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For circuit C, because it has two batteries and one light bulb, it will be brighter than the bulbs in the other circuits.

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We think circuit c would work because it has two cells and one bulb and it will be very very bright.

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Circuit C will be brighter for there is two cells and one bulb. It would also work.

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I think that circuit c will flow around the circuit because it has 2 circuits. It will light up better because there is more than 1 cell so it will light up better.

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I think that circuit b will be successful because all of the wires are connected. However, there are three bulbs so the light would be dimmer because it is shared between three bulbs.

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The third one  will work  and because there are two batterys, the bulb will be brighter because there is more electric current.

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I think that circuit B will be a successful circuit because all of the wires are connected. However, there are three bulbs so the lights would be dimmer because it is shared between three lights.

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For circut C it would be very bright because there is two bateries and one light bulb so the electric current will  give it more energy and will make it to go faster.

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I think for circuit B it will not work that well for there is only one battery and three bulbs so it will go duller when you turn it on because there is not enough electric to go around all of them

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Circuit b doesn't have a switch but it will still work. The lights will be dimmer for the circuit has three bulbs and only one cell.

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Circuit B has one cell and three bulbs which means the bulbs will be very dull.

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Circuit B will work because there is an electrical flow that connects to the bulbs. It would be more dull because there is one cell and three bulbs.

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For circuit B the light would be on but also it would be vrey dimm because there is only one batery and there is three light bulbs.

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circuit A will not work for the switch is not connected to the wire so the electric wont flow around

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The second can work for you  don't need to have a switch but the light would be  dull because the electric current is reduced for it is shared between three bulbs.

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Circuit A would not work for the switch is not connected with the wire. The electrical current wouldn't be able to flow around the circuit.

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On circuit A it would not work because the switch is open and then all the power will not be able to travel through because all the power would go back out again

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The first one wouldn't work for the switch is open.

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We think circuit A won't work because the switch is open which means they are not all connected therefore the electric current won't go around.

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We think circuit a will not work because the switch is open, so the electric current can't go all around the circuit.

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The first one wouldn't work for the switch is not on so the electric current cannot flow through the circuit.
The second one will not be as bright as the others but there will still be a light source throughout the circuit but it will dim.
The third one will be really bright.

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For the first circut it would not work for the switch is open so the electric current will not go all the way round as the circuit is incomplete.

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We think that circuit A will not work because the switch is off therefore the electrical current will not be able to run through the the wires. We know this because in the diagram, the switch is at an angle so that means it wont work,therefore there is a break in the circuit so the chemical energy will not be able to flow through so this will not be a successful circuit.