# data[].attributes.body
Claim:
If the zucchini is placed in a sucrose solution with less than 0.6 M, then the zucchini will become flaccid.
Evidence:
sucrose solution - initial mass - final mass - change in mass (%) - water potential
yellow                         7.85                    5.81                -25.99                         -13.71
purple                         8.32                    5.71               -31.37                         -23.51
green                         7.67                     6.7                  -12.65                         -8.81
red                             12.17                  14.55               19.56                         -3.9
blue                           7.76                     5.55                 -28.48                       -18.61
orange                       7.88                    12.3                 56.09                             1

Reasoning:

Even though our hypothesis is proven wrong, there is still reason to explain why. Once the data table shown won was graphed, we were able to find the molarity of sucrose in the zucchini by identifying the x - axis intercept. Once we found the intercept, the zucchini's molarity came out to be 0.3M.
Since the zucchini's molarity is 0.3M, if the zucchini is placed in a sucrose solution with a molarity more than 0.3M, then the zucchini will then become flaccid. The reason behind this is because of osmosis. The concentration of water is greater on the inside of the zucchini than it is on the outside of the zucchini. Water will then travel its concentration gradient to reach homeostasis in concentrations. So, when zucchini is placed in a sucrose solution of 0.3M or lower, the zucchini will become turgid. Since there is more sugar and less water inside the zucchini rather than on the outside, the water will enter the zucchini in efforts to balance the concentrations.

# data[].attributes.body
Claim- The water potential of zucchini is -8.09 bars.
Evidence- At 0 M, the initial mass of the orange dialysis bag was 7.88 grams. The final mass was 12.32 grams and it increased by 56.09%. At .2 M, the initial mass of the red dialysis bag was 12.17 grams. The final mass was 14.55 grams and it increased by 19.56%. At .4 M, the initial mass of the green dialysis bag was 7.67 grams. The final mass was 6.90 grams and it had a -12.65 % change in mass. At .6 M, the initial mass of the yellow dialysis bag was 7.85 grams. The final mass was 5.81 grams and it had a -25.99 % change. At .8 M, the initial mass of the blue dialysis bag was 7.75 grams. The final mass was 5.55 grams and it had a -28.48 % change. At 1 M, the initial mass of the purple dialysis bag was 8.32 grams. The final mass was 5.71 grams and it had a -31.37 % change in mass. When these are graphed and the line of best fit is drawn, the line crosses at 0.33, which means that the molar concentration is 0.33 M. To find the water potential, which is pressure potential + solute potential, .33 needs to be plugged into the equation
-(1)(.33)(.0831)(295). This comes out to be -8.09 bars, which is the water potential.
Reasoning- The percent change in masses of the different sucrose solutions started at 56.09% and went all the way down to -31.37%. Using our evidence, we were able to determine the actual molar concentration of zucchini by graphing. When the molarity of the sucrose solution reached .4, the percent change got into the negatives and continued to lower thereafter. Osmosis caused the solution surrounding the zucchini to be absorbed and the water in the zucchini to be exuded during the experiment.

# data[].attributes.body
Madison Crump

Claim – Molar concentration of celery came out to be .41 M.

Evidence – Our Data included:

0M initial mass of 2.19 g increased by 10.5% to 2.42g.

.2M initial mass of 3.04g increased by 3.62% to 3.15g.

.4 M initial mass of 1.96g slightly increased by .5% to 1.97g.

.6 initial mass of 3.3g decreased dramatically by 12.42% to 2.89g.

.8 initial mass of 3.23g decreased by 15.79% to 2.72g.

1M initial mass of 2.61g decreased again dramatically by 35.24% to 1.69g.

Reasoning – When placed in several different sucrose solutions, the final masses seemed to vary. The evidence listed above is supported by the percent changing reaching zero slightly after the percent change of .5% at .4M. After reaching .4, the percent change became negative. On our data graph, the line crosses at .41M which displayed the actual molar concentration of our veggie, celery.

# data[].attributes.body
Claim: The water potential of celery is -10.05 bars.
Evidence: Water Potential is found using the equation Water Potential= Pressure Potential + Solute Potential. To find Solute Potential, the percent change of mass must be known. At 0 M the percent change was 10.5%. At 0.2 M the percent change was 3.62%. At 0.4 M the percent change was 0.51%. At 0.6 M the percent change was -12.42%. At 0.8 M the percent change was -15.79%. At 1 M the percent change was -35.25%. Once graphed, the molar concentration of sucrose in celery is found to be 0.41 M. This data will be used in determining the Solute Potential. The Solute Potential equation is Psi= -iCRT. The equation with our collected data is Psi= -(1)(0.41)(0.0831)(295). The Solute Potential is -10.05 bars. Because the Pressure Potential is 0, the total water potential of celery is -10.05 bars. (Because water potential =pressure potential + solute potential)
Reasoning: When the celery was put in different sucrose level solutions, the celery either lose or gain mass. If celery gains or loses mass depends on the direction of osmosis and diffusion occurring between the celery and the solution surrounding the celery. If the celery gains mass, then the percent change is positive. If the celery loses mass, then the percent change is negative. The points obtained can be easily plotted on a graph to determine the molar concentration of sucrose in celery. Wherever the line of best fit between the points crosses the x-axis, that is the solution concentration of what is being tested, which in this case is celery. Because determining water potential is an equation, the above information can be plugged into the formula. This shows the water potential of celery is -10.05 bars. This is reasonable because the more solute there is present in a solution, the more negative it becomes.

# data[].attributes.body
Claim: If the zucchini is placed in the sucrose solution with less than 0.6 M, the zucchini will become flaccid.

Evidence: At 0 M, the orange dialysis bag weighed 7.88 grams initially, and then it increased in mass by 56.09% and its final mass became 12.3. At .2 M, the initial mas was 12.7 and the final mass increased by 19.56% to become 14.55. When the molarity was .4, the initial mass was 7.67 and then the final mass decreased by -12.65% to be 6.90. At .6 M, the initial was 7.85, and the final was 5.81 which decreased by -25.99%. At .8 M the initial mass was 7.76 and the final mass was 5.55 which decreased by -28.48%. At 1.0 M, the dialysis bag weighed 8.32 grams, while its final mass weighed 5.71 which means it decreased by -31.37%.

Reasoning: The percent change started to decrease as the molarity reached .4 which showed the osmotic process going on with the sucrose and the water. The mass decreased after .4 M while it had increased at 0 and .2 M. In the hypothesis it stated that the solution would cause the zucchini to become flaccid which was tested during the experiment as the water left the cells and the zucchini's mass decreased showing how flaccid it was.

# data[].attributes.body
CLAIM- The molar concentration of sucrose in celery is .41 M.
EVIDENCE- At 0 M, the initial mass of 2.19 g increased by 10.5% to 2.42 g. At .2 M, the initial mass of 3.04 g increased by 3.62% to 3.15 g. At .4 M, the initial mass of 1.96 g only increased by .5% to 1.97 g. At .6 M, the initial mass of 3.3 g decreased by 12.42% to 2.89 g. At .8 M, the initial mass of 3.23 g decreased by 15.79% to 2.72 g. At 1 M, the initial mass of 2.61 g decreased by 35.24% to 1.69 g. After .4 M, the percent change became negative.
REASONING- When the celery was put in different sucrose solutions, their final masses were sometimes higher and sometimes lower than their original mass. The evidence supports the claim because at .4 M, the percent change was 0.5%. The percent change would reach zero just after the .4 M, which is true and can be seen on our graph when the line crosses the x-axis at .41 M.

# data[].attributes.body
The initial mass of the potato was 9.20 before it was put in the sucrose solution. When the potato was put in a sucrose solution with a molarity of 0.2, the mass of the potato increased to 10.25. For the higher sucrose molarity the potato decreased in mass. The potato's initial mass was 6.07, the final mass was 4.64 when put into a solution of sucrose molarity of 1.0.

# data[].attributes.body
When put in different sucrose solutions the mass of the potato increased and decreased. In different solutions of a sucrose molarity of 0.2 the mass of the potato was 9.20 and increased to 10.25 because it had a lower concentration of sucrose. When in a higher molarity of 1.0 the mass of the potato was 6.07 and had decreased to 4.64 since the potato had less sucrose then the solution.

# data[].attributes.body
If a Potato has more or less sucrose molarity. By putting it in a sucrose solution of different molarities.