# data[].attributes.custom_properties.w0e-BrBE
I agree that 2n^2 is the highest. It equals 8n

# data[].attributes.custom_properties.w0e-BrBE
i agree with joseph because if n is greater than 1 (e.g. 3) then 2n squared would be equal to (2*3)*(2*3) =36 while 2n would be 2*3=6 and 2+n would be 2+3=5. however if n is 1 or below (e.g. 1) then paul would be correct 2n squared would be (2+1)*(2+1)=4 2n would be 2*1=2 and 2+n would be 2+1=3 which is the greatest

# data[].attributes.custom_properties.w0e-BrBE
2n^2 is the largest as 2n is 2xn and 2+n is just 2+n so but 2n^2 wil be larger as it will be higher then 2nx2n so 2n^2 is the highest.

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph as 2n^2 can also be 4n. 2n is smaller than 4n and 2+n could be higher than 4n but the chances of that is not very likely

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph. Suppose n=3, thus 2n would be 2x3=6, 2+3=5, (2x3)x2=12, thus Joseph is correct as 12 is largest.

# data[].attributes.custom_properties.w0e-BrBE
Joseph, NxN =2N 2n squared is 4n that is the biggest out go the three letters

# data[].attributes.custom_properties.w0e-BrBE
for example if n is 5 then 2n^2 is (2*2)^2 which is 25^2 = 625 and the rest are smaller such as 2+n = 7, and 2n = 5*5 = 25

# data[].attributes.custom_properties.w0e-BrBE
i agree with joseph because if n is 7 for example, 2(7)^2 will equal to 196. 2 + 7 = 9 which is not as big as 196 and 2(7) is 14 which is also not as big as 196. hence joseph is correct

# data[].attributes.custom_properties.w0e-BrBE
2n2 is the square of 2n meaning it is the biggest only if n is 1 or more

# data[].attributes.custom_properties.w0e-BrBE
I agree with Paul because since 'n' is an unknown integer, so the true value of 'n' is unknown, hence meaning that for example, if it were a 0 or a 1 then the answer would be 2 and 3 respectively and it would be the largest.

# data[].attributes.custom_properties.w0e-BrBE
if n is negative, it will make the answer into a large negative number

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph. we wouldnt know if 2+n is larger than 2n, but we are sure that 2n^2 is larger than both. If n is 1, 2+1=3, 2n=2, but 2n^2 is equal to 2^2 which is 4.

# data[].attributes.custom_properties.w0e-BrBE
I agree with joseph because 2n^2 if n=1 or more, 2x1^2 is more than the other two options 

# data[].attributes.custom_properties.w0e-BrBE
I agree with joseph because 2n^2 is 2n×2n which is larger than 2+n and 2n supposing that n is 1 or more

# data[].attributes.custom_properties.w0e-BrBE
I agree with him as n could be equal to 0 so 2n equal to 0 and 2n^2 will also be equal to 0 while 2+n will be equal to 2 (which is the largest)

# data[].attributes.custom_properties.w0e-BrBE
I disagree with all three of them, but I'll just put it under the Joseph section because there isn't any disagree with
everyone section. I think that if n = 1,
2n^2 = 2x1^2 = 2x1 = 2 and 2+n = 2+1 =
3. So 2+n > 2n^2. But if n = 2 then 2n^2 >
2+n. Similarly, if n = 1 then 2n = 2x1 = 2
and 2+n = 2+1=3 so 2n < 2+n, but if
n=2.5 then 2n = 2x2.5 = 5 and 2+n =
2+2.5 = 4.5, so 2+n < 2n. As you can see,
the equation that gives a higher value is solely dependent on the value of 'n', so I don't think you can say that the value of one of the equations "2n^2, 2n and 2+n" will always be higher than another one, so that is why I disagree with all three of them.

# data[].attributes.custom_properties.w0e-BrBE
i agree with joseph because it could be any number 3 and higher. 3+2 is 5, 3x2 is 6 and 3x2^2 is 12.

# data[].attributes.custom_properties.w0e-BrBE
I agree with paul because since n is unknown, it could be 0, and the other 2 statements result in 0, but 2+0 is 2

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph. If n=10, 2n = 2 x n = 2 x 10 =20 which is Anthony's guess. 2 + n = 2 + 10 = 17 which is Paul's guess. Last, 2n^2 =  2 x 10^2  = 2 x 20 =40 which is Joseph's guess. Comparing all of these guesses, 2n^2 is the largest number, so Joseph is correct, thus agreeing with him.

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph.The product of multiplying 2n by itself will definitely be greater than just 2n and 2+n.If we take n as 10, 2n^2 will equal to 400.(Joseph) For Paul the following answer will be 2+10 so  12.Lastly, for Anthony it will be 2x10 which is 20.Evidently, Joseph is correct.

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph. Since 2n^2 > 2n >2+n, Joseph is correct. Example : If n=5, then 2n^2=(2x5)^2=100, 2n=2x5=10, 2+n=2+5=7. Thus, Joseph is correct. For the most part at least. But what if n=0? then that means 2+n is the greatest as it is equal to 2+0=2 and 2n would be just 2 x n= 2 x 0 = 0. 2n^2 would then be equal to (2 x 0) (2 x 0)= 0. Although I am saying why Paul is correct, I still agree with Joseph as for the rest for the numbers, Joseph would be correct. (from the example above) However, we can't just assume n=0 or any other number. To conclude: If n is 0, 2+n is correct. If n>0, then 2n^2 is correct.

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph. Supposing n=5, 2n = 2 x n = 2 x 5 =10 (Anthony) 2 + n = 2 + 5 = 7 (Paul) Lastly, 2n^2 =  2 x 5^2  = 2 x 25 =50. (Joseph) Comparing all of these answers, 2n^2 is the largest number, so Joseph is correct.

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph. So example is if n equals to 3, 2n would be 2 X 3 = 6. Then 2 + n would be 2 + 3 =5. And finally 2n^2 will be (2 X 3) X 2 = 12. If we compare all the answers, 2n^2 is the biggest. Therefore Joseph is correct.

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joseph. 2n^2 is larger than 2n and 2+n. 2n is basically 2xn while 2+n is only adding 2 to n. 2n^2 is basically 2 sets of ns multiplied by each other, making it 4n. As from all the other numbers, 4n is obviously bigger than 2+n and also bigger than 2n.

# data[].attributes.body
You are going to make a stand.

Decide who you agree with - Joseph, Paul or Antony.

In each case, either explain based on concepts or examples to convince others.