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Lesson 12 - When solving number 4  on the practice homework assignment the equation came out as (x-1)^2 = -1 and in order to solve it I have to take the square root of both sides but -1 doesn't have a square root since it is negative?

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Lesson 12 - When solving number 4  on the practice homework assignment the equation came out as (x-1)^2 = -1 and in order to solve it I have to take the square root of both sides but -1 doesn't have a square root since it is negative?

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How to solve the last problem (the 5th one) in the 'applied problems' pdf? (I mean the calculation process)

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How to solve the last problem (the 5th one) in the 'applied problems' pdf? (I mean the calculation process)

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If in an standard form of quadratic equation, the a value is positive and assume the vertex of the parabola line is (0.10); do we even need to factor the original equation because it has no x-intercepts and cannot be factored. 

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If in an standard form of quadratic equation, the a value is positive and assume the vertex of the parabola line is (0.10); do we even need to factor the original equation because it has no x-intercepts and cannot be factored. 

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Can square root be negative? Not the number inside of the square root, but could there be a negative interger before the square root sign which no matter what is the number inside, the result will be negative. 

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Can square root be negative? Not the number inside of the square root, but could there be a negative interger before the square root sign which no matter what is the number inside, the result will be negative. 

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Sometimes, when practicing factoring, we get so used to factoring expressions that we forget that NOT every polynomial can be factored.    Think of this way:
Factor 6.   Answer:  2 x 3
Factor 3.   Answer:  prime number, cannot be factored.

With algebraic expressions, it's the same:
Factor x^2 + 5x + 6
Answer:  (x+3)(x+2)
Factor x^2 + 5x + 3
Answer:  prime, can't be factored

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In today's homework the Factoring Pynomials 2, there is a equation which no common factors. In this case, does it mean there is no answer to this (we cannot factor it), or there is some trick I did not see?

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In today's homework the Factoring Pynomials 2, there is a equation which no common factors. In this case, does it mean there is no answer to this (we cannot factor it), or there is some trick I did not see?

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When using the x-factor method on x^2+3x-28 and x^2 is a 3x is b and -28 is c, why is a*c -28 and not -28x^2?

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When using the x-factor method on x^2+3x-28 and x^2 is a 3x is b and -28 is c, why is a*c -28 and not -28x^2?

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How would you do 4i. Since we are working with 2 digits which are quartic, you cant really factor that fully because you just end up with (x^2+y^2)(x^2-y^2). 

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How would you do 4i. Since we are working with 2 digits which are quartic, you cant really factor that fully because you just end up with (x^2+y^2)(x^2-y^2). 

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How to do the practice exercises problem 4? (Even though I have the answer but I am not sure it is correct)

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How to do the practice exercises problem 4? (Even though I have the answer but I am not sure it is correct)

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How to do the practice exercises problem 2 c?

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How to do the practice exercises problem 2 c?

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Add video links or website links that have helped you grow in your understanding of this unit or topics in this unit.

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Add video links or website links that have helped you grow in your understanding of this unit or topics in this unit.