# data[].attributes.body
/10 = 6.8
b) 6+7/2 = 6.5
2a) 4+5+6+6+6+7+7+8+9+10+100/11 = 15.27
b) 7
3a) 
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Subha Malik
Subha Malik 
1a) 6.8 4+5+6+6+6+7+7+8+9+10/10
1b) 6.5 6+7/2
2) mean 4+5+6+6+6+7+8+9+10+100/11
15.2727
median
6
3a) the outlier increases the mean due to its high value. This brings up the mean.
3b) the outlier does not have an effect on the median
4) the mean id most effected as the it is brought up by the outlier


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Taimur Chishty 9-W

# data[].attributes.body
3.a) Since the value is an outlier, it's increasing the value more than 

# data[].attributes.body
My answers are in word

# data[].attributes.body
1a) 4+5+6+6+6+7+7+8+9+10 = 68

68/10 = 6.8

1b) 6+7/2

= 6.5

2a) 1a) 4+5+6+6+6+7+7+8+9+10+100 = 168

168/11 = 15.27

2b) 7

3a) As there is an outlier, which is 100, the mean doesn’t show an average value because the average has been increased because of the outlier.

3b) The median is effected to a lesser extent because only an additional value is added which still leaves us with a middle number.

4) The mean is more effected because it o longer finds out the average but for the median, only one additional number is included.

# data[].attributes.body
1.  a)  (4+5+6+6+6+7+7+8+9+10)/10 = 68/10 = 6.8

b)  (6+7)/2 = 6.5

2. a)  (4+5+6+6+6+7+7+8+9+10)/11 = 168/11 = 15.27

B)  7

3. a)  The extreme value greatly effects the mean as there is a major difference between the values.

B)  The median is not as effected as it is only the middle value of all of them.

4.  The mean is most affected by the inclusion of the outlier as it would bring a massive change between the values.

# data[].attributes.body
1a) 6.8

b) 6.5

2a) 15.27

b) 7

3a) It increases the value a lot, more than double

B) It doesn’t affect the median that much, it barley changes

4) The mean would be the one that is most affected by the outlier as that has to be added to an equation

# data[].attributes.body
1)a)  4+5+6+6+6+7+7+8+9+10/10 = 6.8
b) 6+7/2 = 6.5
2a) 4+5+6+6+6+7+7+8+9+10+100/11 = 15.27
b) 7
3a) there is a large difference between the answer in 1a and 2a, over 2x the original value
b) the median is now a single number.
4) the mean is most affected as increases over 2x the original amount

# data[].attributes.body
1a) 4+5+6+6+6+7+7+8+9+10/10=6.8
1b) 6+7/2= 6.5
2) Mean = 4+5+6+6+6+7+7+8+9+10+100/11 = 15.27
2b) Median = 7
3a) The value is an outlier and no longer shows an accurate representation of the average numbers.
3b) The mean isn't greatly affected as it makes the data set odd
4) The mean is most affected by the outlier because it brings a big difference between the values

# data[].attributes.body
1a) 68/10=6.8
1b) 6+7/2= 6.5
2a) 168/11 = 15.27
2b) 7
3a) the extreme value effects the mean because there is a big difference between the values.
3b) the extreme value has not affected the median as it is the middle value.
4) the mean would be affected the most by the outlier because there is a big  change in the values.

# data[].attributes.body
1a) 68/10 = 6.8
mean = 6.8
1b) 6 + 7 = 13
13/2 = 6.5
2a) 7
3a) the bigger value effects mean because it increases the value of the mean which is why the results might not be accurate
3b) it is not effected by the extreme value since it is the middle value
4)

# data[].attributes.body
1a) 68/10= 6.8
1b) 6/7= 6.5
2) 168/11=15.3
b)7
3a) Because the value is an outlier, it now does not depict the correct representation of the average of the given digits/numbers,
3b) The median isnt effected as the central number had to be established.
4) However, the mean is affected because the outlier's value was odd as compared to values given prior.

# data[].attributes.body
1a) 4+5+6+6+6+6+7+7+8+9+10/10= 6.8
1b)
4
2a)
4+5+6+6+6+7+9+10+100/11
= 14.6
2b)
7
3a)
The outlier effects the mean due to the major difference between the values
3b)
The outlier does not effect the medium by a great value as the medium is simply the middle value.
4)
The outlier will always heavily effect the mean and not the medium as the medium is only the middle value (which will increase by y 1 if you add an outlier) however the mean is the average so adding an outlier with a huge difference in values will effect the average.

# data[].attributes.body
1a.)

# data[].attributes.body
1a)
68 / 10 = 6.8
MEAN ^

b)
6 + 7 = 13
13/2 = 6.5
MEDIAN ^

2a)
68 + 100 = 168
10 + 1 = 11
168/11 =
15.3
MEAN ^

b)
11 + 1 = 12
12 / 2
= 6
MEDIAN ^

3a)
The mean is affected drastically.

b) the median is not affected severely.

4)
The mean is affected by the inclusion of the outliner as it has the most drastic difference numerically.

# data[].attributes.body
1a) 68/10 = 6.8 is the mean of the data set.

1b) 6+7/2 = 6.5 is the median.

2a) 4+5+6+6+6+7+7+8+9+10+100/11= 15.3
2b) 7 is the median.

3a) the extreme value (in this case is 100) definitely has an effect on the mean of this data set, as it raises the total average of the data set.
3b) the extreme value doesn't have much of an effect on the median of the data set. Since it makes the data set odd, the median would automatically be whole number.

4) the mean is the most affected as the outlier is also included in the equation.

# data[].attributes.body
Q1 a) 4+5+6+6+6+7+7+8+9+10/10
= 6.8
Q1 b) median = 6.5

Q2 a)  mean = 4+5+6+6+6+7+7+8+9+10+100/11
so mean = 15.2727

Q2 b) median = 7,

Q3 a) since the number 100 is an extremity/outlier it doesnt represent the accurate mean of the other 10 numbers.
Q3 b) median also increases

Q4 the mean is most affected by the outlier i.e 100. this is becasue it is a much larger number than the rest.

# data[].attributes.body
1a. 4+5+6+6+6+7+7+8+9+10/10= 6.8
1b. 6+7/2= 6.5
2a. mean=
4+5+6+6+6+7+7+8+9+10+100/11
mean= 15.2
2b.
the median= 11+2/2= 7
3a. Because the value is an outlier, it does not show an accurate representation of the average of numbers.
3b. The mean is not effected as you only need to find the middle number.
4. The mean is the most effected because of the value being an outlier.

# data[].attributes.body
1a) 4+5+6+6+6+7+8+9+10/9 6.8
1b)6+7/2=6.5
2a) 15.27
2b) 7
3a) as the value is an extreme value it no longer shows an accurate representation of the average of the numbers
3b) the median will increase as the middle number will change due to the addition of another number.
4) the mean is more impacted as it is brought up by the outlier

# data[].attributes.body
1a) 4+5+6+6+6+7+7+8+9+10/10 = 6.8
b) 6+7/2 = 6.5
2a) 4+5+6+6+6+7+7+8+9+10+100/11 = 15.27
b) 7
3a) Since we are adding an outlier value (100), it makes a huge difference to the value of the mean.
b) it doesn't have an effect on the median as much.
4) The mean is effected more by the outlier as compared to the median

# data[].attributes.body
1a) 6.8 4+5+6+6+6+7+7+8+9+10/10
1b) 6.5 6+7/2
2) mean 4+5+6+6+6+7+8+9+10+100/11
15.2727
median
6
3a) the outlier increases the mean due to its high value. This brings up the mean.
3b) the outlier does not have an effect on the median
4) the mean id most effected as the it is brought up by the outlier

# data[].attributes.body
1.a) 4 + 5 + 6 + 6 + 6 + 7 + 7 + 8 + 9 = 68/ 10 = 6.8 (mean)
b) (6+7)/2
= 6.5 (median)

2) 168/11
= 15.3 (mean)
= 7 (median)

3.a) Since the value is an outlier, it's increasing the value more than double.

b) The median barely increases.

4) The mean is affected greatly by the outlier  because it's bringing a huge difference between the values.

# data[].attributes.body
1a) 4+5+6+6+6+7+7+8+9+10/10 = 6.8
1b) 6+7/2 = 6.5
2) Mean= 15.27
Median=  7
3a) Since the value is an outlier, its increasing the value a lot for the mean.
3b) The median is not affected a lot by the change.
4) The mean is affected the most because the outlier hugely affects the mean value.

# data[].attributes.body
1a) Find Mean:
4+5+6+6+7+7+8+9+10/10
68/10= 6.8
1b) 4+5+6+6+7+7+8+9+10= 6+7/2
= 6.5 (median)
3a) Since the value is an outlier, it does show accurate results for the average.
3b) The median isn't effected to a great extent as the aim of the median is to find the middle value. Even if the extreme value is added the central values won't change and the median would stay constant. The numbers of the median stay odd and the average of the middle values stay constant.
4) Mean is effected greater than the median, because outlier changes the values of the number drastically. This would change the value of the numbers. Due to the value changing the mean would also change.

# data[].attributes.body
1a) 4+5+6+6+7+7+8+9+10/9 = 6.8
1b) 6+7/2= 6.5
2) mean= 168/11= 15.3
median= 7
3a) the extreme value has an effect on the mean because it raises the total average of the data set.
3b) the extreme value does not really have an effect on the median. It makes the data set odd so the median about automatically be a whole number.
4) The mean is effected more than the median because the outlier changes the values of the number. This would lead to the change in the value of number which means that the mean would change as well.

# data[].attributes.body
1a-  4+5+6+6+7+7+8+9+10/9=6.8

1b- 6.5
2a- 15.27
2b-7

3a- Due to the value being an outlier it no longer shows an accurate representation of a average of the numbers.

3b- The median is less effected due to the extreme value compared to the mean, it doesn’t have much effect as it is only needed to find the central or middle number.

4-The mean is most effected. This is because the outlier throws off the numbers and drastically affects the value.

# data[].attributes.body
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