# data[].attributes.custom_properties.wC9Zh8UE
Assuming n>2 or =2, 2n^2 would be the largest. 
Only if n=1,
2+n=3 (Paul's answer)
2n=2*n=2 (Antony's answer)
2n^2=2*n^2=2 (Joseph's answer)
Only in this scenario would Paul be correct, and as we have limited information, there is no way to tell who is truly correct without making assumptions

# data[].attributes.custom_properties.wC9Zh8UE
2n^2 would normally be the largest if n>1, if you assume n as any other number than 1 and smaller. You would end up with 2n^2 most of the time, except 2+n when n<1 same as Pradyun.

# data[].attributes.custom_properties.wC9Zh8UE
Most of the cases except if n is 1 , 2n^1 is the biggest number, if not, i agree with Paul. Thats why i agree with joseph, as 2n^1 is the biggest number for all the possible numbers n could be except 1

# data[].attributes.custom_properties.wC9Zh8UE
1. Assign a number to n. e.g. a nice neat number like 5.
Then, 2n^2 = 100
           2n = 10
And,    2+n = 7
However if n is a negative number like -1, then the reverse would be true. 2n^2 would then equal 
(2 x -1)x(2 x -1) = -4
2n = -2
2+n = 1. So then, Paul would be right
But either way Anthony is always wrong.

# data[].attributes.custom_properties.wC9Zh8UE
Let n be 2 
2 n squared will be 2*n*n which will be 2*2*2 = 8

# data[].attributes.custom_properties.wC9Zh8UE
let n be 2
then,2 * 2 square will be 8 
however 2+2 = 4
2*2 will also equal = 4

# data[].attributes.custom_properties.wC9Zh8UE
Joseph's statement: 2n^2 = 2 * n^2
Paul's statement: 2 + n 
Antony's statement: 2n. 
Let's compare each statement. 
Joseph's statement, 2n^2 is bigger than Antony's statement, 2n, because well, the square in Joseph's statement that is not present in Antony's statement. 
Paul's statement is only bigger in 1 scenario: n = 1. Below is the equations and results of all the statements n = 1.
Joseph's statement: 2*1^2 = 2
Paul's statement: 2 + 1 = 3
Antony's statement: 2 * 1 = 2
As you can see, Paul's statement is the biggest. But when we move onto higher values, Joseph's statement is the biggest. Let n = 2
Joseph's statement: 2 * 2^2 = 8
Paul's statement: 2 + 2 = 4
Antony's statement: 2 * 2 = 4
Here Joseph's statement is the biggest. 
Let's have a few more examples. 
Let n = 3
Let  2n^2 = a
Let 2 + n = b
Let 2n = c 
a = 18
b = 5
c = 6
Let n = 10
a = 200
b = 12
c = 20
In the results above, a(Joseph's Statement) has the greatest value. 
Therefore, except for the scenario where n = 1, I agree with Joseph

# data[].attributes.custom_properties.wC9Zh8UE
Let n be 2
Paul: 2+2 = 4
Antony: 2x2 = 4
Joseph: 2x2 x (2x2)=16

Another example would be 

Let n be 5
Paul: 2+5=7
Antony: 2x5 = 10
Joseph: 2x5 x (2x5) = 100

No matter what, Joseph's equation will always be greater than paul and Antony because his equation is always 2n x 2n resulting in a greater number. However, if Joseph equation is 2 x n to the power of 2, Paul may be greater than him if the n is 1

# data[].attributes.custom_properties.wC9Zh8UE
In all cases where n≥2, 2n^2 will be the largest. for every value n≥2, n^2 grows way faster than n. however, 2+n only grows by 1 every time n grows by 1.  When n grows by one in 2n, 2n only grows by 2. However, for the smallest values of n≥2 in 2n^2, n grows from 2(2^2)=8 to 2(3^2)=18. when n increases by one, 2n^2 increases by 
2(n+1)^2 - 2n^2 
=2(n+1)(n+1) - 2n^2
=2[n^2 + 2(n)(1) + 1] -2n^2
=2(n^2 + 2n +1) -2n^2
= 2n^2 + 4n + 2 - 2n^2
= 4n+2 
for all values n≥2, 4n+2 is greater than 1 and 2.

this proves that 2n^2 is greater than 2+n or 2n for all 
n ≥2

# data[].attributes.custom_properties.wC9Zh8UE
Only in one case: n=1 as 
 n = 1 , 2+n would be 3, 2n would be 2 and 2n^2 would be 2.

however, this is only the case for 1

# data[].attributes.custom_properties.wC9Zh8UE
Because,among adding 2 to n, adding n to n, and putting n to the power of two, putting n to the power of two will always be the bigger result as long as n is 3 and above. although it is not always the largest result for n smaller than 3, it is still the method which will result in the most cases where n to the power of 2 is the largest among the three methods

# data[].attributes.custom_properties.wC9Zh8UE
Assuming you assign n a value, let's say 10 for convenience sake, the result would be as follows:

2+n=12
2n=20
2n^2=200

 2n^2 results in the largest number, and because of this, I agree with Joseph.

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connect your post to me if you agree with me! 

# data[].attributes.attachment_caption
connect your post to me if you agree with me! 

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connect your post to me if you agree with me! 

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You are going to take a stand.

Decide who you agree with - Joseph, Paul or Antony.

In each case, either explain based on concepts or examples to convience others.