# data[].attributes.body
a) +3
b) +5
c) 0
d) +3
e) +6

# data[].attributes.body
a) +3
b) +5
c) -2
d) +3
e) +6

# data[].attributes.body
a) +3
b) +5
c) 0
d) +3
e) +6

# data[].attributes.body
(a) +3
(b) +5

(c) -6
(d) +3
(e) +12

# data[].attributes.body
+3
+5
0
+3
+12

# data[].attributes.body
a. +3
b. x+-6=-1 -> x= +5
c. -6 ( wrong) ans: 0 cuz O3 is diatomic
d. x+-3=0 -> x=+3
e. 2x+-14=-2 -> 2x=12 -> x= +6

# data[].attributes.body
C = N/V
100 cm^3 = 0.1 dm^3
C = 0.1/0.1
C = 1 Mol/Dm^3

# data[].attributes.body
d 0.8/40 = 0.02/1
= 0.02 mol/dm³

# data[].attributes.body
9. b) C= n/v
C= 0.2 mol/dm3

# data[].attributes.body
c) 0.1 mol / 0.1 dm^3 = 1 mol/dm^3

# data[].attributes.body
a) 0.1 / 0.1 = 1 mol/dm^3

# data[].attributes.body
9. b) c=0.2/1 = 0.2mol/dm^3

# data[].attributes.body
1000 cm^3=1 dm^3
0.2/1=0.2
Ans: 0.2 mol/dm^3

# data[].attributes.body
C= n/v C= 0.2/1 --> 0.2 mol/dm3

# data[].attributes.body
8. c) M = V/VM
0.5 = V/24
= 12 dm3
= 12000 cm3

# data[].attributes.body
0.5*24000=12000
Ans: 12000 cm^3

# data[].attributes.body
8(b) 0.06 mol x 24dm³/mol
= 1.44 dm³
= 1440 cm³

# data[].attributes.body
8. b) 0.06 = v/24
v = 0.06 x 24
v = 1.44 dm3
v = 1440 cm3

# data[].attributes.body
a)  1.5 * 24 = 36
36 dm^3 to cm^3 = 36000cm^3

b) 0.06 * 24 = 1.44
1.44 dm^3 to cm^3 = 1440cm^3

# data[].attributes.body
n= v/vm
1.5= v/24 --> 1.5= v/24000
v= 36000 cm3

# data[].attributes.body
Nathania (10 pts)