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Video #2 - Finding the vertex of an equation using -b/2a

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Video #2 - Finding the vertex of an equation using -b/2a

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https://drive.google.com/file/d/1BYjZsU33ho6B6eTN4okl8PzfYhtwdN-X/view?usp=drivesdk

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Video #1 - Solving for x using the Quadratic formula 

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Video #1 - Solving for x using the Quadratic formula 

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https://drive.google.com/file/d/1RvWlil_JMl9MB1FhR0fv8Lwj9Ykfkadq/view?usp=drivesdk

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An example of a parabola in real life is a rollercoaster track

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Three other points on the graph are (-5,-48), (8,-9), (4,15)

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The intercept form of this equation is y=-1(x-7)(x+1)

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The roots of the equation are (7,0) and (-1,0)

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The vertex form of the equation is y=-(x-3)^2+1

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The y-intercept of the function is 7, or (0,7)

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The maximum value for the quadratic function is 16. Because the vertex is (3,16) the maximum value has to be 16 because the parabola does not go higher

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The vertex is located at (3,16)

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The axis of symmetry is x=3. This is solved with the equation -b over 2a

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The parabola opens down because the coefficient is negative. This can be seen in the equation

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This is my equation