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Nice sunny day here at Sneak HQ. Would much rather be outside enjoying the weather. @Dummy

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Both groups getting the same clue today. Will this one help? Maybe.

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241,771,711,711,732,358 (18) added together = 68  with the (18) = 86

18,510,611,831,964,731 (17) added together = 65  with the (17) = 82

112,484,111,131,722,816 (18) added together = 54  with the (18) = 72

43,715,114,714,383,161 (17) added together = 60  with the (17) = 77

64,621,103,215,111,137 (17) added together =46   with the (17) = 63

87/3 = 29 (3 worded phrase maybe ?)

(Row 7 is totals of each column)

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Letters ranked by common-ness:

E,A,R,I,O,T,N,S,L,C,U,D,P,M,H,G,B,F,Y,W,K,V,X,Z,J,Q

“Unscramble”

“Stuck? Check out SNEAK GOAT” (possibly pointing us to the product pages)

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Cherry + apple = sweet and sour perfection

Sneak said AI can’t crack it alone - they tested it

DC said it was between 1 and 500 characters

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The Genius/dumb quiz could contain clues:

Quiz references numeric sequences (Q2), clearly uses letter-to-number substitution explicitly (Q12)

"Odd one out" question (Q4) might indicate we should look carefully at the cipher to remove or reorder something.

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-First hint THINK keyword possibility

-book cipher but that relies on everyone having a copy of said book or being available online

-With the first clue being books, and the second clue being about the sneak video. I think the video may lead us to a cipher book maybe.

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-The only thing I found that could directly translate was resistor codes, could be a play on something else?

-chemical name for whatever the “Brain Plasticity” is they added to GOAT

-I’ve checked the webpage code. Password is verified server side (I thought it might mean read the code as a clue). Nothing in the code that looks like a clue :(

Nihilist Cipher, found a clue on the video with images of mri, the title “st petersburg”, (russia), Coldwar cipher used was the nihilist cipher. I have tried singular words with a key to try and do the calculation but nothing is adding up yet.

A Nihilist cipher is a 5x5 grid where you pick the word preferably not duplicate letters, followed by the alphabet without repeating a letter, I/J use the same box and J is usually dropped, if a letter is repeated you move to the next letter. You then use a keyword which by using the grid reference would give you a 2 digit number, subtract that with current code and cross ref the grid to get the letter. I have tried the following words/keywords: (Can not use the same word at same time for both key and encryption)