# data[].attributes.body
I am Fantastic!

# data[].attributes.body
x^2 +X-11x-11=0
(x+1) (x-11) = 0
x=11 x=-1

# data[].attributes.body
x+11,-1

# data[].attributes.body
x-10x=11

Move the constant to the left

2 x-10x-11-0

Rewrite the expression

2 x +X-11x-11=0

Factor the expressions

x (x+1)-11(x + 1) = 0

Factor the expression

(x+1)x(x-11) = 0

Separate into possible cases

x+1=0

x-11-0

Solve the equations

X = -1

X = 11

# data[].attributes.body
1) A
Divide all of it by 2=
x^2+5.5x+7.5=0
the divide again by 2 but the middle term only

# data[].attributes.body
1. A

# data[].attributes.body
1/A

2 / X + 1 = plus/minus 5

X=54

x=-5-1

x = - 6

3x * (x + 2) = 70

=3x² +6× = 72 x ^ 2 + 2x = 24 (x + 1) ^ 2 = 25

Final answer 4

# data[].attributes.body
15)Let the number of $1 decreases be n
cost per phone = 75 - n
number sold = 500 + 20n

revenue = (500 + 20n)(75-n)
= 37500 + 1000n - 20n^2

d(revenue)/dn = 1000 - 40n = 0 for a max of revenue
40n=1000
n = 25

rev = -20(n^2 - 50n + 625-625)
= -20(n-25)^2 + 12500

max revenue is $12500 when n = 25
that is,
when the phone sells at $50

# data[].attributes.body
(75-x)(500 +2x)
N=25 as a maximum as the profit will be a Total of 12500$

x ^ 2 - 16x + 64 = 25

Factor the expression

(x - 8) ^ 2 = 25

Simplify the equation

x - 8 = plus/minus 5

Separate into possible cases

X-8=-5

X-8=5

Solve the equations

x = 3

x = 13

The equation has 2 solutions

Solution

x_{1} = 3, x_{2} =13