# data[].attributes.body
A) (3+i)+(7-2i)
=10-i
B) (2+i)*(6+3i)
=9+12i
C) (-1-i)*(5+i)
=-4-6i
D)3+i/7-i
=20+20i/50
E) -3+2i/5+i
=-13+13i/26

# data[].attributes.body
A)10-i
B)9+12i
C)-4-6i
D)20+10i/50
E)-13+13i/26

# data[].attributes.body
Punto #1
a)  2+3i
b) -3+1i
c)  1-2i
Punto #2
a) (3+i)+(7-2i)= 10-i
b) (2+i)(6+3i)=12+6i+6i+3i^2=12+12i+3(-1)=9+12i
c) (-1-i)/(7-i)= -5-i-5i-i^2=-5-6i-(-1)=-4-6i
d) (3+i)/(7-i)=(2/5)+(1/5)i
e) (-3+2i)/(5+i)=(-1/2)+(1/2)i

# data[].attributes.body
B)
a. 10-i
b. 2*6+2*3i+i*6+i*3i = 12+6i+61-3 = 9+12i
c. -1*5+(-1)*i+(-i)*5+-i*i = -4-6i
d. = 20+10i/50
e. -4-3i

# data[].attributes.body
B)
a. 10-i
b. 2*6+2*3i+i*6+i*3i = 12+6i+61-3 = 9+12i

# data[].attributes.body
A:2+3i
B:-3+1i
C:1-2i

# data[].attributes.body
A: 3i+2
B: 1i-3
C: 1-2i

2.

# data[].attributes.body
1. 2+3i

2. -3+i

3. 1-2i

Punto 2 a: (3+i)+(7-2i)=10-i.
b : (2+i)(6+3i)=12+6i+6i-3=9+12i.

c :(-1-i)(5+i)=-5-i-5i-i=1-2i.
d: 3+i/7-i = 20-10i/50.
e:-4-3i

# data[].attributes.body
puntos

A= 2+3i   B= -3+1i   C= 1-2i

segundo punto
A= 10-i
B= 3+i + 7-2i= 10-i
(2+i)(6+3i) = 12+6i+6i-3
= 9+12i

C= -4-6i

D= 20+10i/50

E= -1+1i/2

# data[].attributes.body
A=2+3i
B= -3+1i
C= 1 -2i
B)a)(3+i)+(7-2i)=10-i
b)(2+i)(6+3i)=9+12i
c)=-4-6i
d)=(20+10i)/50
e)=(-1+1i)/2

# data[].attributes.body
Julian Enrique Florez

A) (2+3i)
B)(-3+i)
C)(1-2i)
Punto B

A) (3+i)+(7-2i)=(10-i)

B)(2+i)(6+3i)= 12+6i+6i+3i^2=12+12i-3= 9+12i

C)(-1-i)(5+i)=-5-i-5i-i^2=-5-6i-(-1)=-4-6i

D)(3+i)/(7-i)=(3+i)/(7-i)*(7+i)/(7+i)=
(3+i)(7+i)/(7-i)(7+i)
= 21+3i+7i+i^2/(7^2-i^2)
=20+10i/(50)
=(2/5)+(1/5)i

C)(-3+2i)/(5+i)=(-3+2i)/(5+i)×(5-i)/(5-i)
= (-3+2i)(5-i)/(5+i)(5-i)
=(-15+i+10i-2i^2)/(5^2-i^2)
=-13+11i/26
=(-1/2)+(11/26)i

# data[].attributes.body
punto 1

a. 2+3i
b.-3 + 1i
c.1+(-2i)

2.
A= 10+i
B= -9+12i
C= -4-6i
D=20-10/50
E= -4-3i
D=

# data[].attributes.body
A= 2+3i
B=-3+1i
C=1+(-2i)

# data[].attributes.body
Punto a
a-->
b-->
c-->

# data[].attributes.body
Alejandra Báez

# data[].attributes.body
a = 2+3i
b=-3+1i
c=1+(-2i)
Segundo punto
a= (3+i)+(7-2i) = (10-i)
b= (2+i)(6+3i) = 12+6i+6i+3i^2 = 12+12i-3=9+12i
c=(-1-i)(5+i) = -5-1i-i5-i^2=-5-i-5i+1=4-6i
d= es el de la imagen

# data[].attributes.body
a. 2+3i
b. -3+1i
c. 1-2i

# data[].attributes.body
a : 2 + 3i
b : -3 + 1i
c : 1 + ( -2i )
A. ( 3+i ) + (7-2i ) = ( 10- i )

B . ( 2+ i ) ( 6 + 3i )
12 + 6i - 3
9+ 12 i
C. (-1 -1 ) ( 5 + i ) = 5 - 1 i - i5 + 1 = -4 -61
D. 20 + 10 i / 50
E . ( -3 + 2i ) / ( 5+ i ) = ( - 1 + 1i ) / 2

C.  ( -1-i ) ( 5+i ) = 5-1 i-i 5+1 = -4 -6 i

# data[].attributes.body
a=2+3i
b=-3+1i
c=1+(-2i)

# data[].attributes.body
Punto 1
A) 2+3i
B) -3+1i
C) 1-2i

Punto 2
A) 10-i
B) (2+i) (6+3i) = 2x6+2x3i+ix6+ix3i= 12+6i+6i-3 = 9+12i
C) (-1-i)(5+i) = -1x5+(-1)xi+(-i)x5+(-i)xi= -4-6i

# data[].attributes.body
Edgardo Jimenez
a. 2+3i
b. -3+1
c. 1+(-2i)

2. a. 10-i
b. 9+12i
c.-4-6i

d.20+10i/50
e. -1+1i

# data[].attributes.body
A) 2+3i
B) -3+1i
C) 1-2i
segundo punto
A) 10-i
B) 9+12i
C) -4-6i

# data[].attributes.body
A. 2+3j
B. -3 + j
C. 1 - 2j

Segundo punto

A. 10 - j
B. 9 + 12j
C. -4-6j
D. (20+10j)/50
E. (-13+13j)/25

# data[].attributes.body
a. 2 + 3i
b. -3 + 1i
c. 1 + (-2i)

a. 10 - i
b. 9 + 12i
c. -4 - 6i
d. 20 + 10i / 50
e. -1 + 1i / 2

# data[].attributes.body
A) 2 + 3i
B) -3 + 1i
C) 1 - 2i

Punto 2
A) ( 3 + i) + ( 7 - 2i) = 10 - i
B) ( 2 + i) ( 6 - 3i) = 12 + 6i + 6i -3
= 9 + 12i
C) ( -1 -1) ( 5 + i)
-5 - i -5i - i^2
-4 - 6i
D) (-3 + i)/ (7-i) * (7 +i) / (7 + i)
- 21 + 3i + 7i + 1^2 / 49 - i^2
20 + 10i / 50
E) -3 + 2i/ (5 + i ) * ( 5 - i) / ( 5 - 1)
-15 + 3i + 10i - 2i^2 / 25 - i^2
- 13 + 13i / 26
-1 + 1i / 2

# data[].attributes.body
1.
A) 2+3i
B) -3+1i
C) 1-2i

2.
A) (3+i)+(7-2i)
3*7+i-2i
10-i
B) (2+i)(6+3i)
2*6+2*3i+i*6+i*3i
12+6i+6i-3
9+12i
C) (-1-i)(5+i)
-1*5-1*i-i*5-i^2
-5-1i-5i+1
-4-6i
D) 3+i/7-i
7+i/7+i
(3+i)(7+i)/(7-i)(7+i)
21+3i+7i+i^2/49+7i-7i-i^2
20+10i/50
E) -3+2i/5+i
5-i/5-i
(-3+2i)(5-i)/(5+i)(5-i)
-15+3i+10i-2i^2/25-i^2+5i-i^2
-13+13i/28

# data[].attributes.body
punto 1
a. 2+3i
b.-3 + 1i
c.1+(-2i)

# data[].attributes.body
a. 2+3i
b. -3+1i
c. 1-2i

a. (3+i)+(7-2i)=10-i
b.(2+i)(6+3i)=12+6i+6i+3i^2=12+12i+3(-1)=9+12i
c.(-1-i)(5+i)=-5-i-5i-i^2=-5-6i-(-1)=-4-6i
d.(3+i)/(7-i)=(2/5)+(1/5)i
e.(-3+2i)/(5+i)=(-1/2)+(1/2)i

# data[].attributes.body
a: 2+3i
b: -3+1i
c: 1-2i
ejercicio 2
a: (3+i)+(7-2i)= 10-i
b: (2+i)(6+3i)= (2*6)+(2*3i)+(i*6)+(i*3i)= 12+6i+6i-3= 9+12i
c: (-1-i)(5+i)= (-1*5)-(-1*i)-(i*5)-(i*i)=-5-1i-5i+1= -4-6i
d: (3+i)/(7-i)= (3+i)*(7+i)/(7-i)*(7+i)= 21+3i+7i+i2/49+7i-7i-i2= 20+10i/50
e: (-3+2i)/(5+i)= (-3+2i)*(5-i)/(5+i)*(5-i)= -15+3i+10i-2i2/25-i2= -13+13i/26