# data[].attributes.headline
IT DEPENDS, BUT 2n WILL NEVER BE THE MOST.

# data[].attributes.subject
IT DEPENDS, BUT 2n WILL NEVER BE THE MOST.

# data[].attributes.custom_properties.w0e-BrBE
if n is a negative number, 2n  will be in the netives which makes it the smallest. 2+n may also be in the negatives, however there is a possibility that it could be in the positives or it could be zero. However, no matter what, 2n^2 will always be in the positives as negative * negative is positive and so 2n^2 has the highest likelyhood of being the largest if n is negative. If n is positive, 2n will be 2*n which will still be the smallest. 2+n may be smaller than 2n^2 but if n is less than or equal to 2/2 which is 1, 2+n will be more than 2n and 2n^2. Last but not least, if n = 0, 2+ n will be the largest. However, still,  2n^2 has the highest likelyhood of being the largest as there are only limited number of posibilities that 2+n is more than 2n^2 which is if n is 0 or more than    or equal to -2 and less than or equal to 1.

# data[].attributes.custom_properties.w0e-BrBE
2n square is the largest because 2n square is larger than 2n we do not know the value of n but i think 2n square would still be greater than 2+n

# data[].attributes.custom_properties.w0e-BrBE
2n^2 is the largest because if n = 3, 2+n is equal to 5 which means that 2n is equal to 6 and 2n^2 is 18. so 2n^2 is the biggest.

# data[].attributes.custom_properties.w0e-BrBE
if n=5, 2+5=7, 2n=10,2n^2=100. in this situation, 100 is the largest which is why i think that 2n^2 is the largest

# data[].attributes.custom_properties.w0e-BrBE
2n^2, because 2n^2 is 2 x n squared, which no matter what is bigger than 2 x n or 2 + n

# data[].attributes.custom_properties.w0e-BrBE
If n is 0 2+n is bigger than 4n and 2n as they are still both 0

# data[].attributes.custom_properties.w0e-BrBE
The answer cannot be found. n can be any number. if n = 0, 2n^2 = 0, 2+n=2 and 2n=0, making 2+n the largest. But if n = 2, 2n^2 = 6, 2+n = 4, 2n = 4, making 2n^2 the largest. Thus, the largest cannot be found as there is lack of information.

# data[].attributes.custom_properties.w0e-BrBE
Assuming that n could be any number, we cannot assume that 2n^2 is the largest because if n = 1, then all the equations would have the same value, thus the largest is none of the above.

# data[].attributes.custom_properties.w0e-BrBE
2n^2 is the largest number because if we let n=2, 2n=4, 2+n= 4, and 2n^2=2(2)^2=8. Therefore, 2n^2 is the largest number

# data[].attributes.custom_properties.w0e-BrBE
I agree that 2n^2 is the largest, because 2+n is merely 2 and n added together, and 2n is only 2 multiplied by n. 2n^2 is 2 multiplied by n and recieving the power of 2

# data[].attributes.custom_properties.w0e-BrBE
If n = 1, n + 2 is bigger as the rest are equal to 2: 2n = 2x1 = 2, 2n^2 = 2(1x1) = 2(1) = 2. But if n is more than 1, eg 2, 2n^2 will always be the biggest.

# data[].attributes.custom_properties.w0e-BrBE
If n is 1, 2n is 2. So 2n^2 is 4. 4 is bigger than 2n, which is 2 and is bigger than 2+n which is 3

# data[].attributes.custom_properties.w0e-BrBE
I agree with Joesph because 2 + n just means that you add two to n, 2n means 2 of n or n multiplied by 2. But 2n squared means that you square 2n by itself, like 2n x 2n, which gives you 4n which is the largest number.

# data[].attributes.custom_properties.w0e-BrBE
2n^2 is not 4n. Exponents go first so its 2 x n x n. This is obviously greater than 2n as its 2n x n. For 2 + n, if n > 1 then 2n^n is greater, if n <= 1 then 2 + n is greater. In conclusion, it is unsolvable. 

# data[].attributes.custom_properties.w0e-BrBE
2n^2 is the biggest because 2 x n is bigger than 2 + n, and 2n^2 is bigger than 2n as 2n^2 is basically 2n x 2n

# data[].attributes.custom_properties.w0e-BrBE
I agree with Paul as 2n^2 is equal to 4n which is greater than 2n and n + 2.

# data[].attributes.custom_properties.w0e-BrBE
If n=2 then n+2=4, 2n=2×2=4, but 2n²=2×2²=8, making Joseph correct. However, this is only the case if i assume n=2. N can be any value, so its unsolvable.

# data[].attributes.custom_properties.w0e-BrBE
take n to be 6 so 2n is 12 2+n is 8 then 2n^2 is 144 so 2n^2 is the largest 

# data[].attributes.custom_properties.w0e-BrBE
if n=10, then 2n^2 = 20^2, which is 400, while 2+n would be 12 and 2n would be 20. So, 2n^2 is the largest

# data[].attributes.custom_properties.w0e-BrBE
I think 2n^2 is the biggest as 2n^2 is equal to 4n which is larger than 2+n and 4n is also bigger than 2n

# data[].attributes.custom_properties.w0e-BrBE
if n = 3, 2+n is 5, 2n is 6, and 2n^2 is 18. In this case, 18 is the biggest. 2+n is smaller than 2xn in most cases (excluding if n=1, n=2 or n=0) and 2n^2 is bigger than 2n since 2n^2 is 2 x (n x n) 

# data[].attributes.body
You are going to make a stand.

Decide who you agree with - Joseph, Paul or Antony.

In each case, either explain based on concepts or examples to convince others.