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1A 2B 3C - 50%
1C 2B 3D - 80%

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MCQ

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1A 2B 3C
1C 2D 3A
PRE: 50%
POST; 80%

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1-measure the initial rate of decay

2- Add a source and subtract the background radiation

3-use a stopwatch to see how long would it take for the substance to have half the count rate, and this time will be its half life

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measure the count rate every 2 days

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steps:
1- measure the count rate of the background radiation.
2- add the source and subtract the background radiation from the source count rate and start the stopwatch.
3- stop the stopwatch when the count rate is half of the one calculated at the beginning.
4- the time taken for the count rate to half is the half-life.

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What u did is u found the power loss using I2r but u did that by finding the current by changing the formula to equal to I=V/R u just replaced each voltage by 22000v to find the current to find the power loss and u replaced the voltage by 32000v to find the current to find the power loss

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1289256/100*106)*100=
1.29%
6093/100*106)*100=
6.1*10 -3%

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1289256/100*106)*100=
1.29%
6093/100*106)*100=
6.1*10 -3%

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the magnetic field of the coil interacts with the magnetic field of magnet , producing a force on the coil to rotate in one direction to rotate the axle and the needle . FINALLY PLACE THE 20 $ ON THE WALL!

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Grou  2

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Use 20 pound note to buy nile river
generate electricity from nile river using hydraulic turbine
Use that energy to power a motor moving the axel with the conductor wire
The conductor wire is intersecting the magnetic field of the u shaped magnet so an induced current is made

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                                        ELECTRIC CIRCUITS

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                                        ELECTRIC CIRCUITS

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                                                    LOGIC GATES

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                                                    LOGIC GATES

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                    ELECTROMAGNETIC INDUCTION (GENERATOR SETUP)

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                    ELECTROMAGNETIC INDUCTION (GENERATOR SETUP)

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C (ii) low, because X is a high input and Y is a low imput and c is a NOR gate so the output is going to be 0 so Q=0

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a)i)fixed resistor
thermistor
LED

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b)NOR

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Ai)A=resistor,B=thermistor
C=L.E.D
B)when the temperature goes from hot to cold resistance of thermistor increases.and also voltage increases because r=v/i which means resistance and voltage are directly proportional.If cold the led light gets brighter.If hot the light will not light.

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a)

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low  , its nor gate , one of the input is high and the other is low , sow low will be favored in a nor gate

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OR gate

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c i)0
0

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the resistance of the resistor doesn't change, only its voltage changes.

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the resistance of the resistor doesn't change, only its voltage changes.

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b)

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AND gate

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B)ii)   AND gates output a high signal only when both inputs are high but OR gates only output a low signal when both inputs are low, otherwise it outputs a high signal

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B)ii)   AND gates output a high signal only when both inputs are high but OR gates only output a low signal when both inputs are low, otherwise it outputs a high signal

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In the OR gate, a logic high is achieved if either anyone or both the inputs are high.
In AND gate, logic high output is achieved only when both the applied inputs are high.

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a)i)A-resistor
B-thermistor
C- LED
ii) lower temperature causes higher resistance which will cause a higher voltag in the thermistor as it is in series with the fixed resistance, this will also cause a higher voltage through the LED allowing light to be emitted.
b)
0
0
0
1
1
1
1
1

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b)i)

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c)i) Upper input = 0
Lower Input = 0

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a)
i)
component A: Resistor
component B: Thermistor
component C: Diode

ii) When the temperature changes from hot to cold, the resistance of the thermistor increases and the voltage increases, because they are directly proportional.

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b)ii) When both inputs are different the AND gate gives 0 output and the OR gate give 1 output

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Only high or low, it doesn't keep getting higher.

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I posted 3 questions.. Scroll to the right to see them -->

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I posted 3 questions.. Scroll to the right to see them -->

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a)

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a) digital have signals that only have 2 values 1 and 0
analogue have signals that can be any value and can vary between them
b)ii)AND only turns on when A and B are 1 and OR turns on when A or B is 1
c)i) upper input= 0
lower input = 0
c)ii) the logic gate of A is nand so both inputs should be 1 to get 0. and logic gate b is NOR so Y should be zero for the output of B to be 1. so both inputs of logic gate C should be zero and one. so logic gate C, y is zero and x one to get an output of zero

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a) Digital signals consists of only high and low voltages where as analogue signal consists of continuously varying voltage.
B)I) AND Gate

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A)

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C)i)upper input=0
lower input=0
ii)logic state of Q=1
because X and Y are low and C is a NOR gate, and NOR gate will give high to both low input

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Group 4 (Ali Ahmed, Ahmed Khalil, Ahmed Yasir, Moaaz)

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Group 4 (Ali Ahmed, Ahmed Khalil, Ahmed Yasir, Moaaz)

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Living room lamps must be in parallel to each other in their branch.

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Living room lamps must be in parallel to each other in their branch.

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c)i)  (60*3) - (15*3)= 135 W
ii) (135) *(60*60)= 486000 J

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b)
i) I=P/V 100/200= 0.5A
ii) Q=Ixt 0.5x60= 30C

c)
i) (60x3)-(15x3)= 135W
ii) E=Pxt 135x3600= 4.9x10^5J

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A)

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(Pay attention to the labels of the axes)

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a) iii) 2.

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b)i)
1. (1/20+ 1/80)-1 =16 +24= 40ohms
2. I= V/R= 6/40= 0.15A
3. V= R*I= 16* 0.15= 2.4V

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b)i. I=p/v=100/200=0.5 A
ii. charge=txI= 60x0.5=30c
c)i)(60x3)-(15x3)=180-45=135w
ii)E=pxt=135x 3600=486000J