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Takiy Brownlee

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A-6+8i
B--5+5i
C-34i
D8+i

a. Check your arithmetic for Question 1

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Gilbert
2) (2i)(6+3i)
12i-6i

When you multiply 2i and 3i you get 6i^2.   What is i^2?    Substitute -1 for i^2.

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1. 2 - -6 = -8   5i - i = 4i
2.-6 + 12 i

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Write each of the following in the form a + bi

1. (2 + 5i) - (-6 + i)
2. (2i)(6 + 3i) -- Hint: Use Distributive Property

Solve the equation.

3. x2 + 16 = 0