# data[].attributes.body
(a) …diameter…… is the largest chord of a circle.

(b) ……diameter… divides the circle into two equal semi circles.

(c) Rectangle is a …Closed…… curve.

(d) Triangle has …equilateral…… angles and three sides……… .

(e) Only one line can be drawn through …single…… points.

(f) …infinite…… number of lines can pass through a given point.

(g) A closed figure made up entirely of line segments is called a ……polygon… .

(h) A curve which does not cross itself is called a …simple …… curve.

(i) The length of the boundary of a circle is called its …circumference…… .

# data[].attributes.headline
Aayush Vidhate                                                        Side of the square =18 cm∴ Breadth of the rectangle = 31​ ×18 cm=6 cmArea of square =(18×18)cm 2 =324 cm 2 Area of whole figure 384 cm 2 ∴ Area of rectangle =(384−324)cm 2 =60 cm 2 ∴ Length of rectangle ×6 cm=60 cm 2 ∴ Length of rectangle =(60÷6)cm=10 cm.           

# data[].attributes.subject
Aayush Vidhate                                                        Side of the square =18 cm∴ Breadth of the rectangle = 31​ ×18 cm=6 cmArea of square =(18×18)cm 2 =324 cm 2 Area of whole figure 384 cm 2 ∴ Area of rectangle =(384−324)cm 2 =60 cm 2 ∴ Length of rectangle ×6 cm=60 cm 2 ∴ Length of rectangle =(60÷6)cm=10 cm.           

# data[].attributes.headline
Aayush Vidhate                                                                   Length of rectangle =6mBreadth of rectangle carpet =2mArea of 1 rectangle 6m×2m=12m2∴ Area of 4 rectangles=4×12m2=48m2Cost of carpeting 1m2 area of rectangle =Rs. 6Cost of carpeting 48m2 area of                                          rectangle =Rs.6×48=Rs.288Side                             square =(6−2)=4mArea of                               square =4m×4m=16m2Cost of carpeting 1m2 area of                                                                     square =Rs.8Cost of carpeting 16m2 area of square=Rs.(8×16)=Rs.128∴                                                       Total amount paid by Priya=Rs.288+Rs.128=Rs.416                                                                                                                                          

# data[].attributes.subject
Aayush Vidhate                                                                   Length of rectangle =6mBreadth of rectangle carpet =2mArea of 1 rectangle 6m×2m=12m2∴ Area of 4 rectangles=4×12m2=48m2Cost of carpeting 1m2 area of rectangle =Rs. 6Cost of carpeting 48m2 area of                                          rectangle =Rs.6×48=Rs.288Side                             square =(6−2)=4mArea of                               square =4m×4m=16m2Cost of carpeting 1m2 area of                                                                     square =Rs.8Cost of carpeting 16m2 area of square=Rs.(8×16)=Rs.128∴                                                       Total amount paid by Priya=Rs.288+Rs.128=Rs.416                                                                                                                                          

# data[].attributes.body
Aayush Vidhate

# data[].attributes.body
2) Solutions :-

Given :
Perimeter of rectangle = Perimeter of Square = 100 m

Find the side of the square :-

Perimeter of Square = 4 × side
=> 100 m = 4 × Side
=> Side = 100/4 = 25 m

Breadth of rectangle = (side of square - 2) m
= (25 - 2) m = 23 m

Let the length of rectangle be x

Find the length of rectangle :-

Perimeter of rectangle = 2(Length +Breadth)
=> 100 = 2(x + 23)
=> 100/2 = x + 23
=> 50 - 23 = x = 27 m

Find the area of rectangle :-

Area of rectangle = (Length × Breadth) sq. units
= (27 × 23) m²
= 621 m²

Hence,
Length of Rectangle = 27 m
Area of rectangle = 621 m²

# data[].attributes.body
1) The perimeter of a square is 64 cm. Find the length of each side.

# data[].attributes.body
1) Answer: Perimeter of square = 4 × side. side = 64 / 4 = 16

# data[].attributes.body
Perimeter =64cm

Perimeter =4×side

64=4×side

side= 64/4

=16cm