# data[].attributes.body
lim x->2
f(2) = 0/0 (indeterminate form)
= (x-2)(x^2-2x) / (x-2)(x+2)
= lim-> x^2-2x/x+2
2^2-2x2/2+2
= 0/4 = 0

# data[].attributes.body
part 2

# data[].attributes.body
lim x-> 2
f(2) = 0/0 form (indeterminate form)
=x(x^2-4x+4)/(x+2)(x-2)
= x(x-2)^2/(x+2)(x-2)
= x(x-2)/x+2
sub x with 2
= 2(2-2) / 2+2
= 0/4 = 0
lim x-> 2 is approaching 0

# data[].attributes.body
lim x->2 (x-2)(x²-2x)/(x-2)(x+2)
=lim x->2 x²-2x/x+2
=2²-2(2)/2+2
=0/4
=0

# data[].attributes.body
Abhipsa-11G1

# data[].attributes.body
part 1