# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number. It can only be divided by itself and 1. So p times q is 37.

# data[].attributes.custom_properties.PxYmxijk
Closest prime number to 42 is 43 and after doing calculation, I realised that 43 is the answer.

# data[].attributes.custom_properties.5bU1IQIg
Since 37 is a prime number, it can only be divided by 1 and 37, therefore 1 and 37 are the numbers.

# data[].attributes.custom_properties.PxYmxijk
1x(1x42)=43. this is the only possible equation.

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number, and it's only factors are 1 and 37

# data[].attributes.custom_properties.PxYmxijk
If n is any other number except for 1, when you expand the equation, you get n^2 + 42n. As you can see, both of these numbers can be divided by this number 'n'. So by putting any number larger than 1 in there equation, there is always 'n' as a factor. Why the number 1 works is because it only has one factor, being itself. So anything divided by 1 gives you back the same result as the number that was divided by 1.

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number so its only two factors are 1 and 37

# data[].attributes.custom_properties.5bU1IQIg
pxq=37 1x37 = 37 meaning p and q are 1 and 37

# data[].attributes.custom_properties.5bU1IQIg
As 1 multiplied by 37 gives the most logical answer as both numbers are whole numbers, and the product is also a prime number

# data[].attributes.custom_properties.PxYmxijk
As n times (n plus 42) can be simplified as n squared plus 42. Now we will need to find prime numbers that are bigger than 42. The first prime number after 42 is 43. So if we subtract 42 from 43, we get 1, and 1 squared also equals one, so I think I’m correct

# data[].attributes.custom_properties.5bU1IQIg
because 37 is a prime number and prime numbers only have 2 factors, which is 1 and itself and since 37 cannot have any other multiple other than 1 and 37, thus the values of p and q are 1 and 37

# data[].attributes.custom_properties.PxYmxijk
when n, a whole number is added to 42 and then after multiplied by 42+n, we can assume that n=1 so 1x(1+42) resulting in 43 which is a prime number, thus arriving us at the answer of 43

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number so the only factors could be 1 and 37.

# data[].attributes.custom_properties.PxYmxijk
It is because 1+(1x42)=43 and 43 is a prime number.

# data[].attributes.custom_properties.5bU1IQIg
Sine 37 is a prime number, it only has two factors, 1 and 37.

# data[].attributes.custom_properties.PxYmxijk
n = 1. This is because 1 x (1+42) =43, 43 is a prime number and 1 is a whole number

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number, so it should only have 2 factors, itself and number 1.

# data[].attributes.custom_properties.PxYmxijk
the closest prime number to 42 is 43, and the difference between 43 and 42 is one, which 1 divided by 1 is 1, which means n=1 and the prime number is 43.

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number so its only factors are 1 and 37

# data[].attributes.body
Owen

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number it cannot be divided properly by a number other than itself or one.hence if p x q  is 37 p can be one and q can be 37

# data[].attributes.custom_properties.PxYmxijk
43 is the closest prime number to 42 which was my first assumption. I then calculated that if n was 1, (42 +1) x 1 would be 43 which is a prime number

# data[].attributes.body
Nathan

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number and its factors are 1 and itself

# data[].attributes.custom_properties.PxYmxijk
the number is a prime number and is only divisible by only 1 

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number, hence the only factors of 37 is 1 and 37 itself

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number thus the only factors are 1 and 37

# data[].attributes.custom_properties.PxYmxijk
a prime number must have a factor of 1 thus n is 1 and 1 + 42 = 43

# data[].attributes.custom_properties.5bU1IQIg
37 is rime so only factors are 1 and 37 so 1 + 37 = 38

# data[].attributes.custom_properties.5bU1IQIg
it is the correct answer as 37 is a prime number, so it can only be divided bt itself or 1, and since the total is 37, the answer has to be 1 x 37, so p is 1 and q is 37

# data[].attributes.custom_properties.PxYmxijk
to get 43, it is 1 x (1+43), and 43 turns out to be a prime number as it only can be divided by itself and 1, so the prime number is 43.

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number and a prime numbers have only 2 factors - 1 and itself.

# data[].attributes.custom_properties.5bU1IQIg
As 37 is a prime numbers the factors can only be 1 and 37.

# data[].attributes.custom_properties.PxYmxijk
N is 1 so that n×n+42 is 43. 43 is a prime number

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number so it only has 2 factors 1 and itself. So, p x q has to be 1x37

# data[].attributes.custom_properties.PxYmxijk
N is equal to 1 so 1 x (1+42) =43 and as 43 is a prime number, the answer is 43.

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number so its only factors are 1 and 37

# data[].attributes.custom_properties.PxYmxijk
1 x (1+42) =43      43 is a prime number and 1 is a whole number

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number. Therefore, its only factors are 1 and 37.

# data[].attributes.custom_properties.PxYmxijk
In n(n+42), n must be 1 as if n is anything else, the total number would not be a prime number due to the fact that the number would be multiplied by n. 1(1+42) = 1x43 = 43.

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number and the only factors of 37 is 37 and 1

# data[].attributes.custom_properties.PxYmxijk
If n times (n plus 42) equals to a prime number, the product can only have 2 factors which is 1 and 42.

# data[].attributes.custom_properties.5bU1IQIg
37 is a prime number and the only factors of 37 is 37 and 1

# data[].attributes.custom_properties.PxYmxijk
If n is not 1, the final answer will be a product of n

# data[].attributes.body
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# data[].attributes.body
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