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Discrimination -b/2a

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If a parabola opens up it's always positive

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I leanerned that i had multiple ways of being used but when you have a big number like 54 you must divide by 4 to find you answer as i

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To find the discriminant use b squared -4ac

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i cubed is -1
i to the 4th power is 1
i to the 5th power is the same as just i and the cycle continues

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If the discriminant is greater than zero, then there are two real solutions.

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I can be used to find solutions of parabolas that don't cross the x-axis

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i= (square root) -1
i(2)= -1
i(3)= -i
i(4)= 1

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The remainder of 3 is -i

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If the parabola opens up there is a minimum. If the parabola opens down there is a maximum

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if the discriminant is less than 0, there are two imaginary solutions

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If the discriminant is above zero then it has two real solutions

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If x^2 is negative then the parabola reflects downward; in contrast, if the equation's x^2 is positive, it points upward.

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The square root of -5 equals the square root of 5 with "i" in front

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When you have a negative under a square root you need to pull out a form of i

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If the parabola is negative it always opens down

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To simplify a fraction with an imaginary number in the denominator, one must multiply the fraction by the donominator's congugate over itself. This will then allow the imaginary numbers in the denominators to cancel out and, in some cases, would leave only the numerator complex, which is acceptable in an answer. An example of this would be 5 / 2+4i. The conjugate would be 2-4i. To simplify the above problem you would multiply 5 / 2+4i by 2-4i / 2-4i. This would give you 10-20i / 20, which can then be simplified to 1-2i / 2.

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I is the square root of -1 but I squared is -1

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The discriminant is b squared - 4ac

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i is the square root of -1

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parent quadratic function is y equals x squared

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Sum of the roots is -b/a

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-b plus or minus the square root of b square minus 4ac over 2

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This is a negative quadratic function with vertex at (-2, 4) and zeros at -4 and 0.