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(x-3)(x+8)=x2+5x-24
(x-1)(x-2)=x2-3x+2
(x+5)(x-5)=x2-25
5. a=1 p+q=b pq=c

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#4
(x+1)(x+7)=x2+8x+7
(x-3)(x+8)=x2+5x-24
(x-1)(x-2)=x2-3x+2
(x+5)(x-5)-x2-25

#5 (b=p+q,, c+pq)
(x+p)(x+q)=ax2+(p+q)x+pq

# data[].attributes.body
(x+1)(x+7)=x^2+8x+7
(x-3)(x+8)=x^2+5x-24
(x-1)(x-2)=x^2-3x+2
(x+5)(x-5)=x^2+25
(x+p)(x+q)=x^2+(p+q)x+pq

# data[].attributes.body
When the factorized expression at the form of (x+p)(x+q)

, its standard expression is x^2+(p+q)x+pq

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(x+p)(x+q)=ax^2+(p+q)x+pq

# data[].attributes.body
(x+1)(x+7)=x^2+8x+7
(x-3)(x+8)=x^2+5x-24
(x-1)(x-2)=x^2-3x+2
(x+5)(x-5)=x^2-25

p+q=b pxq=c

# data[].attributes.body
#4 (x+1)(x+7)=x^2+7x+x+7=x^2+8x+7
p=1 q=7 b=p+q=8 c=p*q=7
ax^2+bx+c=x^2+8x+7

#5
（x+p)(x+q)=ax^2+bx+c=ax^2+(p+q)x+(p*q)

# data[].attributes.body
（x+1）（x+7）=x ² +8x+7
(x-3)(x+8)=x ² +5x-24
(x-1)(x-2)=x ² -3x+2
(x+5)(x-5)=x ² -25

#5
(x+p)(x+q)=x ² +（p+q）x+pq

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(x+5)(x+6)=x^2+11x+30
5+6=11 5*6=30

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4. (x+1)(x+2)=x^2+3x+2
(x-1)(x-2)=x^2-3x+2
(x+1)(x-2)=x^2-x-2
(x-1)(x+2)=x^2+x-2
5.(x+p)(x+q)=x^2+(p+q)x+pq

# data[].attributes.body
4. (x+4)(x-7)=x^2-3x-28
(x-4)(x+7)=x^2+3x-28

5. (x+p)(x+q)=x^2+(p+q)x+pq

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4. predictions: p+q=b, pq=c, a=1.
(x+1)(x+7)=x²+8x+7
(x-3)(x+8)=x²+5x-24
(x-1)(x-2)=x²-3x+2
(x+5)(x-5)=x²-25
5. In (x+p)(x+q)=ax²+bx+c, a=1, b=p+q, and c=pq.

# data[].attributes.body
4# （x+1)(x+7)=x^2+8x+7
(x-3)(x+8)=x^+5x-24
(x-1)(x-2)=x^2-3x+2
(x+5)(x-5)=x^-25
5#(x+p)(x+q)=x^2+(p+q)x+p*q

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#4
(x+1)(x+7) =x^2+8x+7
(x-3)(x+8) =x^2+5x
(x-1)(x-2) =x^2-3x+2
(x-5)+(x+5)=x^2-25
#5
(x+p)(x+q) = x^2 +(p+q)x+pq

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Please answer the question and share your answer for #4 and #5 here.

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Download the following Worksheet

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Informal Formative Exploration Task #1_Expanding Binomial