# data[].attributes.body
1. the magnitude 1.00 x 10-6C

2. There will be a loss of potential energy.  - 4000 J

3. The capacitance is 0.1 F.

4. The flowing capacitance is 0.05 A

5. The potential difference across a resistor is 640 V.

6. The resistivity is 0.459m.

# data[].attributes.body
1. The magnitude of the two charges is 1x10^-6C Coulombs.

2. There will be a loss of potential energy at -4000 Joules.

3. The capacitance of the eclectic capacitor is 0.1 Farads.

4. The current flowing to the wire is 0.05 Ampere.

5. The potential difference across a resistor is 6400 Volts.

6. The resistivity of the wire is 0.459m.

# data[].attributes.body
Continuation

6. The resistivity of the wire is 4.59x10-4 Ohmmeter

# data[].attributes.body
1. The magnitude of the two charges is

1x10^-12 C.

2. The potential energy is -4000 J. Since it's negative, we can conclude that there is a loss of potential energy.
3. The capacitance of the electric circuit is 0.1 F (farad).

4. The amount of current flowing in the wire is 0.05 A (ampere).

5. The potential difference across the resistor is 640 V.

6. The resistivity of the wire is 4.59 Ω⋅m (ohm⋅metre).

# data[].attributes.body
1. The magnitude of the two identical charges separated by 1 cm is Positive or Negative 1.0010^-6 Coulombs
2. There will be a gain (increase) of potential energy. After computing for the given problem, I got 4000J which led me to conclude that it gained energy.
3. The capacitance is 0.0100 F.
4. The current flowing is less current with0.05 A.
5. The potential difference across a resistor, with a resistance of 320Ω is

640 V .
6. The resistivity is 0.03k ohms.

# data[].attributes.body
1. The magnitude of the two charges

(Q1 and Q2)is 1.00110-6 Coulombs.

2. The electric potential difference is -4000 Joules, and since it is negative, we conclude that there is a loss of potential energy.

3. C = 0.1 Farads.

4. I = 0.05 Ampere.

5.V = 640 V

6. = 0.459  m

# data[].attributes.body
1.  Q= 1 x 10^-12c
2. It is loss of energy because it is negative -4000 J
3. c = 0.1

4. A = 0.05

5. V= 640

6. P= 4.59 c

# data[].attributes.body
1. The magnitude of charge is 1.00 x 10^-6 C

2. E = -4000 J, since the joules is negative there will be a loss of potential energy

3. Capacitance is 0.100 Farads

4. The current flow is  0.05 Amperes

5. The potential difference across a resistor is 640 V

6. The resistivity is 0.459 m

# data[].attributes.body
1. The magnitude of the two chargers is 1.00 x 10^-6 C

2. There will be a loss in potential energy because the answer is in the negative, which is -4000 J.

3. The capacitance is 0.1 Farads.

4. The flowing current is 0.05 A.

5.  The potential difference across a resistor, with a resistance of 320 Ω is 640 V.

6.  The resistivity is 0.0459 k Ω x m

# data[].attributes.body
#1: The magnitude of the two identical charges are +1.00 x 10⁻⁶ C, and -1.00 x 10⁻⁶ C.

#2: There is a gain of the potential energy of 4000 J.

#3: The capacitance is 0.100 F.

#4: The flowing current is 0.05 A.

#5: The potential difference across a resistor is 640 V.

#6: The resistivity is 4.60 x 10⁻⁴ Ωm

# data[].attributes.body
1. The magnitude of the two charges

(Q1 and Q2)is 1.00110-6 Coulombs.

2. The electric potential difference is -4000 Joules, and since it is negative, we conclude that there is a loss of potential energy.

3. The capacitance is 0.1 Farads.

4. The current flowing is at 0.05 Ampere.

5. The electric potential difference across a resistor is 640 Volts.

6. The resistivity is 0.459 ohm(m)

# data[].attributes.body
1. The magnitude of the two charges is 1x10-4 Coulombs.

2. Since the potential energy is negative, then there will be a loss of 4000 Joules.

3. The capacitance is 2.5 Farads.

4. The current flowing is 0.05 Amperes.

5. The potential differences across the resistor is 640 Volts.

# data[].attributes.body
INSTRUCTIONS:

1. In 5 minutes, transfer your answers here.
2. Note: Just type your final answer.
3. In question number 2, make sure to justify why your answer is a gain or loss.