# data[].attributes.body
a: 74-10 = 64

b: 74-1 = 73

c: 74+10=84

d: 84 (c) +10 = 94

e: 74+1 = 75

f: 84 (c) + 1 = 85 OR 75 (e) + 10 = 85

# data[].attributes.body
I would start with what I know, I have 10 rows and 10 columns. 74 is given

a- a is directly above 74- therefore a is 10 less than 74 so 74-10= a

b-b is one block to the left of 74- therefore it is 1 less than 74 so 74-1= b

c- c is one row below 74- therefore it is 10 more than 74 so 74+10=c

d-d is two rows below 74- therefore it is 20 more than 74 so 74+20=d

e-e is one block to the right of 74- therefore it is 1 more than 74 so 74+1=e

f- f is one row below and one to the right of 74- therefore it is 10+1 more than 74 so 74+11=f

Ms. F. Arendse

# data[].attributes.body
Previous knowledge allows you to complete the chart. The fact that you know it is a 100 block with 10 number per row.

a) 74 - 10 = 64

b) 74 - 1 = 73

c) 74 + 10 = 84

d) 84 (Answer of c) + 10 = 94

e) 74 + 1 = 75

f) 84 (answer of c) + 1 = 85

# data[].attributes.body
a) 74 - 10 = 64

b) 74 - 1 = 73

c) 74 + 10 = 84

d) 74 + 20 = 94

e) 74 + 1 = 75

f) 74 + 11 = 85

# data[].attributes.body
It is a 10 by 10 chart, therefore the numbers directly above and below the 74 will either be 10 before or 10 after. Therefore:

a) 64

c) 84

d) 94

Then, b is one to the left of 74, therefore we need to minus one. C is one to the right of 74, therefore we need to plus one. Therefore:

b) 73

e) 75

Lastly, f is one to the right of c (84), therefore we need to add one. Therefore:

f) 85

# data[].attributes.body
It's a 10 by 10 chart which means there's a difference of 10 between all numbers that are in one column. Also, each block = 1

a 74-10 = 64

b 74-1 = 73

c 74+10=84

d 74 + (2x10) = 94

e 74+1 = 75

f 74+ 10 +1 = 85

# data[].attributes.body
a = 74 - 10 = 64

b = 74 - 1 = 73

c = 74 + 10 = 84

d = 74 + 20 =94

e = 74 + 1 = 78

f = 74 + 10 + 1 = 85

# data[].attributes.body
Since the grid or chart is 10 x 10.

a. 74 - 10 = 64

b. 74 - 1 = 73

c. 74 + 10 = 84

d. 74 + 10 = 94

e. 74 + 1 = 75

f. 74 + 10 = 84 + 1 = 85

# data[].attributes.body
a. 74 - 10 = 64

b. 74 - 1 = 73

c. 74 + 10 = 84

d. 74 + 20 = 94

e. 74 + 1 = 75

f. 74 + 10 + 1 = 85

# data[].attributes.body
a. 74-10=64

b. 74-1=73

c. 74+10=84

d. 74+20=94

e. 74+1=75

f. 74+10+1=85

# data[].attributes.body
This is a 10 by 10 chart which = 10, so I will use that knowledge to inform my thinking.

74 - 10 = a [directly above], 64

74 - 1 = b [before], so 73

74 +10 = c [directly 1 row below], so 84

74 + 20 = d [directly 2 rows below], so, 94

74 + 1 = e [directly after], so 75

74 + 11 = f [directly below + 1 / c+ e], so 85

# data[].attributes.body
a) 74-10 = 64

B) 74-1 = 73

c) 74+10 = 84

d) 74 + 20 ( 10x2) = 75

e) 74+ 1 = 75

f) 74+10+1= 85

Ms T Weitz

# data[].attributes.body
A) 74 - 10 = 64

B) 74 - 1 = 73

C) 74 + 10 = 84

D) 84 (ANSWER OF C) + 10 = 94

E) 74 + 1 = 75

F) 75 (ANSWER OF E) + 10 = 85 /

84 (ANSWER OF C) + 1 = 85

# data[].attributes.body
a = 74-10

b = 74-1

c= 74+10

d= c+10 (c's answer +10)

e = 74+1

f= c+1 (c's answer + 1)

# data[].attributes.body
a) 74-10=64

b) 74-1=73

c) 74+10=84

d) 74+20=94

e) 74+1=75

f) 74+11=85

# data[].attributes.body
74-10=64

74-1=73

74+10=84

74+20=94

74+1=78

# data[].attributes.body
a) 74 - 10 = 64

b) 74 - 1 = 73

c) 74 + 10 = 84

d) 74 + 20 = 94

e) 74 + 1 = 75

f) 74 + 11 = 85

# data[].attributes.body
The 100 chart is a 10×10 chart, therefore:

A. Subtract 10=64

B. Subtract 1=73

C. Add 10=83

D. Add 20 to 73=93

E. Add 1=75

F. Add 10 to 75=85

Mona I.L.

# data[].attributes.body
As this is a 10 by 10 chart I will use the following knowledge to support my thinking.

a (64) will be 74 minus 10 since a is right above 74.

b will be 73 because b is before 74.

c (84) will be 74 + 10 because it is directly below 74.

d(94) will be 74 + 20 because it is 2 rows below 74.

e (75) will be 74 + 1 because it is also directly after 74.

f (85) will be 74 + 11 because it is directly below 74 and one block extra.

# data[].attributes.body
a) 74 - 10 = 64

b) 74 - 1 = 73

c) 74 + 10 = 84

d) 74 + 10 + 10 = 94

e) 74 + 1 = 75

f) (74 +1) + 10 = 85

# data[].attributes.body
Each row has 10 blocks.

rows 1-10.

if 74 is in row 7 the just below that would be row 8 which means below 74 will be 84 plus one F=85

row 1- 4

row 2 - 14

row 3 - 24

row 4 - 34

etc

help the learner also recognise the pattern.

on this way they can find any other letter.

# data[].attributes.body
a = 74 - 10 = 64

b = 74 - 1 = 73

e = 74 + 1 = 75

c = 74 + 10 = 84

f = 84 + 1 = 85

d = 74 + (2 x 10) = 94

# data[].attributes.body
I know what a 100 chart look like. It has 10 rows and 10 column. I know 4,14,24,34,44,54,64,74,84,94 is underneath each other. Therefore if 74 is given, the number right below will be 84 + 1 to the right will be 85. L Joorst

# data[].attributes.body
It is a 10 x 10 chart.

a. 74 - 10

b. 74 - 1

c.74 +10

d. 74 + 20

e. 74 + 1

f. 74 + 10 + 1

# data[].attributes.body
Known that it is a 100-block with 10 rows 10 colums, starting at number 1.

b = 74 - 1

= 73

e = 74 + 1

= 75

a = 74 - 10 (directly above)

= 64

c = 74 + 10 (directly below)

= 84

f = 84 + 1 (next to c, therefore 1 more)

= 85

d = 74 + 20 (two rows below)

= 94 / d = 84( c ) + 10 (directly below c)

# data[].attributes.body
Chart – 10 x 10 (1-100)

Any number before 74 you will have to minus x and any number after 74 you will have to add x.

A = 74 – 10

B = 74 – 1

C = 74 + 10

D = 74 + 20

E = 74 + 1

F = 74 + 10 + 1

# data[].attributes.body
b=73

c=84

d=94

e=75

f=85

# data[].attributes.body
a: 74-10=64

b: Count 1 backwards - 74 - 1 = 73

c: Count 10 forward - 74 + 10 = 84

d: C= 84 + 10=94

e: Count 1 forward - 74 + 1 =75

f: Count 1 forward: 84 + 1 = 85 / Count 10 forward : 75 + 10 = 85

# data[].attributes.body
a= Count backward 10: 74 - 10 = 64

b= Count 1 backward: 74 - 1 = 73

c= Count 10 forward : 74 + 10 = 84

d = C (84) + 10 = 94

e= Count 1 forward: 74 + 1 = 85

f = C (84) + 1 = 85 / e (75) + 10 = 85

# data[].attributes.body
I will ciunt vackwards to determin"a" value. B-f count in 1s

# data[].attributes.body
I will work from my prior knowledge and start with what I know:

Step 1 :100 Chart means 10 rows of 10 (10x10)

Step 2: I know the first row is 1 - 10, then 11-20, 31-40, 41-50,51-60,61-70.

Step 3: I start with what I have: 74. I count how many blocks before and how many after. 74 at block 3, so that mean 2 blocks before is 73 and 72. Then one block after means 75.

Step 4: Now I know...Row 1:62, 63, 64 (A), 65. Row 2: 72, 73 (B), 74, 75 (E). Row 3: 82, 83, 84(C), 85 (F). Row 4: 92, 93, 94 (D), 95

# data[].attributes.body
A = 74-10 (64)

B = 74-1 (73)

C = 74+10 (84)

D = 74 + 20 (94)

E = 74 + 1 (75)

F = 74 + 11 (85)

# data[].attributes.body
Prior knowledge will be used for this activity. 100 block has 10 blocks in a row.

a) 74-10=64

b) 74-1=73

c) 74+10=84

d) 84+10=94

e)74+1=75

f)84+1=85

# data[].attributes.body
The 100 chart is 10 by 10, therefore

a) would be 64 because it is above 74

b) would be 73 because its on the left of 74

c) would be 75 because its on the right of 75

d) would be 84 because its underneath 74

e) would be 85 because its next to 85

e) would be 94 because its underneath 84

# data[].attributes.headline
Well, when I move to the right in 1 row I know I add  1 and when I move backwards I subtract 1 and when I move downward I Add 10 and upwards I subract 10. So a=74-10=64, b=74-1=73, c=74+10=84, d=84+10=94, e=74+1=75 and f=84+1=85. 

# data[].attributes.subject
Well, when I move to the right in 1 row I know I add  1 and when I move backwards I subtract 1 and when I move downward I Add 10 and upwards I subract 10. So a=74-10=64, b=74-1=73, c=74+10=84, d=84+10=94, e=74+1=75 and f=84+1=85. 

# data[].attributes.headline
a-f calculation using a 100 number chart

# data[].attributes.subject
a-f calculation using a 100 number chart

# data[].attributes.body
a. 74 - 10

b. 74 - 1

c. 74 + 10

d. 74 + 20

e. 74 +1

f. 74 + 10 + 1

# data[].attributes.headline
Calculation technique for a - f using a 100 number chart

# data[].attributes.subject
Calculation technique for a - f using a 100 number chart

# data[].attributes.body
a. 74 - 10 = 64

b. 74 - 1 = 73

c. 74 + 10 = 84

d. 74 + 20 = 94

e. 74 +1 = 75

f. 74 + 10 + 1 = 85

# data[].attributes.body
Using prior knowledge it will be easy to figure out a -f. Knowing that every rou is 10 and evert column counts ten it will be easy to determine that a is 64 because it is ten blocks backwards

and.

# data[].attributes.body
I used prior knowledge to determine the following:

a = 74 - 10 which equals 64

b = 74 - 1 which equals 73

c = 74 + 10 which equals 84

d = 74 + 10 + 10 which equals 94

e = 74 + 1 which equals 75

f = 74 + 1 + 10 which equals 85

# data[].attributes.body
I counted in ones 72 to 74 then I said 74 - 10 = 64 at A then i said 74-1 = 73 at B, 74 + 1 = 75 at E, 75 + 10 = 85 AT F then 85-11 = 84 + 10 = 94 at D

# data[].attributes.body
I counted in ones 72 to 74 then I said 74 - 10 = 64 at A then i said 74-1 = 73 at B, 74 + 1 = 75 at E, 75 + 10 = 85 AT F then 85-11 = 84 + 10 = 94 at D

# data[].attributes.body
a) 74 - 10 =64

b) 74 - 1 = 73

c) 74 + 10 = 84

d) 74 + 20 = 94

e) 74 + 1 = 75

f) 74 + 11 = 85

# data[].attributes.body
place value chart using a 100 number chart

# data[].attributes.headline
How to work out number value between a-f?

# data[].attributes.subject
How to work out number value between a-f?

# data[].attributes.body
To work a=subtract 4( number above 74 means we are counting back), letters c and d I would add 4 all the time, therefore c = 78 and d=82, there's a repetition of 4 blocks all the time so I can use use repeated addition. To figure out b? I subtracted 1 as it's the block before 74 and e, I would add 1, as it's a block that comes after 74. As there is a additive reaction of 4, all number in each column running down vertically I would add 4 all the time.

# data[].attributes.body
A=74-10 =64,b=73,c=74+10=84,d=c+10=94,f=c+1

# data[].attributes.body
numbers in the same column as 74 needs to calculated as -10 of +10 depending on the number of rows above (minus) or below (add) 74, therefore:

a) 74 - 10 = 64 (1 row up subtract 10)

b) 74 - 1 = 73 (because it is the number just prior to 74)

c) 74 + 10 = 84 (1 row down - qdd 10)

d) 74 + 20 = 94 (2 rows down - add 20)

e) 74 + 1 = 75 (number after 74)

f) 74 + 1 (e) = 75 + 10 (one row down) = 85

# data[].attributes.headline
The letter above 74 should also end at 4, which makes it easier to identify that they number should be 64 as it should be one tenth more. As for the number beneath 74, it should also be ending with a 4 and should be 1 tenth more... Using the Thousands Hundred Tens Ones strategy 

# data[].attributes.subject
The letter above 74 should also end at 4, which makes it easier to identify that they number should be 64 as it should be one tenth more. As for the number beneath 74, it should also be ending with a 4 and should be 1 tenth more... Using the Thousands Hundred Tens Ones strategy 

# data[].attributes.body
A) 64

B) 73

C)84

D94

E) 75

F)85

# data[].attributes.body
a= 74-10=64

b= 74-1=73

c= 74+10=84

d= 74+20=94

e=74+1=78

f=74+10+1=85