# data[].attributes.body
If the discriminant is negative, then we know that the quadratic equation will have complex roots.

# data[].attributes.body
A quadratic linear system cannot have more than two solutions because α and γ are distinct. This, a(α - γ) = 0 cannot be true.

# data[].attributes.body
To solve a linear and quadratic system, you will have to isolate one of the two variables in one of the equations., then substitute the expression that is equal to the isolated variable from step 1 into the other equation and lastly solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
We can find the roots of a system of linear equations by graphing, substitution, and elimination. - Jazelle

# data[].attributes.body
Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0 is the expression 𝑏 − 4 𝑎 𝑐 . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

# data[].attributes.body
How I uncover if a quadratic-linear system has complex roots is the discriminant of the quadratic equation ax + bx + c = 0 is the
formula b-4ac. We know the quadratic equation will have complex roots if the discriminant is negative.

# data[].attributes.body
If the discriminant is negative, then we know that the quadratic equation will have complex roots.

# data[].attributes.body
Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0 is the expression 𝑏 − 4 𝑎 𝑐 . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

# data[].attributes.body
Recall that the discriminant of a quadratic equation 𝑎 𝑥 + 𝑏 𝑥 + 𝑐 = 0 is the expression 𝑏 − 4 𝑎 𝑐 . If the discriminant is negative, then we know that the quadratic equation will have complex roots.

# data[].attributes.body
The discriminant of the quadratic equation ax + bx + c = 0 is the formula b-4ac. We know the quadratic equation will have complex roots if the discriminant is negative.

# data[].attributes.headline
 If the discriminant is negative, then we know that the quadratic equation will have complex roots. -Alana Fedrick

# data[].attributes.subject
 If the discriminant is negative, then we know that the quadratic equation will have complex roots. -Alana Fedrick

# data[].attributes.body
If the discriminant is negative, then we know that the quadratic equation will have complex roots.

# data[].attributes.body
If the discriminant is negative then that'll tell that the equation has complex roots.

# data[].attributes.body
To solve a linear and quadratic system, First you isolate one of the two variables in one of the equations. Then you substitute the expression that is equal to the isolated variable from Step 1 into the other equation. And lastly you solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
a and y are distinct. Thus, a(a - y) = 0 cannot be true. Therefore, our assumption that a quadratic equation has three distinct real roots is wrong. Hence, every quadratic equation cannot have more than 2 roots.

# data[].attributes.body
A quadratic linear system can only have 2 solutions because three or more solutions would not be real solutions.

# data[].attributes.body
A and Y are distinct. A(a - y) = 0 cannot be true. Therefore a quadratic equation has three distinct real roots is wrong. Which is why quadratic equation cannot have more than 2 roots.

# data[].attributes.body
A quadratic linear system cannot have more than two solutions because α and γ are distinct. This, a(α - γ) = 0 cannot be true.

# data[].attributes.body
Isolate one of the two variables in one of the equations. Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
When a parabola and a line touches at a point, there's only one solution that's true for both equations. Sometimes it may have two solutions but more than two solutions won't be real.

# data[].attributes.body
α and γ are distinct. Thus, a(α - γ) = 0 cannot be true. Therefore, our assumption that a quadratic equation has three distinct real roots is wrong. Hence, every quadratic equation cannot have more than 2 roots.

# data[].attributes.body
a and y are distinct. Thus, a(a - y) = 0 cannot be true. Therefore, our assumption that a quadratic equation has three distinct real roots is wrong. Hence, every quadratic equation cannot have more than 2 roots.

# data[].attributes.body
a and y are distinct. Thus, a(α - y)= 0 cannot be true. Therefore, our assumption that a quadratic equation has three distinct real roots is wrong. Hence, every quadratic equation cannot have more than 2 roots.

# data[].attributes.body
First you would isolate one of the two variables in one of the equations. Then you would substitute the expression that is equal to the isolated variable from Step 1 into the other equation. And then lastly you can solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
To solve a linear and quadratic system, you will have to isolate one of the two variables in one of the equations., then substitute the expression that is equal to the isolated variable from step 1 into the other equation and lastly solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
To find the solutions of a quadratic linear system you solate one of the two variables in one of the equations. Then substitute the expression that is equal to the isolated variable from Step 1 into the other equation. Lastly, solve the resulting quadratic equation to find the x-values of the solutions

# data[].attributes.body
Isolate one of the two variables in one of the equations. ...Substitute the expression that is equal to the isolated variable from Step 1 into the other equation. ...Solve the resulting quadratic equation to find the x-value(s) of the solution(s).

# data[].attributes.body
We can find the roots of a system of linear equations using graphing, substitution, and elimination

# data[].attributes.body
To figure out the solution of a quadratic linear system, you first need to isolate one of the two variables in one of the equations. Than, change the expression that is equal to the isolated variable from step 1 into the other equation.Lastly, solve the quadratic equation you got to find the x-values of the solutions.

# data[].attributes.headline
To solve a linear and quadratic system:  you will have to isolate one of the two variables in one of the equations., then substitute the expression that is equal to the isolated variable from step 1 into the other equation and lastly solve the resulting quadratic equation to find the x-value(s) of the solution(s). -Alana 

# data[].attributes.subject
To solve a linear and quadratic system:  you will have to isolate one of the two variables in one of the equations., then substitute the expression that is equal to the isolated variable from step 1 into the other equation and lastly solve the resulting quadratic equation to find the x-value(s) of the solution(s). -Alana 

# data[].attributes.body
By looking where an intersection of two points occur on a graph.

# data[].attributes.body
We can find the roots of a system of linear equations with graphing, substitution, and elimination.

# data[].attributes.body
We can find the roots of a system of linear equations by graphing, substitution, and elimination.

# data[].attributes.body
when a system of two linear equations  have different  slopes  they will meet in space at 1 point the point of intersection is the solution

# data[].attributes.body
We can find the roots of a system of linear equations by graphing, substitution, and elimination.

# data[].attributes.body
By looking at the graph where the intersection of the x, y, and z value occur. Also the elimination method or the transposing method can be used to find the root.

# data[].attributes.body
You would find the system of linear equations  finding the degree with the highest power of the independent variable.