# data[].attributes.body
Therefore, the mode of the given data of the weight of the 50 students of Class 8B is 43.833 kilograms.

# data[].attributes.body
Weight of 50 Students of Class 8B

Maximum Class Frequency = 14
Modal Class = 41-45
Lower Boundary of The Modal Class = 40.5
Class Size (i) = 5
D₁ = 4
D₂ = 2

Mo = lbmo + [D₁/D₁=D₂] i
= 40.5 + [4/4+2] 5
= 40.5 + [4/6] 5
= 40.5 + [20/6]
= 40.5 + [3.333]
Mo =  43.833 kg

Therefore, the mode of the given data of the weight of the 50 Students of class 8B is 43.833 kg.

(There's no need to round off because the weight of the students is a continuous number.)

# data[].attributes.body
Therefore, the mode of the given data of the weight of the 50 Students of class 8B is 43.833 kg.

# data[].attributes.body
Maximum frequency is 14.
Modal class is 41-45 = 4.
Class interval / i is 4+1 = 5.

lbmo is 40.5
d1 is 2
d2 is 4

Mo = [lbmo + d1/d1+d2]*i
40.5+[4/4+2]*5
40.5+[4/6]*5
40.5+[20/6]
40.5+[3.333]
=43.833

Therefore, the mode of the given data of the weight of the students of Class 8B is 43.833 kilograms.

(There is no need to round it up since this is a continuous data.)

# data[].attributes.body
Therefore the mode of the given data (weight of 50 students of class 8B) is 43.83 kg.

# data[].attributes.body
Formula : lbmo + [d1/d1=d2] i

Maximum frequency is 14.
class corresponding to this frequency is 41-45
41 - 0.5 = 40.5
Lower boundary of the modal class / lbmo = 40.5

41-45 = 4 (modal class)
4+1= 5
class interval / i = 5

The maximum frequency is 14
14-10 (lower class)
d1= 4

The maximum frequency is 14
14-2 (upper class)
d2=2

Equation:
40.5 + [4/4+2] 5
40.5 + [4/6] 5
40.5 + [20/6]
40.5 + [3.333]
=  43.833
Therefore, the mode of the given data of the weight of the 50 students of class 8b is 43.833 kg.

(no need to round off since we are talking about the weight of the students which is a continuous data.)

# data[].attributes.body
Therefore, the mode of the given data of the weight of the 50 students of class 8B is 43.833 kilograms.