# data[].attributes.body
1. t = kb
b = brick
t = time
65 = k(45)
k = 65/45
k = 13/9
t = kb
t = 13/9(500)
t = 722.22...

2. t=k/w
t = time
w = workers
24 = k/5
k = 24(5)
k = 120
t = 120/w
15 = 120/w
15w = 120
w=8

# data[].attributes.body
1.

# data[].attributes.body
2. let w = workers and d = days

w = k / d

k = (24) (5)
k = 120

w = 120/15
w = 8

# data[].attributes.body
2.

# data[].attributes.body
1. Let b be the number of bricks laid
Let t be the time it takes

t = kb
65 = k(45)
65 = 45k
65/45 = 45k/45
13/9 = k

t = 13/9b
t = 13/9(500)
t = 722.2222.....

Therefore, it would take 722.222.... minutes to lay 500 bricks.

2. Let t be the time to plant.
Let w be the number of workers

w = k/t
5 = k/24
5(24) = k/24(24)
120 = k

w = 120/t
w = 120/15
w = 120/15
w = 8

Therefore, they need 8 workers.

# data[].attributes.body
let t = time and b = bricks

t=65
b-45

b = kt
45 = k(65)

1.444 = k

k = 1.444 x 500

k = 722

# data[].attributes.body
1.

# data[].attributes.body
1.) let the minutes be represented as T
and let the bricks be represented as B
t = kb
65 = k(45)
1.444... = k

t = (1.4444)500
t = 722.2 min or 12.036.. hrs
so it would take 700min or 12.036..hrs to place 500 bricks
(edited)

2.) let the days be represented as D and let the amount of workers be represented as W
k=wd
k = (24)(5)
k = 120
if k is equal to 120 then
w=kd
W = (120)(15)
w = 8

# data[].attributes.body
2. w = workers
d = days

equation: w = k / d

Now find constant k

k = (24) (5)
k = 120

lastly:

w = 120 / 15
w = 8 workers

# data[].attributes.body
1. y = xk

Let n= to number of bricks
t= to number of minutes

65 = t, 45 = n

65 = k(45)
65/45 = k(45)/45
13/9 = k

t = (13/9)500
t = 722.2

2. y = k/x

Let d = to number of days
w = to number of workers

5 = w, 24 = d

5 = k/24
24x5 = k
120 = k

w =120/15
w = 8

# data[].attributes.body
1.) 722.22222... minutes
2.) 8 workers

# data[].attributes.body
1. Formula: t = kb
t = time or minutes
b = bricks

65 / 45 = k (45) / 45
1.4 = k

substitute

t = 1.4 (500)
t = 700 mins

# data[].attributes.body
1. Let x be the time it would take to lay bricks
And y be the number of bricks

y = kx
65 = 45k/45
1.4 = k
k = 1.4

x = 500
y = (1.4)x
y = 1.4(500)
y = 700

2. Let x be the number of days
Let y be the number of workers

y = k/x
5 = k/24
k = 120

x = 15
y = 120/15
y = 8

# data[].attributes.body
1.) Given: 45 bricks = 65 min, 500 = ?
y=kx where y is time and x is bricks
~65=k45 / 45
~1.44444444 = k, y = kx
~y = 1.44444444(500)
~y = 722.22 min

2.) Given: 5 workers = 24 days, ? = 15 days
y = k/x, where y is workers and x is days
~5 = k/24
~24 x 5 = k
~120 = k, y = k/x
~y = 120/15, y = 8 workers

# data[].attributes.body
1.

# data[].attributes.body
1. t = k(x), wherein t = time, x = bricks

t = 65
x = 45

t = k(x)
65 = k (45)
65/45 = 45k/45
1.444 = k

t = k(x)
t = 1.444 (500)
t = 722.22

2. x = k/t, wherein t = time, x = workers

t = 24
x = 5

x = k/t
5 = k/24
5(24) = k
120 = k
k = 120

x = k/t
x = 120/15
x = 8

# data[].attributes.body
1.
Let the minutes be represented as t
Let the bricks be represented as b

t = kb

Find the constant k

k = 65/45
k = 1.44444...

1.4444.... = k
(EDITED)
t = kb
t = (1.444444........)(500)
t = 722.222222.....

722.22222..... Minutes

2.
Let the workers be w
Let the days be d

w = k/d

Find the constant k

k = wd
k = (24)(5)
k = 120

w = 120/15
w = 8

8 workers

# data[].attributes.body
1. t=kn
let t= to number of minutes
n= to number of bricks
65=k(45)
65/45=k(45)/45
1.44444=k

t=1.44444(500)
t=722.22

It would take 700 minutes to lay 500 bricks.

2. n=k/t
let t = to number of days
n= to number of workers
5=k/24
24x5=k
120=k

n=120/15
n=8

It will take 8 workers to finish the field in 15 days.

# data[].attributes.body
1. The number of bricks laid varies directly as the amount of time spent. If 45 bricks are laid in 65 minutes, determine the time it would take to lay 500 bricks.

# data[].attributes.body
2. The time to plant a rice field is inversely proportional to the number of people who are working. A large field can be planted by five workers in 24 days. In order to finish the planting sooner, the farmer plans to hire additional workers. How many workers are needed to finish the field in 15 days?