# data[].attributes.body
-To find LCM you skip count to the lowest common number
-To find GCF you ex: 15: 1,3,5,15

# data[].attributes.body
For LCM first you should skip count then you should find the less common multiple and count how many times it takes you to get their then what ever you do to the bottom you do to the top so you would times the top by the same

# data[].attributes.body
List all the factors and put the greatest factor and put what I got on the bottom so I basically only need to list all the factors

# data[].attributes.headline
I would find the lcm by listing all the factors of the 2 numbers and find the greatest common factor by listing the easiest one and for lcm find 5e one you wouldn’t find automatically 

# data[].attributes.subject
I would find the lcm by listing all the factors of the 2 numbers and find the greatest common factor by listing the easiest one and for lcm find 5e one you wouldn’t find automatically 

# data[].attributes.body
Skip Count  the two numbers until you find 1 number that is the same

# data[].attributes.body
Skip count Itill you find it

# data[].attributes.body
I would skip count foe LCM and list down all the fractions for GCF

# data[].attributes.body
LCMs & GCMs skip count to the bottom number and times for top number

# data[].attributes.body
Skip count until you find the common factor.

# data[].attributes.body
Skip count until u find a common factor.?

# data[].attributes.body
I would skip count to find the common multiple to see if they have a big number in common factors

# data[].attributes.body
Skip count the two numbers until you find something that both numbers have in common.

# data[].attributes.body
To find the LCM you would skip count by the number until they match. For the GCFS I would count all the factors.

# data[].attributes.body
Fractors: LCMS skip count

# data[].attributes.body
For LCM First you would skip count for both numbers then find the

# data[].attributes.body
Skip count then find the answer Jayde

# data[].attributes.body
Multiply the 2 numbers until you get the first same number for both the numbers. (Example).        3: 3, 6, 12, 15
4: 4, 8, 12

# data[].attributes.body
For LCMs I would skip count and for GCFs I would find all of the factors

# data[].attributes.body
Skip count until you find the same number for both of them

# data[].attributes.body
Skip count for lcm and write down all factors on gcf.

# data[].attributes.body
How would you find the least common multiple for any two numbers? How would you find the greatest common factor for any two numbers?

Ms. McGee