# data[].attributes.body
10x2=20

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if the first bar has 10 then the second has twice

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if the first bar is ten and the secon b

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in the 2nd bar graph there are 20 student

# data[].attributes.body
the first bar shows 10 students the second bar is twice

# data[].attributes.body
if the first bar is ten and the second one is twice as long the second one whloud

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if the first bar has 10 and then the seconed bar is twice a long means again.

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If the first bar is

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(1

# data[].attributes.body
if the first bar has 10 and then the seconed bar is twcie a long that means thatit can

# data[].attributes.body
10x2=20

# data[].attributes.body
10x2=20 because 10+10=20 and because it says the second

# data[].attributes.body
their are 20 students and the second bar graph because the first one got 10 in it says the second bar graph has twice as long as the first bar.

# data[].attributes.body
The amount of students in the second bar graph is 20 because 2 times 10 is the same as 20.

# data[].attributes.body
if the first bar is 10 and the secon one is twice as long the scond one wold be 20 and since the third bar is the aame

# data[].attributes.headline
amira a bar graph is  10 the then 10x2=20 then the second bar graph is a 20

# data[].attributes.subject
amira a bar graph is  10 the then 10x2=20 then the second bar graph is a 20

# data[].attributes.body
If the second bar is twice as long as the first bar that means that you need to multiply 10x2 and that equals 20 there are 20 students.

# data[].attributes.body
there are 20 bar in the second

# data[].attributes.body
If the first bar is 10 and the second one is twice as long the second one would be 20 and since the third bar is the same length as the second bar the third bar is 20