x2x3x11x11=1452

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i)-2 and 3
-1 and 4
1 and 6
ii)1 and 2
-1 and -2
iii)1+3+6
1+4+5
2+3+5
-1+5+6

# data[].attributes.body
i)15=3x5
25=5^2
55=5x11
LCM of 15,25,55:3x5^2x11=825
Ans:825
ii)825/60=13 hours 45min
05:30+13 hours = 18:30
18:30+30 min = 19:00
19:00+15min=19:15
Ans:19:15

# data[].attributes.body
a)42-->7x2x3
66----->11x2x3
78----->13x2x3
HCF-->2x3=6

b)9-->3^2
16---->2^4
18----->2x3^2
LCM--->4x3^2=144

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i) 2^6 x 5^2 x 13 = 20800
ii) 2^3 x 5 = 40

# data[].attributes.body
a) 42 = 2 x 3 x 7
66 = 2 x 3 x11
78 = 2 x 3 x 13
HCF = 2 x 3
= 6
b) 9 = 3^2
16 = 2^4
18 = 2 x 3^2
LCM = 2^4 x 3^2
= 144

# data[].attributes.body
a)2^6x5^2x13=20800
Ans:20800
b)2^3x5=40
Ans:40