# data[].attributes.body
question 11

200 x 1000 / 2500 = 80mg

# data[].attributes.body
question 11

200

# data[].attributes.body
question 8

245-22 / 245 x 100 = 91%

# data[].attributes.body
((8.5-5.1) x 300)/9 =113mg/L

question 4

# data[].attributes.body
svi= 200/2500 x1000
=80mg/l

# data[].attributes.body
200 x 1000 / 2500 = 80 mL/g

# data[].attributes.body
200ml/L x 1000mg/g ÷ 2500 mg/L = 80 mg

# data[].attributes.body
(245 - 22)/245 x 100 = 91

# data[].attributes.body
245

# data[].attributes.body
Q4) BOD=(initial DO-final DO)xdf

= (8.5-5.1)x (300/9)

= 113mg/l

Q8) (245-22)/245 x100

= 91%

Q11) (200x1000) / 2500

= 80 mL/g

# data[].attributes.body
(245-22mg/L) ×100% ÷ 245mg/L = 91%

# data[].attributes.body
(8.5-5.1)x300

# data[].attributes.body
(8.5-5.1)x300/

# data[].attributes.body
(8.5-5.1)x300

# data[].attributes.body
(8.5 mg/l - 5.1 mg/l) x 300 ml ÷ 9 ml

= 113 mg/l

# data[].attributes.body
(8.5-5.1Lmg/L) x 300ml÷ 9ml = 113 mg/L

# data[].attributes.body
df=300/9

=33.3

BOD = (DO final -DO initial) x df

= (8.5-5.1) x (300/9)

= 113 mg/L

# data[].attributes.body
8.5 - 5.1 x 300/9 = 113 mg/L