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Textbook 1A Exercise 7A (p187)

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Attempt Questions 9 & 10.
Remember to write the working clearly.

Take a clear photo of your worked solution (preferably one post per question) and post it under your index number.

Complete by today.

Estimated duration: 10 min

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t1=1
t2=6=2^3
t3=27=3^3
t4=64=4^3
t5=125=5^3

i) t6=6^3=216
t7=7^3=343
therefore the next two terms of the sequence is 216 and 343

ii) tn=n^3
therefore the expression is n^3

iii) p^3=3375
therefore p=15

10
a) tn=2n^2+1
t1=2(1)^2+1
=3
t2=2(2)^2+1
=9
t3=2(3)^2+1
=19
t4=2(4)^2+1
=33

therefore the first four terms of the sequence are 3,9,19,33

b)
i) tn=2n^2-1
therefore the formula is 2n^2-1

ii) tn=2(38)^2-1
=2887
therefore the 38th term is 2887